Chapter 11: Problem 22
Let a and b be nonparallel vectors, and let \(\mathbf{c}\) be any nonzero vector. Show that \((\mathbf{a} \times \mathbf{b}) \times \mathbf{c}\) is a vector in the plane of \(\mathbf{a}\) and b.
Short Answer
Expert verified
The vector \((\mathbf{a} \times \mathbf{b}) \times \mathbf{c}\) lies in the plane of \(\mathbf{a}\) and \(\mathbf{b}\).
Step by step solution
01
Understanding Cross Products
The cross product of two vectors, such as \( \mathbf{a} \times \mathbf{b} \), results in a vector perpendicular to both \( \mathbf{a} \) and \( \mathbf{b} \). This vector defines a direction normal to the plane created by \( \mathbf{a} \) and \( \mathbf{b} \).
02
Applying Vector Triple Product Identity
The vector identity for the triple product \( (\mathbf{a} \times \mathbf{b}) \times \mathbf{c} \) is given by the formula: \[(\mathbf{a} \times \mathbf{b}) \times \mathbf{c} = (\mathbf{c} \cdot \mathbf{b})\mathbf{a} - (\mathbf{c} \cdot \mathbf{a})\mathbf{b}\] This identity shows that the result of the triple product is a linear combination of the vectors \( \mathbf{a} \) and \( \mathbf{b} \).
03
Analyzing the Result
By examining the expression \( (\mathbf{c} \cdot \mathbf{b})\mathbf{a} - (\mathbf{c} \cdot \mathbf{a})\mathbf{b} \), we see that the result is composed of a sum of two terms that are multiples of \( \mathbf{a} \) and \( \mathbf{b} \).
04
Conclusion
Since \( (\mathbf{a} \times \mathbf{b}) \times \mathbf{c} = (\mathbf{c} \cdot \mathbf{b})\mathbf{a} - (\mathbf{c} \cdot \mathbf{a})\mathbf{b} \) is a linear combination of \( \mathbf{a} \) and \( \mathbf{b} \), it lies in the plane defined by \( \mathbf{a} \) and \( \mathbf{b} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
The cross product is a fascinating operation in vector mathematics. It is a binary operation performed on two vectors, resulting in a third vector that is perpendicular to the plane containing the first two vectors. This operation is indispensable in three-dimensional space. Consider two nonparallel vectors, \( \mathbf{a} \) and \( \mathbf{b} \). When you compute their cross product, denoted as \( \mathbf{a} \times \mathbf{b} \), the resulting vector can be visualized as pointing out of the plane formed by \( \mathbf{a} \) and \( \mathbf{b} \). This behavior is unique to three-dimensional spaces.
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The magnitude of the resulting vector from the cross product is given by \( \|\mathbf{a} \times \mathbf{b}\| = \|\mathbf{a}\|\|\mathbf{b}\|\sin(\theta) \), where \( \theta \) is the angle between \( \mathbf{a} \) and \( \mathbf{b} \). This value represents the area of the parallelogram with sides \( \mathbf{a} \) and \( \mathbf{b} \).
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It is essential to remember that the cross product is only defined in three dimensions and it has the important property of being anti-commutative, i.e., \( \mathbf{a} \times \mathbf{b} = - (\mathbf{b} \times \mathbf{a}) \).
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The magnitude of the resulting vector from the cross product is given by \( \|\mathbf{a} \times \mathbf{b}\| = \|\mathbf{a}\|\|\mathbf{b}\|\sin(\theta) \), where \( \theta \) is the angle between \( \mathbf{a} \) and \( \mathbf{b} \). This value represents the area of the parallelogram with sides \( \mathbf{a} \) and \( \mathbf{b} \).
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It is essential to remember that the cross product is only defined in three dimensions and it has the important property of being anti-commutative, i.e., \( \mathbf{a} \times \mathbf{b} = - (\mathbf{b} \times \mathbf{a}) \).
Vector Triple Product Identity
The vector triple product identity is a vital formula in vector mathematics, used particularly when dealing with combinations of cross products. Given three vectors \( \mathbf{a} \), \( \mathbf{b} \), and \( \mathbf{c} \), the triple product \( (\mathbf{a} \times \mathbf{b}) \times \mathbf{c} \) can appear complicated at first.
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Thankfully, there's a straightforward identity to simplify this expression:
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Thankfully, there's a straightforward identity to simplify this expression:
- This identity can be written as:
\[(\mathbf{a} \times \mathbf{b}) \times \mathbf{c} = (\mathbf{c} \cdot \mathbf{b})\mathbf{a} - (\mathbf{c} \cdot \mathbf{a})\mathbf{b}\] - This formula reveals that the triple product is a linear combination of the vectors \( \mathbf{a} \) and \( \mathbf{b} \), rather than a complex new vector.
Linear Combination
Understanding linear combinations is crucial for grasping vector mathematics. In the context of vectors, a linear combination involves creating a new vector by combining a set of vectors with corresponding coefficients. When you see the expression \((\mathbf{c} \cdot \mathbf{b})\mathbf{a} - (\mathbf{c} \cdot \mathbf{a})\mathbf{b} \), you are looking at a linear combination of two vectors \( \mathbf{a} \) and \( \mathbf{b} \).
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This expression essentially means that the resultant vector is made by adding vector \( \mathbf{a} \) multiplied by some scalar to vector \( \mathbf{b} \) multiplied by another scalar. These scalars \((\mathbf{c} \cdot \mathbf{b})\) and \(-(\mathbf{c} \cdot \mathbf{a})\) are derived from dot products with a third vector, \( \mathbf{c} \).
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In practical terms, a linear combination allows you to express a new vector in terms of known vectors. For instance:
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This expression essentially means that the resultant vector is made by adding vector \( \mathbf{a} \) multiplied by some scalar to vector \( \mathbf{b} \) multiplied by another scalar. These scalars \((\mathbf{c} \cdot \mathbf{b})\) and \(-(\mathbf{c} \cdot \mathbf{a})\) are derived from dot products with a third vector, \( \mathbf{c} \).
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In practical terms, a linear combination allows you to express a new vector in terms of known vectors. For instance:
- These combinations are often used in solving equations, analyzing movements in physics, or other practical applications involving vectors.
- Interestingly, by representing a vector as a linear combination of others, you confirm its position within the same plane or space jointly spanned by those original vectors.