Chapter 7: Problem 57
Over what intervals (on the nonnegative side of the number line) is the error function increasing? Concave up?
Short Answer
Expert verified
The error function \(\text{erf}(x)\) is increasing for all \(x \geq 0\) and concave up for \(x < 0\), but not on the non-negative side.
Step by step solution
01
Understanding the Error Function
The error function, denoted as erf(x), is defined as \[ \text{erf}(x) = \frac{2}{\sqrt{\pi}} \int_{0}^{x} e^{-t^2} \, dt \]. It is a sigmoid-shaped function that is widely used in probability, statistics, and partial differential equations.
02
Determine When Error Function is Increasing
A function is increasing on an interval if its derivative is positive. The derivative of the error function is \( \frac{d}{dx} \text{erf}(x) = \frac{2}{\sqrt{\pi}} e^{-x^2} \). This derivative is always positive for all \( x \geq 0 \) since \( e^{-x^2} > 0 \). Therefore, \( \text{erf}(x) \) is increasing for all \( x \geq 0 \).
03
Determine When Error Function is Concave Up
A function is concave up when its second derivative is positive. The second derivative of \( \text{erf}(x) \) is \( \frac{d^2}{dx^2} \text{erf}(x) = -\frac{4x}{\sqrt{\pi}} e^{-x^2} \). This second derivative is positive when \( -4x < 0 \) and thus \( x < 0 \). However, for the non-negative side of the number line, \( x \geq 0 \), the function is never concave up.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Increasing Function
The term "increasing function" refers to a function that consistently rises as you move along the x-axis. For the error function, denoted as \( \text{erf}(x) \), this can be identified by examining its derivative. The derivative of a function helps in understanding how the function behaves as you traverse along the x-axis.
For \( \text{erf}(x) \), the derivative is given by \( \frac{d}{dx} \text{erf}(x) = \frac{2}{\sqrt{\pi}} e^{-x^2} \). Notice that the exponential term \( e^{-x^2} \) is always positive, regardless of the value of \( x \).
For \( \text{erf}(x) \), the derivative is given by \( \frac{d}{dx} \text{erf}(x) = \frac{2}{\sqrt{\pi}} e^{-x^2} \). Notice that the exponential term \( e^{-x^2} \) is always positive, regardless of the value of \( x \).
- If the derivative is positive across an interval, the function is said to be increasing over that interval.
- Since \( \frac{d}{dx} \text{erf}(x) \) is positive for all \( x \geq 0 \), the error function is increasing for all nonnegative values of \( x \).
Derivative of Error Function
The derivative of a function is a powerful concept in calculus, providing insight into its rate of change. For the error function \( \text{erf}(x) \), its derivative is crucial for understanding its behavior.
The derivative of \( \text{erf}(x) \) is given by the expression \( \frac{2}{\sqrt{\pi}} e^{-x^2} \). Here are some essential points about this derivative:
The derivative of \( \text{erf}(x) \) is given by the expression \( \frac{2}{\sqrt{\pi}} e^{-x^2} \). Here are some essential points about this derivative:
- It tells us that the error function's rate of increase is directly tied to the value of \( e^{-x^2} \).
- The exponential component \( e^{-x^2} \) ensures that the derivative is always positive for \( x \geq 0 \).
- This positive derivative signifies that the function is increasing in this range.
- The relatively simple structure of this derivative makes it easier to analyze compared to more complex functions.
Concavity of Error Function
Understanding concavity helps us visualize how a function curves. It’s all about how the function bends. If a function is concave up, it looks like a smile; concave down resembles a frown.
To determine the concavity of a function, we look at its second derivative. For \( \text{erf}(x) \), the second derivative is \( \frac{d^2}{dx^2} \text{erf}(x) = -\frac{4x}{\sqrt{\pi}} e^{-x^2} \). Let's break this down:
To determine the concavity of a function, we look at its second derivative. For \( \text{erf}(x) \), the second derivative is \( \frac{d^2}{dx^2} \text{erf}(x) = -\frac{4x}{\sqrt{\pi}} e^{-x^2} \). Let's break this down:
- The presence of \( -4x \) means the second derivative is influenced by \( x \).
- For \( \text{erf}(x) \), the second derivative is positive if \( -4x < 0 \), which implies \( x < 0 \).
- Since we're examining the non-negative interval \( x \geq 0 \), \( \text{erf}(x) \) is never concave up here.