Chapter 14: Problem 6
Use Stokes's Theorem to calculate $$\iint_{S}(\operatorname{curl} \mathbf{F}) \cdot \mathbf{n} d S$$ \(\mathbf{F}=(z-y) \mathbf{i}+(z+x) \mathbf{j}-(x+y) \mathbf{k} ; S\) is the part of the paraboloid \(z=1-x^{2}-y^{2}\) above the \(x y\) -plane and \(\mathbf{n}\) is the upward normal.
Short Answer
Expert verified
The integral over the surface \( S \) is \( 2\pi \).
Step by step solution
01
Understand Stokes's Theorem
Stokes's Theorem states that \( \iint_{S}(\operatorname{curl} \mathbf{F}) \cdot \mathbf{n} \, dS = \oint_{C} \mathbf{F} \cdot \mathbf{dr} \), where \( C \) is the closed curve bounding the surface \( S \) and oriented counterclockwise. First, we verify that \( S \) is the surface of the paraboloid \( z = 1 - x^2 - y^2 \). The boundary \( C \) is the circle where \( z = 0 \), hence \( x^2 + y^2 = 1 \).
02
Compute the Curl of \( \mathbf{F} \)
The vector field is \( \mathbf{F} = (z-y) \mathbf{i} + (z+x) \mathbf{j} - (x+y) \mathbf{k} \). To find \( \operatorname{curl} \mathbf{F} \), we compute\[ abla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \ z-y & z+x & -(x+y) \end{vmatrix}. \]Evaluating the determinant, we get\[ \operatorname{curl} \mathbf{F} = (1 + 1) \mathbf{i} + (-1 - 1) \mathbf{j} + (-1 + 1) \mathbf{k} = 2 \mathbf{i} - 2 \mathbf{j}. \]
03
Parametrize the Boundary Curve
The circle \( C \) is on the plane \( z = 0 \) with radius 1. A standard parametrization of this circle is \( \mathbf{r}(t) = \cos(t) \mathbf{i} + \sin(t) \mathbf{j} \) for \( t \in [0, 2\pi] \).
04
Evaluate the Line Integral
The line integral is given by \( \oint_{C} \mathbf{F} \cdot \mathbf{dr} \). First, compute \( \mathbf{F} \mid_C = (-\sin(t) - \sin(t)) \mathbf{i} + (-\cos(t) + \cos(t)) \mathbf{j} - (\cos(t) + \sin(t)) \mathbf{k} \). Then \( \mathbf{dr} = (-\sin(t) \mathbf{i} + \cos(t) \mathbf{j}) dt \). Integrating, we have \[ \oint_{C} \mathbf{F} \cdot \mathbf{dr} = \int_{0}^{2\pi} [-2\sin(t)(-\sin(t))] \, dt = \int_{0}^{2\pi} 2\sin^2(t) \, dt. \]
05
Solve the Integral
We simplify \( 2\sin^2(t) \) using the identity \( \sin^2(t) = \frac{1 - \cos(2t)}{2} \), so \( 2\sin^2(t) = 1 - \cos(2t) \). Hence, the integral becomes\[ \int_{0}^{2\pi} 1 \cdot dt - \int_{0}^{2\pi} \cos(2t) \, dt. \]The first integral evaluates to \( 2\pi \) and the second to 0 (since the integral of a full period of cosine is 0). Therefore, the result is \( 2\pi \).
06
Conclusion Using Stokes's Theorem
By Stokes's Theorem, \( \iint_{S}(\operatorname{curl} \mathbf{F}) \cdot \mathbf{n} \, dS = \oint_{C} \mathbf{F} \cdot \mathbf{dr} = 2\pi \). Therefore, the integral over the surface \( S \) is \( 2\pi \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curl of a Vector Field
The curl of a vector field is a way to measure the rotation or swirling of the field at a given point. It's a vector operation that acts on a three-dimensional vector field to produce another vector field. The formula for the curl is given by the cross product of the del operator, \( abla \), with a vector field \( \mathbf{F} \). This can be expressed as
- \( \operatorname{curl} \mathbf{F} = abla \times \mathbf{F} \)
- \( 2 \mathbf{i} - 2 \mathbf{j} \)
Line Integrals
A line integral is a fundamental tool used in calculus to integrate functions along a curve. It's a way to sum up values of a function along a path. This can involve scalar functions, measuring total value along a path, or vector fields, measuring the work done by a force.The line integral of a vector field \( \mathbf{F} \) along a curve \( C \) is expressed as
- \( \oint_{C} \mathbf{F} \cdot \mathbf{dr} \)
Surface Integrals
Surface integrals are akin to line integrals but are carried out over a surface rather than a path. They calculate the accumulation of a field over a two-dimensional surface, measuring quantities like fluid flow or electric flux through a surface.The surface integral of a vector field involves the dot product of the field with the normal vector \( \mathbf{n} \) to the surface. In the context of Stokes's Theorem, this becomes:
- \( \iint_{S} (\operatorname{curl} \mathbf{F}) \cdot \mathbf{n} \, dS \)
Parametrization of Curves
Parametrization of curves is a technique to represent a curve by functions of a single parameter, typically \( t \), which varies over an interval. This expresses each point on the curve as a position vector function \( \mathbf{r}(t) \).A simple and effective example is parametrizing a circle of radius 1 by
- \( \mathbf{r}(t) = \cos(t) \mathbf{i} + \sin(t) \mathbf{j} \)