Chapter 6: Problem 8
In Problems \(7-10,\) plot a slope field for each differential equation. Use the method of separation of variables (Section 3.9) or an integrating factor (Section 6.6) to find a particular solution of the differential equation that satisfies the given initial condition, and plot the particular solution. $$ y^{\prime}=-y ; y(0)=4 $$
Short Answer
Step by step solution
Understand the Problem
Plot the Slope Field
Solve the Differential Equation
Apply Initial Condition
Plot the Particular Solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope Field
- We draw small line segments at various points in the coordinate plane.
- Each line segment has a slope equal to \( -y \) for the corresponding \( y \) value of that point.
Separation of Variables
- Rearrange the equation to \( \frac{dy}{y} = -dx \).
- Integrate both sides separately. The left side becomes \( \int \frac{dy}{y} = \ln |y| \), and the right becomes \(-\int dx = -x + C \).
Initial Condition
- The solution curve must intersect the \( y \)-axis at \( y = 4 \) when \( x = 0 \).
- This single point determines the constant \( C \) in our general solution \( y = Ce^{-x} \).
Particular Solution
- This solution uniquely follows the path through the slope field dictated by \( y' = -y \).
- It passes through \( (0, 4) \), which aligns with the given initial condition.
- Representing a real scenario, it illustrates how one particular path fits the broader family of solutions the equation describes, making it unique.