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Determine the convergence or divergence of the series. \(\sum_{n=1}^{\infty} \frac{1}{2 n-1}\)

Short Answer

Expert verified
The given series diverges.

Step by step solution

01

Identifying the Type of Series

Recognize that the series \(\sum_{n=1}^{\infty} \frac{1}{2 n-1}\) is a harmonic series with a linear term in the denominator which looks like \(\frac{1}{n}\) where 'n' is a positive integer.
02

Apply the P-test

The P-series test or p-test is applied to series of the form \(\sum_{n=1}^{\infty} \frac{1}{n^p}\). If the power p is greater than 1, the series converges; if the power p is less than or equal to 1, the series diverges. Here, our power p = 1.
03

Decision

As our power p=1 which is equal to 1, based on the P-test, the series \(\sum_{n=1}^{\infty} \frac{1}{2 n-1}\) diverges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Harmonic Series
A harmonic series is one of the classic types of infinite series in mathematics. It takes the form \[ \sum_{n=1}^{\infty} \frac{1}{n} \]where each term is the reciprocal of a positive integer. It's one of the most well-known examples of a series that diverges, meaning it doesn't converge to a specific value as the number of terms increases.
Think of it like this: despite each term getting smaller as you proceed further into the series, the sum still grows without bound. You might expect that as the terms become tiny, the sum would eventually settle at a finite number. But surprisingly, it doesn't; it just keeps increasing, albeit very slowly.
  • Example: The series 1 + \(\frac{1}{2} + \frac{1}{3} + \cdots \) is a harmonic series.
  • Each term decreases slowly, but never fast enough to make the total sum finite.
The concept of a harmonic series is foundational for understanding divergence in number series, and it highlights the intriguing nature of infinite sums.
P-series Test
The P-series test is a handy tool in determining whether certain series converge or diverge. It's particularly useful for series of the form \[ \sum_{n=1}^{\infty} \frac{1}{n^p} \]where \( p \) is a constant. The rule is straightforward:
  • If \( p > 1 \), the series converges.
  • If \( p \leq 1 \), the series diverges.
This test effectively helps in quickly assessing the nature of the series just by examining the exponent of \( n \) in the denominator. For instance, if you have a series like \( \sum_{n=1}^{\infty} \frac{1}{n^{1.5}} \), it converges because the power \( p = 1.5 \) is greater than 1.
For the exercise, the series given has terms just like a harmonic series but with a transformed denominator \( \frac{1}{2n-1} \), which effectively boils down to a \( p \)-series with \( p = 1 \). This implies its divergence following the P-series test.
Divergence of Series
When we discuss the divergence of a series, we refer to whether the sum of its terms does not settle or approach a specific number as more terms are added. Divergence tells us that the series grows indefinitely. In simple terms, no matter how far out you take the sum, it just keeps getting larger.
There are different reasons why series might diverge:
  • Like in a harmonic series, where even though each term decreases, the total sum grows endlessly.
  • For power series with \( p \leq 1 \), like the harmonic series, the terms aren't reducing fast enough to produce a finite sum.
Understanding divergence is crucial for distinguishing which infinite series can be evaluated to a finite sum and which cannot. For students dealing with problems involving series, recognizing divergence helps pinpoint the behavior of the infinite sum and avoids expectations of convergence where it isn't possible.

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