Chapter 2: Problem 2
Use the definition $$f^{\prime}(c)=\lim _{h \rightarrow 0} \frac{f(c+h)-f(c)}{h}$$ to find the indicated derivative. \(f^{\prime}(2)\) if \(f(t)=(2 t)^{2}\)
Short Answer
Expert verified
The derivative \( f'(2) \) is 16.
Step by step solution
01
Understanding the Problem
We need to find the derivative of the function \( f(t) = (2t)^2 \) at \( t = 2 \). The derivative, \( f'(t) \), is calculated using the limit definition: \( f'(t) = \lim_{h \to 0} \frac{f(t+h) - f(t)}{h} \). We will apply this definition to find \( f'(2) \).
02
Substituting into the Function
Start by substituting \( t + h \) into the function \( f(t) = (2t)^2 \). This gives: \[ f(t + h) = (2(t + h))^2 = (2t + 2h)^2 \].
03
Expanding \( f(t+h) \)
Expand the expression \((2t + 2h)^2\):\[ (2t + 2h)^2 = (2t)^2 + 2(2t)(2h) + (2h)^2 = 4t^2 + 8th + 4h^2 \].
04
Compute the Difference \( f(t+h) - f(t) \)
Substitute \( f(t) = (2t)^2 = 4t^2 \) and \( f(t+h) \) from step 3 into the difference:\[ f(t+h) - f(t) = (4t^2 + 8th + 4h^2) - 4t^2 = 8th + 4h^2 \].
05
Form the Difference Quotient
Set up the difference quotient: \[ \frac{f(t+h) - f(t)}{h} = \frac{8th + 4h^2}{h} = 8t + 4h \], by dividing each term by \( h \).
06
Taking the Limit as \( h \) Approaches Zero
Take the limit of the difference quotient as \( h \to 0 \):\[ \lim_{h \to 0} (8t + 4h) = 8t \], because \( 4h \) approaches zero as \( h \to 0 \).
07
Substitute \( t = 2 \) to Find \( f'(2) \)
Substitute \( t = 2 \) into the result from step 6 to find the derivative at this point:\[ f'(2) = 8 \times 2 = 16 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit Definition of Derivative
The limit definition of a derivative is a fundamental concept in calculus. It provides a precise way to calculate the rate of change, or slope, of a function at a specific point. The official definition is expressed as:\[ f'(c) = \lim_{h \to 0} \frac{f(c+h) - f(c)}{h}, \]where \( f'(c) \) represents the derivative of the function \( f \) at the point \( c \). This equation captures how the function \( f \) changes as \( h \), a small increment, approaches zero.
Understanding this definition involves several parts:
Understanding this definition involves several parts:
- \( f(c+h) \): This term represents the function value at a small distance \( h \) away from \( c \).
- \( f(c) \): This represents the function value at the exact point \( c \).
- \( \frac{f(c+h) - f(c)}{h} \): This quotient calculates the average rate of change over the interval from \( c \) to \( c+h \).
Polynomial Derivatives
Polynomials are common mathematical expressions that are relatively straightforward to differentiate due to their consistent structure. A polynomial function is represented as a sum of terms, each of the form \( a_n t^n \) where \( a_n \) is a coefficient and \( n \) is a non-negative integer.
When finding derivatives of polynomial functions, each term is differentiated using the power rule. The power rule states that the derivative of \( t^n \) is \( n \cdot t^{n-1} \). For example, the derivative of \( (2t)^2 \) can be expanded to \( 4t^2 \) so that we can apply the power rule effectively.
To differentiate a complete polynomial, perform the power rule for each term:
When finding derivatives of polynomial functions, each term is differentiated using the power rule. The power rule states that the derivative of \( t^n \) is \( n \cdot t^{n-1} \). For example, the derivative of \( (2t)^2 \) can be expanded to \( 4t^2 \) so that we can apply the power rule effectively.
To differentiate a complete polynomial, perform the power rule for each term:
- Derive each term separately.
- Apply any necessary constants or coefficients.
- Sum the derivatives of the individual terms to find the derivative of the entire polynomial.
Calculating Derivatives at a Point
When solving problems, knowing how to calculate a derivative at a specific point is important, especially in understanding the behavior of functions in calculus. Here’s how to approach it:
- Understand the Function: First, identify the function you are interested in. For this example, it's \( f(t) = (2t)^2 \).
- Use the Limit Definition: As seen previously, start with the limit definition of a derivative. This provides a detailed path to finding \( f'(t) \) by directly considering the function's behavior as \( h \) approaches zero.
- Simplify Terms: Simplify any expressions before taking the limit, such as the "difference quotient" \( \frac{f(t+h)-f(t)}{h} \).
- Substitute the Point: Once the general derivative \( f'(t) \) is found, substitute the specific value of \( t \) to find the derivative at that point.