/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Use the Second Fundamental Theor... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the Second Fundamental Theorem of Calculus to evaluate each definite integral. $$ \int_{1}^{2}\left(4 x^{3}+7\right) d x $$

Short Answer

Expert verified
The value of the definite integral is 22.

Step by step solution

01

Identify the Function to Integrate

The function inside the integral is \( f(x) = 4x^3 + 7 \). We'll use this function to find the antiderivative.
02

Find the Antiderivative

To apply the Second Fundamental Theorem of Calculus, we need to find the antiderivative of \( f(x) \). The power rule gives us \( \int 4x^3 \, dx = x^4 \) and \( \int 7 \, dx = 7x \). Thus, the antiderivative is \( F(x) = x^4 + 7x + C \), where \( C \) is the constant of integration. However, for definite integrals, we don't need to consider \( C \).
03

Apply the Second Fundamental Theorem of Calculus

The Second Fundamental Theorem of Calculus states that if \( F(x) \) is the antiderivative of \( f(x) \), then \( \int_{a}^{b} f(x) \, dx = F(b) - F(a) \). In this case, \( F(x) = x^4 + 7x \).
04

Evaluate the Antiderivative at the Upper Limit

Substitute \( x = 2 \) into \( F(x) \):\[F(2) = (2)^4 + 7(2) = 16 + 14 = 30.\]
05

Evaluate the Antiderivative at the Lower Limit

Substitute \( x = 1 \) into \( F(x) \):\[F(1) = (1)^4 + 7(1) = 1 + 7 = 8.\]
06

Subtract to Find the Definite Integral

Subtract the result from Step 5 from the result from Step 4 to find the value of the definite integral:\[F(2) - F(1) = 30 - 8 = 22.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integral
A definite integral is a way to calculate the area under a curve from one point to another on the x-axis. In this exercise, we're looking at the definite integral \( \int_{1}^{2} (4x^3 + 7) \, dx \). This tells us that we're interested in finding the area under the curve of the function \( 4x^3 + 7 \) between \( x = 1 \) and \( x = 2 \).Unlike indefinite integrals, which give a family of functions with a constant \( C \), definite integrals provide a specific numerical value. This is because the limits of integration—lower limit \( a \) and upper limit \( b \)—are specified, making it possible to use the Second Fundamental Theorem of Calculus to directly find the difference \( F(b) - F(a) \). This approach helps in evaluating the precise area associated with the function over the specified interval. Definite integrals are essential in real-world applications, such as calculating distances, areas, and in physics for finding quantities like work and energy.
Antiderivative
An antiderivative is a function whose derivative gives back to the original function. In simpler terms, it's the reverse process of differentiation. In this exercise, we need to find the antiderivative of \( f(x) = 4x^3 + 7 \).To find the antiderivative of polynomial functions like \( 4x^3 \) and constants like \( 7 \), we add one to the power of \( x \) and then divide by the new power for each term:
  • For \( 4x^3 \), the antiderivative is \( \frac{4}{4}x^4 = x^4 \).
  • For \( 7 \), the antiderivative is simply \( 7x \) because the integral of a constant \( c \) is \( cx \).
Thus, the antiderivative for the given function is \( F(x) = x^4 + 7x \). Notice we omit the constant of integration \( C \) because it's irrelevant for definite integrals, as it cancels out when evaluating \( F(b) - F(a) \).
Power Rule
The power rule is a fundamental technique used to find the antiderivative of terms where the variable is raised to a power. It simplifies the process of integration, especially for polynomial expressions. The rule states that for any function \( x^n \), where \( n eq -1 \), the antiderivative is given by:\[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \]In the context of our exercise, the power rule helps us solve the integral of \( 4x^3 \). If we apply the power rule:
  • Add 1 to the exponent (3 + 1) to get 4.
  • Divide by the new exponent: \( \frac{4}{4}x^4 = x^4 \).
For constant terms like \( 7 \), we remember that the integral simply becomes \( 7x \) since there's no variable to raise to any particular power. The power rule is a handy shortcut instead of manually reversing differentiation, making the integration process much more efficient for students.

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Most popular questions from this chapter

The velocity of an object is $$ v(t)=\left\\{\begin{array}{ll} 5 & \text { if } 0 \leq t \leq 100 \\ 6-t / 100 & \text { if } 100700 \end{array}\right. $$ (a) Assuming that the object is at the origin at time \(0,\) find a formula for its position at time \(t(t \geq 0)\) (b) What is the farthest to the right of the origin that this object ever gets? (c) When, if ever, does the object return to the origin?

Use the given values of \(a\) and \(b\) and express the given limit as a definite integral. $$ \lim _{|P| \rightarrow 0} \sum_{i=1}^{n}\left(\sin \bar{x}_{i}\right)^{2} \Delta x_{i} ; a=0, b=\pi $$

Prove that the function \(f\) defined by \(f(x)=\left\\{\begin{array}{ll}1 & \text { if } x \text { is rational } \\ 0 & \text { if } x \text { is irrational }\end{array}\right.\) is not integrable on [0,1] . Hint: Show that no matter how small the norm of the partition, \(\|P\|,\) the Riemann sum can be made to have value either 0 or 1 .

Find the average value of the function on the given interval. $$ f(x)=\cos x ; \quad[0, \pi] $$

Household electric current can be modeled by the voltage \(V=\hat{V} \sin (120 \pi t+\phi),\) where \(t\) is measured in seconds, \(\hat{V}\) is the maximum value that \(V\) can attain, and \(\phi\) is the phase angle. Such a voltage is usually said to be 60 -cycle, since in 1 second the voltage goes through 60 oscillations. The root-mean-square voltage, usually denoted by \(V_{\mathrm{rms}}\) is defined to be the square root of the average of \(V^{2} .\) Hence $$ V_{\mathrm{rms}}=\sqrt{\int_{\phi}^{1+\phi}(\hat{V} \sin (120 \pi t+\phi))^{2} d t} $$ A good measure of how much heat a given voltage can produce is given by \(V_{\mathrm{rms}}\) (a) Compute the average voltage over 1 second. (b) Compute the average voltage over \(1 / 60\) of a second. (c) Show that \(V_{\mathrm{rms}}=\frac{\hat{V} \sqrt{2}}{2}\) by computing the integral for \(V_{\mathrm{rms}}\) Hint: \(\int \sin ^{2} t d t=-\frac{1}{2} \cos t \sin t+\frac{1}{2} t+C\) (d) If the \(V_{\mathrm{rms}}\) for household current is usually 120 volts, what is the value \(\hat{V}\) in this case?

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