Chapter 2: Problem 13
Use \(f^{\prime}(x)=\lim _{h \rightarrow 0}[f(x+h)-f(x)] / h\) to find the derivative at \(x\). \(h(x)=\frac{2}{x}\)
Short Answer
Expert verified
The derivative of \( h(x) = \frac{2}{x} \) is \( h'(x) = \frac{-2}{x^2} \).
Step by step solution
01
Write the Difference Quotient
We begin by writing the difference quotient for the function \( h(x) = \frac{2}{x} \). This will help us in finding the derivative: \[ \frac{h(x+h) - h(x)}{h} = \frac{\frac{2}{x+h} - \frac{2}{x}}{h} \]
02
Simplify the Difference
Combine the fractions in the numerator of the difference quotient by getting a common denominator:\[\frac{2}{x+h} - \frac{2}{x} = \frac{2x - 2(x+h)}{x(x+h)} = \frac{2x - 2x - 2h}{x(x+h)} = \frac{-2h}{x(x+h)}\]
03
Insert Simplified Difference into the Quotient and Cancel Terms
Replace the numerator in the difference quotient with the simplified expression from Step 2 and cancel \( h \):\[\frac{\frac{-2h}{x(x+h)}}{h} = \frac{-2h}{hx(x+h)} = \frac{-2}{x(x+h)}\]
04
Take the Limit as \(h\) Approaches Zero
Take the limit of the difference quotient as \( h \) approaches 0:\[\lim_{h \to 0} \frac{-2}{x(x+h)} = \frac{-2}{x^2}\]
05
State the Derivative
After evaluating the limit, we find the derivative of the function \( h(x) = \frac{2}{x} \): \[ h'(x) = \frac{-2}{x^2} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference Quotient
The difference quotient is a crucial concept when it comes to finding derivatives in calculus. It helps in determining the rate at which a function changes. The generic formula for a difference quotient of a function \( f(x) \) is:
For the function \( h(x) = \frac{2}{x} \), the difference quotient would look like:
- \( \frac{f(x+h) - f(x)}{h} \)
For the function \( h(x) = \frac{2}{x} \), the difference quotient would look like:
- \( \frac{\frac{2}{x+h} - \frac{2}{x}}{h} \)
Rational Functions
Rational functions are expressions formed by the ratio of two polynomials. A basic understanding of their structure helps in manipulating expressions for calculus tasks. In our case, \( h(x) = \frac{2}{x} \) is a simple rational function. The key characteristics of rational functions include:
- Being defined as \( \frac{P(x)}{Q(x)} \) where both \( P(x) \) and \( Q(x) \) are polynomials.
- The domain excludes values where \( Q(x) = 0 \) since division by zero is undefined.
- They often require the application of algebraic methods for simplification, especially when working with derivatives.
Limit Process
The limit process is the heart of calculus, providing a method to assess the behavior of functions as they approach specific points. When computing the derivative, we take the limit of the difference quotient as \( h \) becomes infinitesimally small, specifically:
Thus, the limit process is not just a mathematical tool, but a core underpinning of calculus that gives precise insight into function dynamics.
- \( \lim_{h \to 0} \left( \frac{-2}{x(x+h)} \right) \)
- \( \lim_{h \to 0} \frac{-2}{x(x+h)} = \frac{-2}{x^2} \)
Thus, the limit process is not just a mathematical tool, but a core underpinning of calculus that gives precise insight into function dynamics.