Chapter 2: Problem 7
Find \(D_{x} y .\) \(y=\frac{1}{(x+3)^{5}}\)
Short Answer
Expert verified
\(D_x y = \frac{-5}{(x+3)^6}\)
Step by step solution
01
Rewrite the Function
We begin by rewriting the function in a form that is easier to differentiate. The original function given is \( y = \frac{1}{(x+3)^5} \). This can be rewritten using exponents as \( y = (x+3)^{-5} \).
02
Differentiate Using the Power Rule
Next, we apply the power rule to differentiate the function \( y = (x+3)^{-5} \). The power rule states \( \frac{d}{dx}[x^n] = nx^{n-1} \). Applying this to our function, we get:\[D_x y = -5(x+3)^{-5-1} = -5(x+3)^{-6}.\]
03
Simplify the Expression
Finally, we simplify the derivative expression. Converting \((x+3)^{-6}\) back to fractional form, we obtain:\[D_x y = \frac{-5}{(x+3)^6}.\] This is the final expression for the derivative.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
The Power Rule is a basic, yet powerful, tool in calculus. It provides a straightforward method for differentiating functions of the form \( x^n \), where \( n \) is any real number, including integers and fractions. The rule states that:\[\frac{d}{dx}[x^n] = nx^{n-1}\]This means you multiply the original exponent \( n \) by the coefficient of \( x \), then subtract 1 from the exponent.Let's say you have a function \( f(x) = x^3 \).- According to the Power Rule, the derivative is \( f'(x) = 3x^{3-1} = 3x^2 \).In our exercise, we applied the Power Rule to a function expressed as \((x+3)^{-5}\). The exponent was \(-5\), so following the rule:- The derivative became \(-5(x+3)^{-6}\), as we subtracted 1 from the original exponent.The Power Rule is particularly useful because it simplifies the process of taking derivatives, making it quicker and more intuitive.
Exponents
Exponents are a way of expressing repeated multiplication of a number by itself. They are essential in calculus, especially when differentiating functions with powers. An expression \( a^b \) tells you to multiply \( a \) by itself \( b \) times.Here are some important points about exponents:
- If the exponent is positive, such as \( x^3 \), it means \( x \times x \times x \).
- If the exponent is negative, such as \( x^{-3} \), it represents \( 1/x^3 \), or the reciprocal of \( x^3 \).
- A fraction as an exponent, like \( x^{1/2} \), is equivalent to taking the square root of \( x \).
Fractional Functions
Fractional functions can initially seem complex due to their format of having polynomials in a numerator and/or denominator. They can involve any rational exponent, making differentiation a bit tricky without the right approach.When faced with fractional functions like \( \frac{1}{(x+3)^5} \), a helpful strategy is to rewrite them as a function with a negative exponent. This transforms the expression into a format that's easier to differentiate using the Power Rule.Here's a step-by-step look at our exercise:
- Initially, we had \( y = \frac{1}{(x+3)^5} \).
- This can be rewritten as \( y = (x+3)^{-5} \), changing it to a negative exponent.
- Using the Power Rule, the differentiation becomes manageable, allowing for simplification back to a fractional form: \( \frac{-5}{(x+3)^6} \).