Chapter 10: Problem 16
In each of Problems, a parametric representation of a curve is given. (a) Graph the curve. (b) Is the curve closed? Is it simple? (c) Obtain the Cartesian equation of the curve by eliminating the parameter (see Examples \(1-4\) ). $$ x=2 \cos ^{2} r, y=3 \sin ^{2} r ; 0 \leq r \leq 2 \pi $$
Short Answer
Expert verified
The curve is closed and simple; its Cartesian equation is \( y = 3 - \frac{3}{2}x \).
Step by step solution
01
Understanding the Parametric Equations
The given parametric equations are: \( x = 2\cos^2 r \) and \( y = 3\sin^2 r \) with \( 0 \leq r \leq 2\pi \). These equations describe a curve by varying the parameter \( r \).
02
Graph the Curve
To graph the curve, evaluate the parametric equations at various values of \( r \) within the interval \([0, 2\pi]\). You can create a table of values for \( r \) and the corresponding \( x \) and \( y \) values, which helps in plotting the points on a coordinate plane. This curve visually forms an ellipse.
03
Check if the Curve is Closed and Simple
A curve is closed if it forms a complete loop. Here, as \( r \) varies from \( 0 \) to \( 2\pi \), the path returns to the starting point, meaning the curve is closed. A simple curve does not intersect itself, and since every \( r \) value corresponds to a unique point, this curve is simple.
04
Eliminate the Parameter to Find the Cartesian Equation
To eliminate the parameter \( r \), use the Pythagorean identity. Start with: \( \sin^2r = 1 - \cos^2r \). From \( x = 2\cos^2r \), express \( \cos^2r \) as \( \cos^2r = \frac{x}{2} \). Substitute into \( y = 3\sin^2r \): \[ y = 3(1 - \cos^2r) = 3(1 - \frac{x}{2}) = 3 - \frac{3x}{2} \] Thus, the Cartesian equation is \( y = 3 - \frac{3}{2}x \).
05
Verify the Cartesian Equation
Check the Cartesian equation \( y = 3 - \frac{3}{2}x \) against the parametric bounds for consistency. For instance, substitute some \( (x, y) \) pairs from the original parametric equations into this Cartesian equation to verify their correctness.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Curves
Graphing curves from parametric equations involves creating a visual representation of the equations for given parameter ranges. A parametric equation describes both the x and y coordinates in terms of a third variable, commonly denoted as \( r \). This allows you to see the curve as \( r \) varies.
To graph the curve from the parametric equations \( x = 2\cos^2 r \) and \( y = 3\sin^2 r \), follow these steps:
To graph the curve from the parametric equations \( x = 2\cos^2 r \) and \( y = 3\sin^2 r \), follow these steps:
- Identify the parameter range, here it is \( 0 \leq r \leq 2\pi \).
- Incrementally choose values of \( r \) within this range, like \( 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi \).
- Calculate the corresponding \( x \) and \( y \) for each \( r \).
- Plot these points on the Cartesian coordinate plane to visualize the curve.
Closed and Simple Curves
A curve is considered closed if it forms a complete loop, meaning the curve ends where it begins after covering its path. In the context of parametric equations, we check if as \( r \) traverses its entire range, the ending and starting points coincide.
For our parametric representation \( x = 2\cos^2r \) and \( y = 3\sin^2r \), as \( r \) moves from \( 0 \) to \( 2\pi \), the path traversed returns to the starting point. Hence, this curve is closed.
A simple curve is one that does not intersect itself at any point other than potentially at its starting/ending point. In our example, each \( r \) corresponds to a unique point. This uniqueness implies no self-intersections, categorizing it as a simple curve.
For our parametric representation \( x = 2\cos^2r \) and \( y = 3\sin^2r \), as \( r \) moves from \( 0 \) to \( 2\pi \), the path traversed returns to the starting point. Hence, this curve is closed.
A simple curve is one that does not intersect itself at any point other than potentially at its starting/ending point. In our example, each \( r \) corresponds to a unique point. This uniqueness implies no self-intersections, categorizing it as a simple curve.
Cartesian Equation
To derive the Cartesian equation from parametric ones, you aim to remove the parameter \( r \) from the equations. By doing this, you establish a direct relationship between \( x \) and \( y \).
In this example, we use the identity \( \sin^2 r + \cos^2 r = 1 \). From the parametric equations given:
In this example, we use the identity \( \sin^2 r + \cos^2 r = 1 \). From the parametric equations given:
- Express \( \cos^2 r \) from \( x = 2\cos^2 r \) as \( \cos^2 r = \frac{x}{2} \).
- Substitute \( \cos^2 r \) into \( \sin^2 r = 1 - \cos^2 r \), giving \( \sin^2 r = 1 - \frac{x}{2} \).
- This results in \( y = 3(1 - \frac{x}{2}) = 3 - \frac{3}{2}x \).
Eliminating Parameters
Eliminating parameters transforms a parametric set of equations into a single equation in terms of \( x \) and \( y \). This is often useful for easier manipulations, especially when comparing with known equations.
To eliminate the parameter \( r \), we utilized trigonometric identities. Here's how it works:
To eliminate the parameter \( r \), we utilized trigonometric identities. Here's how it works:
- Start with the substitution \( \cos^2 r = \frac{x}{2} \) from the equation \( x = 2\cos^2 r \).
- Apply this to the identity \( \sin^2 r = 1 - \cos^2 r \), leading to \( \sin^2 r = 1 - \frac{x}{2} \).
- Add \( y = 3\sin^2 r \), substituting \( \sin^2 r \) yields \( y = 3 - \frac{3x}{2} \).