Chapter 13: Problem 7
Evaluate the iterated integrals. $$ \int_{1 / 2}^{1} \int_{0}^{2 x} \cos \left(\pi x^{2}\right) d y d x $$
Short Answer
Expert verified
The iterated integral evaluates to \(-\frac{\sqrt{2}}{2\pi}\).
Step by step solution
01
Understand the Problem
We need to solve the iterated integral \( \int_{1 / 2}^{1} \int_{0}^{2 x} \cos \left(\pi x^{2}\right) d y d x \). This represents an integral over a region where the function is \( \cos(\pi x^2) \), integrated first with respect to \( y \) from 0 to \( 2x \), and then with respect to \( x \) from 1/2 to 1.
02
Evaluate the Inner Integral
The inner integral is \( \int_{0}^{2x} \cos(\pi x^2) \, dy \). Since \( \cos(\pi x^2) \) is constant with respect to \( y \), the integral simplifies to:\[\cos(\pi x^2) \cdot (2x - 0) = 2x \cos(\pi x^2)\]
03
Set Up the Outer Integral
After evaluating the inner integral, we substitute it into the outer integral to get:\[\int_{1/2}^{1} 2x \cos(\pi x^2) \, dx\]
04
Evaluate the Outer Integral
To solve \( \int_{1/2}^{1} 2x \cos(\pi x^2) \, dx \), use the substitution method:Let \( u = \pi x^2 \) so that \( du = 2\pi x \, dx \). Solving for \( x \, dx \) gives \( x \, dx = \frac{du}{2\pi} \).Change the limits of integration: when \( x = 1/2, \, u = \pi (1/2)^2 = \pi/4 \); when \( x = 1, \, u = \pi \).Substitute into the integral:\[\int_{\pi/4}^{\pi} \frac{1}{\pi} \cos(u) \, du\]The integral of \( \cos(u) \) is \( \sin(u) \), so we have:\[\frac{1}{\pi} [\sin(u)]_{\pi/4}^{\pi}\]
05
Compute the Definite Integral
Evaluate \( \frac{1}{\pi} [\sin(u)]_{\pi/4}^{\pi} \):\[\frac{1}{\pi} (\sin(\pi) - \sin(\pi/4)) = \frac{1}{\pi} (0 - \sin(\pi/4)) = -\frac{1}{\pi} \cdot \frac{\sqrt{2}}{2}\]Thus, the result is \(-\frac{\sqrt{2}}{2\pi}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a technique used in calculus to simplify the process of evaluating integrals. It works by replacing a complex expression within the integral with a single variable. This is especially useful when dealing with integrals that are difficult to solve directly.
For instance, when we face an integral like \( \int 2x \cos(\pi x^2) \, dx \), using substitution can make the integral much more manageable. In this specific exercise, we set \( u = \pi x^2 \). This substitution allows us to express the differential \( dx \) in terms of \( du \):
For instance, when we face an integral like \( \int 2x \cos(\pi x^2) \, dx \), using substitution can make the integral much more manageable. In this specific exercise, we set \( u = \pi x^2 \). This substitution allows us to express the differential \( dx \) in terms of \( du \):
- Differentiate \( u \) with respect to \( x \): \( du = 2\pi x \, dx \).
- Solve for \( x \, dx \): \( x \, dx = \frac{du}{2\pi} \).
Definite Integral
A definite integral computes the accumulation of quantities, such as areas under curves, between two bounds or limits. Unlike an indefinite integral, which gives a function, a definite integral results in a specific numerical value.
In this exercise, we are looking at the integral \( \int_{1/2}^{1} 2x \cos(\pi x^2) \, dx \), which is a classic example of a definite integral. Here, the bounds are from \( x = 1/2 \) to \( x = 1 \). During substitution, these bounds are also transformed according to the substitution rule.
When substitution \( u = \pi x^2 \) is applied, the limits of \( u \) change accordingly:
In this exercise, we are looking at the integral \( \int_{1/2}^{1} 2x \cos(\pi x^2) \, dx \), which is a classic example of a definite integral. Here, the bounds are from \( x = 1/2 \) to \( x = 1 \). During substitution, these bounds are also transformed according to the substitution rule.
When substitution \( u = \pi x^2 \) is applied, the limits of \( u \) change accordingly:
- When \( x = 1/2 \), \( u = \pi (1/2)^2 = \pi/4 \).
- When \( x = 1 \), \( u = \pi \).
Cosine Function
The cosine function, denoted as \( \cos(x) \), is a fundamental trigonometric function representing the x-coordinate of a unit circle as a function of an angle \( x \). Its properties include being an even function, periodic with a period of \( 2\pi \), and oscillating between -1 and 1.
In the given exercise, the function of interest is \( \cos(\pi x^2) \). This translates the typical behavior of the cosine function into a more complex argument \( \pi x^2 \), which shifts the timing of the oscillations. Despite this complex appearance, the original properties of the cosine still apply.
Key aspects of the cosine function to remember include:
In the given exercise, the function of interest is \( \cos(\pi x^2) \). This translates the typical behavior of the cosine function into a more complex argument \( \pi x^2 \), which shifts the timing of the oscillations. Despite this complex appearance, the original properties of the cosine still apply.
Key aspects of the cosine function to remember include:
- It is periodic with identical values repeating every \( 2\pi \) units.
- It is even, meaning \( \cos(-x) = \cos(x) \).
- The integral of \( \cos(u) \) over a range can be calculated efficiently since \( \int \cos(u) \, du = \sin(u) \).