Chapter 0: Problem 44
A regular polygon of \(n\) sides is inscribed in a circle of radius \(r\). Find formulas for the perimeter, \(P,\) and area, \(A,\) of the polygon in terms of \(n\) and \(r\).
Short Answer
Expert verified
\(P = 2nr\sin\left(\frac{\pi}{n}\right),\ A = \frac{1}{2}nr^{2}\sin\left(\frac{2\pi}{n}\right)\).
Step by step solution
01
Understand the Problem
We need to find the perimeter and area of a regular polygon with \(n\) sides inscribed in a circle of radius \(r\). A regular polygon is perfectly symmetrical with all sides and angles equal.
02
Calculate Central Angle
A regular polygon inscribed in a circle forms \(n\) isosceles triangles with the center of the circle. The central angle of each triangle is \(\theta = \frac{2\pi}{n}\) radians.
03
Express Side Length Using Law of Cosines
Using the law of cosines in one of these triangles, the side length \(s\) of the polygon is derived as \(s = 2r \sin\left(\frac{\pi}{n}\right)\). This uses the property that \(s = 2r \sin\left(\frac{\theta}{2}\right)\).
04
Calculate the Perimeter
The perimeter \(P\) of the polygon is the number of sides multiplied by the side length. Therefore, \(P = n \cdot s = n \cdot 2r \sin\left(\frac{\pi}{n}\right)\).
05
Calculate the Area
The area \(A\) of one of the isosceles triangles formed is \(\frac{1}{2} \cdot r^{2} \cdot \sin\left(\theta\right)\). So, the total area of the polygon is \(A = n \cdot \frac{1}{2} \cdot r^{2} \cdot \sin\left(\frac{2\pi}{n}\right)\).
06
Combine Results
Thus, the formulas for the perimeter and area of the polygon are:\[ P = 2nr\sin\left(\frac{\pi}{n}\right) \]\[ A = \frac{1}{2} nr^{2} \sin\left(\frac{2\pi}{n}\right) \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Perimeter Calculation
To calculate the perimeter of a regular polygon inscribed in a circle, we first need to identify the side length of the polygon. The polygon has all sides and angles equal, providing a harmonious geometric structure. Each side of the polygon can be determined using trigonometric principles. Specifically, by employing the law of cosines, the side length \( s \) is expressed as:
- \( s = 2r \sin\left(\frac{\pi}{n}\right) \)
- \( P = n \times s = n \times 2r \sin\left(\frac{\pi}{n}\right) \)
Area Calculation
The area calculation of a regular polygon inscribed within a circle requires dividing the polygon into smaller geometric parts. Each of these parts is an isosceles triangle formed by two radii and one side of the polygon. The area \( A \) of each triangle can be calculated using:
- \( \text{Area of one triangle} = \frac{1}{2} r^2 \sin\left(\frac{2\pi}{n}\right) \)
- \( A = n \times \frac{1}{2} r^2 \sin\left(\frac{2\pi}{n}\right) \)
Law of Cosines
The law of cosines is a powerful tool in geometry that helps us derive relationships in triangles. For a regular polygon inscribed in a circle, we focus on the isosceles triangles formed by a side \( s \) and two radii \( r \). The law of cosines states:
- \( s^2 = 2r^2 - 2r^2 \cos(\theta) \)
- \( s = 2r \sin\left(\frac{\pi}{n}\right) \)
Inscribed Circle
An inscribed circle serves as the foundational base for locating a regular polygon symmetrically within it. This condition of being inscribed means the circle touches all vertices of the polygon, creating a balance and uniformity in the polygon's structure. Characteristics include:
- A center which is coincident with the polygon's center.
- A radius that is constant from the center to each vertex of the polygon.
Central Angle
The central angle is crucial when studying regular polygons inscribed in a circle because it aids in structuring the polygon into smaller, manageable parts. It is the angle subtended by each side of the polygon at the center of the circle. For a polygon with \( n \) sides, the central angle \( \theta \) is calculated as:
- \( \theta = \frac{2\pi}{n} \)