Chapter 11: Problem 38
Show that the curve determined by \(\mathbf{r}=t \mathbf{i}+t \mathbf{j}+t^{2} \mathbf{k}\) is a parabola, and find the coordinates of its focus.
Short Answer
Expert verified
The curve is a parabola; its focus is at (0, 0, 1/4).
Step by step solution
01
Represent the Curve in a Parametric Form
The given vector function is \( \mathbf{r}=t \mathbf{i}+t \mathbf{j}+t^{2} \mathbf{k} \). This represents the space curve with parametric equations \( x = t \), \( y = t \), and \( z = t^2 \).
02
Express as a Equation in Terms of z
From \( x = t \) and \( y = t \), it follows that \( x = y \). Thus, we can use this relation to express \( t = x \) and replace \( t \) in the equation for \( z \): \( z = t^2 = x^2 \).
03
Recognize the Parabola z = x^2
The equation \( z = x^2 \) is the equation of a parabola in the \( xz \)-plane (with axis of symmetry along the \( z \)-axis and vertex at the origin).
04
Locate the Focus of the Parabola
The standard form of a parabola \( z = x^2 \) is \( 4a(z - h) = (x - k)^2 \). Comparing \( z = x^2 \) with \( z = \frac{1}{4p}(x-h)^2 + k \), the parabola vertex is at the origin (\( h = 0, k = 0 \)), and \( p = \frac{1}{4} \) since \( 4p = 1 \). The focus is at \( (0, 0, p) = (0, 0, \frac{1}{4}) \).
05
Interpret in the 3D Coordinate System
In the 3-dimensional space defined by \( (t, y, z) = (x, x, z) \), this means the vertex is at \( (0, 0, 0) \) and the focus is directly on the \( z \)-axis at \( (0, 0, \frac{1}{4}) \). The curve looks like a parabolic sheet extending along the direction where \( x = y \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Parametric Equations
In mathematics, parametric equations play a crucial role in describing curves in various degrees of dimensionality. Unlike normal equations, parametric equations express the set of coordinates of the points that make up a geometric object, as functions of one or more parameters.
In the given exercise, we have a vector function \( \mathbf{r}=t \mathbf{i}+t \mathbf{j}+t^{2} \mathbf{k} \). This function represents our 3D space curve. Here:
In the given exercise, we have a vector function \( \mathbf{r}=t \mathbf{i}+t \mathbf{j}+t^{2} \mathbf{k} \). This function represents our 3D space curve. Here:
- \( x = t \)
- \( y = t \)
- \( z = t^2 \)
Finding the Focus of a Parabola
The focus of a parabola is a unique point. This point lies on the axis of symmetry and has a property such that every point on the parabola is equidistant from it and a line called the directrix. For the parabola given by \( z = x^2 \), the parabola opens along the z-axis with its vertex at the origin (0, 0, 0).
To find the focus, we adapt the standard form equation of a parabola: \[ z = \frac{1}{4p}(x-h)^2 + k \]. Comparing it to our form \( z = x^2 \), we identify that:
To find the focus, we adapt the standard form equation of a parabola: \[ z = \frac{1}{4p}(x-h)^2 + k \]. Comparing it to our form \( z = x^2 \), we identify that:
- \( h = 0 \)
- \( k = 0 \)
- \( p = \frac{1}{4} \)
Exploring Space Curves
Space curves are fascinating 3D trajectories defined mathematically via vector functions. These curves differ from 2D interpretations by their potential to traverse through three dimensions, showcasing a dance through x, y, and z axes. In our exercise, the vector function \( \mathbf{r}=t \mathbf{i}+t \mathbf{j}+t^{2} \mathbf{k} \) graciously paths out a parabolic trajectory.
Space curves like this one are specified by parametric equations, making them essential in visualizing geometrical paths in fields like physics and engineering. For instance, the path of a projectile under gravity or the form of a metal rod under stress can be represented using space curves. Much like in this example, the understanding of where the path converges or its curvature—dictated by the parabola with a defined focus—adds immense detail to structural analyses and physical interpretations, crafting a vivid understanding of three-dimensional movements.
Space curves like this one are specified by parametric equations, making them essential in visualizing geometrical paths in fields like physics and engineering. For instance, the path of a projectile under gravity or the form of a metal rod under stress can be represented using space curves. Much like in this example, the understanding of where the path converges or its curvature—dictated by the parabola with a defined focus—adds immense detail to structural analyses and physical interpretations, crafting a vivid understanding of three-dimensional movements.