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Chapter 2: Problem 3

Find \(D_{x} y\) using the rules of this section. $$y=\pi x$$

Short Answer

Expert verified
The derivative \(D_{x}y\) is \(\pi\).

Step by step solution

01

Identify the Function

The function given is a linear function: \ \(y = \pi x\). This implies that \(y\) is a function of \(x\) where \(\pi\) is a constant multiplier in front of \(x\).
02

Recall the Derivative Rule for a Constant Multiplier

The derivative of a function where a constant multiplies a variable is simply the constant itself multiplied by the derivative of the variable. In our case, the derivative \(D_{x}[\pi x]\) is calculated by multiplying \(\pi\) with the derivative of \(x\).
03

Differentiate the Variable

The derivative of \(x\) with respect to itself (\(x\)) is 1. Therefore, \(D_{x}[x] = 1\).
04

Apply the Derivative Rule

Now, apply the rule: \(D_{x}[\pi x] = \pi \cdot D_{x}[x] = \pi \cdot 1 = \pi\).
05

Conclude the Solution

Thus, the derivative of \(y = \pi x\) with respect to \(x\) is \(\pi\), so \(D_{x}y = \pi\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative of a constant multiplier
When you have a function where a constant multiplies a variable, it鈥檚 important to know how to find its derivative. This concept is crucial in calculus.
A constant multiplier is simply a fixed number that is multiplied by a variable. For example, in the expression \(y = \pi x\), \(\pi\) is a constant multiplier.
The rule we use is straightforward: the derivative of a function with a constant multiplier is the constant multiplied by the derivative of the variable.
  • In the formula \(D_{x}[c \, f(x)] = c \, D_{x}[f(x)]\), \(c\) represents the constant.
  • For \(y = \pi x\), applying this rule means \(D_{x}[\pi x] = \pi \cdot D_{x}[x]\).
  • Since \(D_{x}[x] = 1\), we conclude \(D_{x}[\pi x] = \pi \cdot 1 = \pi\).
Understanding this rule helps simplify problems when dealing with linear equations in calculus.
Linear function
A linear function is a type of equation where each term is either a constant or the product of a constant and a single variable. Linear equations have a special importance because they describe straight lines on a graph.
In mathematical terms, a linear function has the form \(y = mx + b\), where \(m\) and \(b\) are constants. If there is no \(b\), the function is directly proportional, similar to our expression \(y = \pi x\).
Key characteristics of linear functions include:
  • The graph of a linear function is a straight line.
  • The slope of this line is represented by the coefficient of \(x\) (in this case, \(\pi\)).
  • The function's derivative is constant and equals the slope.
These functions are easier to differentiate because their rate of change is constant.
Calculus
Calculus is a branch of mathematics focused on studying changes. Differentiation and integration are two primary operations in calculus, each serving specific purposes.
Differentiation involves finding the rate at which a quantity changes. For example, by deriving \(y = \pi x\), we determine how \(y\) changes as \(x\) changes.
  • The concept of a derivative allows us to understand functions' behavior, like finding the slope of a curve or analyzing motion.
  • The derivative of a function gives the slope of the tangent line to the function's graph at any point.
Applying calculus concepts, like differentiation, helps solve real-world problems such as optimizing functions or predicting trends in data. It lays the groundwork for advanced mathematical study and various applications in science and engineering.

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Most popular questions from this chapter

Find all points on the graph of \(y=9 \sin x \cos x\) where the tangent line is horizontal.

Find the slopes of the tangent lines to the curve \(y=x^{2}-1\) at the points where \(x=-2,-1,0,1,2\) (see Example 2 ).

Find the slopes of the tangent lines to the curve \(y=x^{3}-3 x\) at the points where \(x=-2,-1,0,1,2\)

A wire of length 8 centimeters is such that the mass between its left end and a point \(x\) centimeters to the right is \(x^{3}\) grams (Figure 12). (a) What is the average density of the middle 2 -centimeter segment of this wire? Note: Average density equals mass/length. (b) What is the actual density at the point 3 centimeters from the left end?

Use \(f^{\prime}(x)=\lim _{h \rightarrow 0}[f(x+h)-f(x)] / h\) to find the derivative at \(x\). \(g(x)=\sqrt{3 x}\)
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