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For the transformation \(x=2 u+v, y=v-u\), sketch the \(u\) -curves and \(v\) -curves for the grid \(\\{(u, v):(u=2,3,4,5\) and \(1 \leq v \leq 3)\) or \((v=1,2,3\) and \(2 \leq u \leq 5)\\}\).

Short Answer

Expert verified
Plot the transformation by overlaying the specified lines on the xy-plane.

Step by step solution

01

Understand the Parametric Equations for x and y

The transformation equations given are \(x = 2u + v\) and \(y = v - u\). These equations describe the relationships between \(x, y\) (the Cartesian coordinate system) and \(u, v\) (the parametric coordinate system). We need to plot curves based on constant values of \(u\) and \(v\).
02

Define the u-Curves

For \(u\)-curves, \(u\) is constant. Let's consider different values of \(u\) (\(u = 2, 3, 4, 5\)) while \(v\) varies from 1 to 3. Substitute each constant value of \(u\) into the parametric equations to obtain equations dependent only on \(v\):- For \(u = 2\), \(x = 4 + v\) and \(y = v - 2\).- For \(u = 3\), \(x = 6 + v\) and \(y = v - 3\).- For \(u = 4\), \(x = 8 + v\) and \(y = v - 4\).- For \(u = 5\), \(x = 10 + v\) and \(y = v - 5\).
03

Sketch the u-Curves on the xy-plane

On the xy-plane, each \(u\)-curve will be a straight line. For each value of \(u\), plot the lines:- \(u = 2\): Line starts at \((x, y) = (5, -1)\) and ends at \((x, y) = (7, 1)\).- \(u = 3\): Line starts at \((x, y) = (7, -2)\) and ends at \((x, y) = (9, 0)\).- \(u = 4\): Line starts at \((x, y) = (9, -3)\) and ends at \((x, y) = (11, -1)\).- \(u = 5\): Line starts at \((x, y) = (11, -4)\) and ends at \((x, y) = (13, -2)\).
04

Define the v-Curves

For \(v\)-curves, \(v\) is constant. Let's consider different values of \(v\) (\(v = 1, 2, 3\)) while \(u\) varies from 2 to 5. Substitute each constant value of \(v\) into the parametric equations to get equations dependent only on \(u\):- For \(v = 1\), \(x = 2u + 1\) and \(y = 1 - u\).- For \(v = 2\), \(x = 2u + 2\) and \(y = 2 - u\).- For \(v = 3\), \(x = 2u + 3\) and \(y = 3 - u\).
05

Sketch the v-Curves on the xy-plane

On the xy-plane, each \(v\)-curve will be a straight line. For each value of \(v\), plot the lines:- \(v = 1\): Line climbs from \((5, -1)\) to \((11, -4)\).- \(v = 2\): Line climbs from \((6, 0)\) to \((12, -3)\).- \(v = 3\): Line climbs from \((7, 1)\) to \((13, -2)\).
06

Combine to Complete the Grid

Overlay the \(u\)-curves and \(v\)-curves on the same \(xy\)-plane. These lines will form a grid. Each pair of intersecting lines on the grid represents a unique combination of \(u\) and \(v\) values in the coordinate system, covering defined ranges for \(u\) and \(v\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transformation of Coordinates
In mathematics, a transformation of coordinates involves changing from one coordinate system to another. This process is crucial when dealing with parametric equations, which introduce new parameters that simplify complex equations or enhance their understanding. For instance, in the given problem, we're transforming between the parametric coordinate system defined by \( u \) and \( v \), and the Cartesian coordinate system represented by \( x \) and \( y \).

These transformations are represented by the equations \( x = 2u + v \) and \( y = v - u \). They allow us to express the flawed variables of the parametric system into the more familiar Cartesian form. This can be particularly beneficial in visualizing and analyzing the behavior of the equations.

Key points to remember during a transformation include:
  • Ensure you understand the relations between old and new coordinates.
  • Geo-spatial relationships can change under transformation, so plotting helps.
  • Use transformations appropriately to make complex graphs more manageable.
These transformations help plot coordinate curves straightforwardly, as shown in this exercise.
Sketching Curves
Sketching curves through parametric equations involves translating the abstract representations into clear, visual forms on a graph. For safe sketching, we identify all variables and constants in our equations—like the parameters \( u \) and \( v \) in our problem.

Each curve, based on parametric equations defining either \( x \) or \( y \), simplifies into a straight line on the Cartesian plane when one parameter remains constant.
For instance:
  • \( u \)-curves are drawn by keeping \( u \) fixed and solving for \( x \) and \( y \) in terms of \( v \).
  • \( v \)-curves are drawn by holding \( v \) constant and computing \( x \) and \( y \) using \( u \).
Whether we are at constant \( u \) or \( v \), the resulting straight lines will naturally intersect as per defined parametric bounds, forming a grid-like pattern on the graph.
Steps for effective curve sketching:
  • Substitute constant parameter values into the transformation equations.
  • Calculate and connect \( x \) and \( y \) points for each constant value.
  • Overlay all resulting lines to complete the graph.
These steps demystify parametric curve sketching by providing clear, sequential actions for plotting.
Cartesian Coordinate System
The Cartesian coordinate system forms the foundation for representing equations and functions graphically. It utilizes two perpendicular axes, typically labeled \( x \) and \( y \), to map each point in a plane with a unique pair of numerical values.

This system's structure makes it ideal for converting and visualizing parametric equations. Here, each \( u \)-curve or \( v \)-curve becomes a simple line once plotted on the Cartesian plane.
Importantly:
  • \( x \)-axis runs horizontally, representing the independent variable in many contexts.
  • \( y \)-axis runs vertically, often representing the dependent variable.
  • The origin, where these axes intersect, is the point \((0,0)\).
The Cartesian coordinate system allows for clarity when interpreting complex transformations by converting them into easily digestible straight-line or curved representations.

In solving our exercise, this system enables us to realize visual forms out of parametric descriptions like \( x = 2u + v \) and \( y = v - u \), providing a coherent backdrop for analyzing their behavior in space.

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Most popular questions from this chapter

Sketch the indicated solid. Then find its volume by an iterated integration. Wedge bounded by the coordinate planes and the planes \(x=5\) and \(y+2 z-4=0\)

Sketch the solid \(S .\) Then write an iterated integral for \(\iiint_{S} f(x, y, z) d V\). \(S\) is the tetrahedron with vertices \((0,0,0),(3,2,0),(0,3,0),\) and (0,0,2).

Six surfaces are given below. Without performing any integration, rank the surfaces in order of their surface area from smallest to largest. Hint: There may be some "ties." (a) The paraboloid \(z=x^{2}+y^{2}\) over the region in the first quadrant and inside the circle \(x^{2}+y^{2}=1\) (b) The hyperbolic paraboloid \(z=x^{2}-y^{2}\) over the region in the first quadrant and inside the circle \(x^{2}+y^{2}=1\) (c) The paraboloid \(z=x^{2}+y^{2}\) over the region inside the rectangle with vertices \((0,0),(1,0),(1,1),\) and (0,1) (d) The hyperbolic paraboloid \(z=x^{2}-y^{2}\) over the region inside the rectangle with vertices \((0,0),(1,0),(1,1),\) and (0,1) (e) The paraboloid \(z=x^{2}+y^{2}\) over the region inside the triangle with vertices \((0,0),(1,0),\) and (0,1) (f) The hyperbolic paraboloid \(z=x^{2}-y^{2}\) over the region inside the triangle with vertices \((0,0),(1,0),\) and (0,1)

Use triple iterated integrals to find the indicated quantities. Center of mass of the tetrahedron bounded by the planes \(x+y+z=1, x=0, y=0,\) and \(z=0\) if the density is proportional to the sum of the coordinates of the point

Find the surface area of the given surface. If an integral cannot be evaluated using the Second Fundamental Theorem of Calculus, then use the Parabolic Rule with \(n=10 .\) The paraboloid \(z=x^{2}+y^{2}\) over the region (a) in the first quadrant and inside the circle \(x^{2}+y^{2}=9\) (b) inside the triangle with vertices (0,0),(3,0),(0,3)

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