/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Determine whether the series con... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the series converges conditionally or absolutely, or diverges.\(\sum_{n=2}^{\infty} \frac{(-1)^{n}}{\ln n}\)

Short Answer

Expert verified
The series \(\sum_{n=2}^{\infty} \frac{(-1)^{n}}{\ln n}\) converges conditionally but not absolutely.

Step by step solution

01

Identifying Series Type

Recognise that the given infinite series \(\sum_{n=2}^{\infty} \frac{(-1)^{n}}{\ln n}\) is an alternating series because the (-1)^n term will alternate signs.
02

Apply Alternating Series Test

Applying the Alternating Series Test, we observe that (1) the terms \(\frac{1}{\ln n}\) are monotonically decreasing, and (2) the limit as n approaches infinity of \(\frac{1}{\ln n}\) is 0. Therefore, the series converges conditionally.
03

Apply Absolute Convergence Test

Applying the Absolute Convergence Test to \(\sum_{n=2}^{\infty} \frac{1}{\ln n}\), we find that the series diverges. This is because the sum of the absolute values of the series diverges. Therefore, the series does not converge absolutely.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alternating Series
Understanding alternating series is crucial in advanced calculus, especially when identifying series behavior. An alternating series is characterized by terms that switch signs. This means the series consists of both positive and negative numbers in a regular pattern. Often, it's expressed in the form \[ a_1 - a_2 + a_3 - a_4 + \ldots \].
These series have a specific test called the Alternating Series Test, which helps determine convergence. The test requires two conditions to be satisfied:
  • The absolute value of the terms \(a_n\) should decrease monotonically, meaning each term is smaller than the one before it.
  • The limit of \(a_n\) should approach zero as \(n\) approaches infinity.
If both are met, the series is considered to converge. However, it only means it converges conditionally, not absolutely. In the exercise, the series \(\sum_{n=2}^{\infty} \frac{(-1)^{n}}{\ln n}\) meets these conditions, indicating conditional convergence. This means although the terms balance each other out enough to converge, absolute convergence has not yet been confirmed.
Absolute Convergence
Absolute convergence is a stronger form of convergence compared to conditional convergence. For a series \(\sum a_n\), if the series of the absolute values \(\sum |a_n|\) converges, then the original series converges absolutely. This implies that the direction of the terms (whether positive or negative) does not affect its convergence.
To test for absolute convergence, you calculate the series without signs, effectively turning negative terms positive. If this resulting series converges, absolute convergence is confirmed.
In the provided exercise, we tested \(\sum \frac{1}{\ln n}\). Unfortunately, this series does not converge since it resembles the harmonic series, known for its divergence. It shows that although our original series converges conditionally, it does not converge absolutely.
Series Divergence
Series divergence is the opposite of convergence. A series diverges when its terms do not settle to a single finite number, essentially growing without bound or oscillating endlessly. For absolute convergence, a critical step is recognizing when the absolute values of the terms do not sum to a finite number.
A common situation where we see divergence is with harmonic-like series. In this exercise, despite the alternating pattern, the series \(\sum \frac{1}{\ln n}\) diverges because it resembles the harmonic series. When proving divergence, if the sum of \(|a_n|\) grows towards infinity, the series cannot possibly converge absolutely.
Divergence plays a vital role in analyzing convergence types and helps us understand why only conditional convergence occurs in some cases, as observed in the given exercise.

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Most popular questions from this chapter

Investigation The interval of convergence of the series \(\sum_{n=0}^{\infty}(3 x)^{n}\) is \(\left(-\frac{1}{3}, \frac{1}{3}\right)\) (a) Find the sum of the series when \(x=\frac{1}{6}\). Use a graphing utility to graph the first six terms of the sequence of partial sums and the horizontal line representing the sum of the series. (b) Repeat part (a) for \(x=-\frac{1}{6}\). (c) Write a short paragraph comparing the rate of convergence of the partial sums with the sum of the series in parts (a) and (b). How do the plots of the partial sums differ as they converge toward the sum of the series? (d) Given any positive real number \(M\), there exists a positive integer \(N\) such that the partial sum \(\sum_{n=0}^{N}\left(3 \cdot \frac{2}{3}\right)^{n}>M\) Use a graphing utility to complete the table. $$ \begin{array}{|l|l|l|l|l|} \hline \boldsymbol{M} & 10 & 100 & 1000 & 10,000 \\ \hline \boldsymbol{N} & & & & \\ \hline \end{array} $$

Find all values of \(x\) for which the series converges. For these values of \(x\), write the sum of the series as a function of \(x\). $$ \sum_{n=1}^{\infty}\left(\frac{x^{2}}{x^{2}+4}\right)^{n} $$

Probability A fair coin is tossed repeatedly. The probability that the first head occurs on the \(n\) th toss is given by \(P(n)=\left(\frac{1}{2}\right)^{n}\), where \(n \geq 1\) (a) Show that \(\sum_{n=1}^{\infty}\left(\frac{1}{2}\right)^{n}=1\). (b) The expected number of tosses required until the first head occurs in the experiment is given by \(\sum_{n=1}^{\infty} n\left(\frac{1}{2}\right)^{n}\) Is this series geometric? (c) Use a computer algebra system to find the sum in part (b).

Use the formula for the \(n\) th partial sum of a geometric series \(\sum_{i=0}^{n-1} a r^{i}=\frac{a\left(1-r^{n}\right)}{1-r}\) Salary You go to work at a company that pays \(\$ 0.01\) for the first day, \(\$ 0.02\) for the second day, \(\$ 0.04\) for the third day, and so on. If the daily wage keeps doubling, what would your total income be for working (a) 29 days, (b) 30 days, and (c) 31 days?

Find the Maclaurin series for \(f(x)=\ln \frac{1+x}{1-x}\) and determine its radius of convergence. Use the first four terms of the series to approximate \(\ln 3 .\)

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