Chapter 3: Problem 18
Find the general antiderivative \(F(x)+C\) for each of the following. $$ f(x)=\frac{x^{6}-x}{x^{3}} $$
Short Answer
Expert verified
\( F(x) = \frac{x^{4}}{4} - \frac{x^{3}}{3} + C \)
Step by step solution
01
Simplify the Function
Start by simplifying the given function \( f(x) = \frac{x^6 - x}{x^3} \). You can do this by dividing each term in the numerator by the denominator. This gives: \[ f(x) = x^3 - x^{2}. \] This is a simpler form of the function with which it's easier to work.
02
Find the Antiderivative
The general antiderivative of a function \( f(x) \) is a function \( F(x) \) such that \( F'(x) = f(x) \). Here, integrate each term of \( f(x) = x^3 - x^{2} \):- For \( x^3 \), the antiderivative is \( \frac{x^{4}}{4} \). - For \(-x^2\), the antiderivative is \(-\frac{x^{3}}{3} \).So, the antiderivative of \( f(x) \) is \[ F(x) = \frac{x^{4}}{4} - \frac{x^{3}}{3}. \]
03
Add the Constant of Integration
Remember to include the constant of integration \( C \) for the general antiderivative, as integration yields a family of functions. Thus, the general antiderivative is: \[ F(x) = \frac{x^{4}}{4} - \frac{x^{3}}{3} + C. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Simplifying Algebraic Expressions
Simplifying algebraic expressions is about making a math problem easier to solve by reducing it to a simpler form. When faced with a complex rational expression like \( f(x) = \frac{x^6 - x}{x^3} \), the first step is to simplify by dividing each term in the numerator by the denominator.
In this example, you divide \( x^6 \) and \( -x \) individually by \( x^3 \). This gives \( x^3 - x^2 \). Why do we do this? It's like cleaning a room before starting a project. A more straightforward expression makes it easier to perform operations like finding the antiderivative later.
Things to remember when simplifying algebra:
In this example, you divide \( x^6 \) and \( -x \) individually by \( x^3 \). This gives \( x^3 - x^2 \). Why do we do this? It's like cleaning a room before starting a project. A more straightforward expression makes it easier to perform operations like finding the antiderivative later.
Things to remember when simplifying algebra:
- Divide each term separately.
- Watch out for common denominators or factors.
- Reduce fractions when possible.
Integration Techniques
Integration is somewhat the opposite of differentiation. It's all about finding the antiderivative. In this exercise, we started with the simplified function \( f(x) = x^3 - x^2 \). To find the antiderivative, you need to integrate each term.
For \( x^3 \), the power rule of integration says to increase the exponent by one and divide by the new exponent, resulting in \( \frac{x^4}{4} \). The same technique applies to \(-x^2\), leading to \(-\frac{x^3}{3} \).
Key integration techniques include:
For \( x^3 \), the power rule of integration says to increase the exponent by one and divide by the new exponent, resulting in \( \frac{x^4}{4} \). The same technique applies to \(-x^2\), leading to \(-\frac{x^3}{3} \).
Key integration techniques include:
- Power Rule: For \( x^n \), the antiderivative is \( \frac{x^{n+1}}{n+1} \) (for \( n eq -1 \)).
- Decomposing complex expressions into simpler parts that you can integrate separately.
- Verifying your result by differentiating it to see if you get back the original function.
Constant of Integration
In calculus, after integrating a function, you get what's called an antiderivative. But there is a twist: integration doesn’t just give one answer. There are infinitely many answers!
When you take the derivative of a constant, it vanishes, so when you integrate, any number added to the solution will still have the original function as its derivative. That's why we add a constant of integration \( C \) at the end.
This results in a family of functions rather than a single function. For example, \( F(x) = \frac{x^4}{4} - \frac{x^3}{3} + C \) represents all possible antiderivatives of \( f(x) = x^3 - x^2 \).
The constant of integration \( C \) is crucial to:
When you take the derivative of a constant, it vanishes, so when you integrate, any number added to the solution will still have the original function as its derivative. That's why we add a constant of integration \( C \) at the end.
This results in a family of functions rather than a single function. For example, \( F(x) = \frac{x^4}{4} - \frac{x^3}{3} + C \) represents all possible antiderivatives of \( f(x) = x^3 - x^2 \).
The constant of integration \( C \) is crucial to:
- Represent the most general form of the solution.
- Provide flexibility for solving real-world problems where certain conditions are given.
- Ensure completeness, acknowledging the infinite number of antiderivatives possible.