Chapter 3: Problem 33
Sketch the graph of a function \(f\) that
(a) has a continuous first derivative;
(b) is decreasing and concave up for \(x<3\);
(c) has an extremum at (3,1) ;
(d) is increasing and concave up for \(3
Short Answer
Step by step solution
Analyze Conditions for x
Interpret Extremum at (3,1)
Define Behavior for 3
Identify Inflection at (5,4)
Explore 5
Determine Extremum at (6,7)
Consider x>6 Behavior
Sketch the Graph
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First Derivative
Conversely, if \(f'(x) < 0\), the function is decreasing, sliding downwards as you move right. A critical value for the first derivative is when \(f'(x) = 0\). This doesn't necessarily mean the function stops; instead, it implies a possible change in direction, often at points of extremum like a peak (maximum) or a trough (minimum).
- A positive first derivative indicates an upward trend.
- A negative first derivative points to a downward trend.
- Zero first derivative implies a potential extremum.
Extremum
In our specific case, at the point \((3,1)\), the function has a local minimum. Before \(x = 3\), the function decreases, and after \(x = 3\), it begins to increase. Therefore, \(f'(3) = 0\), but more importantly, this forms a U-shape, signaling the lowest point of the curve locally.
However, not all zeros of the first derivative are extrema. Further tests or analyzing the surrounding points help confirm whether it's a maximum, minimum, or neither.
Inflection Point
For instance, at \((5,4)\), our function's second derivative is zero, \(f''(5) = 0\), marking an inflection point. Before this point, the function is concave up; after, it's concave down. This shift means the graph changes from bending upwards like a bowl to bending downwards like a hill.
- Inflection points do not necessarily occur at extrema.
- There must be a change in the sign of \(f''(x)\).
- These points indicate a significant feature in graph behavior.
Concavity
In the problem, we see different sections of concavity. For \(x < 3\) and \(3 < x < 5\), the function is concave up—think of a bowl that could hold water. When \(5 < x < 6\) and \(x > 6\), it's concave down, like an overturned bowl spilling water.
- Concave up: \(f''(x) > 0\) (bends upwards)
- Concave down: \(f''(x) < 0\) (bends downwards)
- Change in concavity is a sign of an inflection point