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Determine the convergence or divergence of the series using any appropriate test from this chapter. Identify the test used. $$ \sum_{n=1}^{\infty} \frac{3}{n \sqrt{n}} $$

Short Answer

Expert verified
The series converges, according to the p-series test.

Step by step solution

01

Identify the form of the series

We can quickly see that this series is of the form \(\frac{1}{n^p}\), which is a p-series. We can write the series in this form by simplifying the fraction: \( \frac{3}{n \sqrt{n}} = \frac{3}{n^{1.5}}=3n^{-1.5} \). The p in this case is 1.5.
02

Apply the p-series test

The p-series test states that the p-series \( \sum_{n=1}^{\infty} n^{-p} \) is convergent if p > 1 and divergent if p ≤ 1. Since our p is 1.5, which is greater than 1, we can determine that the series is convergent.
03

Identify the test used

The test used in this case is the p-series test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

P-series Test
When examining the convergence of an infinite series, one effective approach is to use the p-series test. A p-series is an infinite series of the form \( \sum_{n=1}^{\infty} \frac{1}{n^p} \), where \( p \) is a constant. The convergence or divergence of a p-series depends on the value of \( p \).

According to the p-series test, a p-series is convergent if \( p > 1 \) and divergent if \( p \leq 1 \). This is because when \( p > 1 \) the terms of the series decrease quickly enough that their sum approaches a finite limit. Conversely, when \( p \leq 1 \), the terms do not decrease fast enough and the series 'grows' infinitely.

In the context of the exercise, the series \( \sum_{n=1}^{\infty} \frac{3}{n \sqrt{n}} \) can be simplified to \( 3n^{-1.5} \) which resembles the form of a p-series with \( p = 1.5 \), greater than 1. Hence, applying the p-series test immediately suggests its convergence without the need for further complex calculations.
Infinite Series
An infinite series is essentially the sum of an infinite sequence of numbers. It can be expressed in the form \( \sum_{n=1}^{\infty} a_n \), where \( a_n \) represents the nth term of the sequence. The intricate nature of infinite series requires specific methods for determining whether the sum is finite (convergent) or if it increases without bound (divergent).

The concept of infinite series is central to many areas of mathematics, particularly analysis and calculus, because it allows us to describe functions and number sets in compact forms. Furthermore, infinite series can model complex phenomena in physics and other sciences where finite sums are not sufficient.

Recognizing the form an infinite series takes, such as whether it is arithmetic, geometric, or a p-series, provides the necessary first step towards determining its convergence, as can be seen in the given exercise through the identification of the series as a p-series.
Convergent Series
A series is said to be convergent if the sum of its infinite terms approaches a specific value as n approaches infinity. This means that there is a clear limit to the sum despite the series being infinite. To determine if a series is convergent, various tests such as the p-series test, comparison test, ratio test, and others may be applied.

In practice, establishing convergence is critical for confirming that processes described by the series are well-defined and finite in nature. For example, in the field of series solutions to differential equations, convergence ensures that the obtained power series solution is meaningful and can represent a function over some interval.

Reflecting on the exercise provided, since the series \( \sum_{n=1}^{\infty} \frac{3}{n \sqrt{n}} \) is identified as a convergent p-series, it reassures us that the series has a finite limit, which is an integral conclusion in many practical applications.

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Most popular questions from this chapter

True or False? Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If \(\left\\{a_{n}\right\\}\) converges to 3 and \(\left\\{b_{n}\right\\}\) converges to 2, then \(\left\\{a_{n}+b_{n}\right\\}\) converges to 5 .

(a) Find the common ratio of the geometric series, (b) write the function that gives the sum of the series, and (c) use a graphing utility to graph the function and the partial sums \(S_{3}\) and \(S_{5^{*}}\). What do you notice? \(1-\frac{x}{2}+\frac{x^{2}}{4}-\frac{x^{3}}{8}+\cdots\)

Time The ball in Exercise 99 takes the following times for each fall. \(s_{1}=-16 t^{2}+16, \quad s_{1}=0\) if \(t=1\) \(s_{2}=-16 t^{2}+16(0.81), \quad s_{2}=0\) if \(t=0.9\) \(s_{3}=-16 t^{2}+16(0.81)^{2}, \quad s_{3}=0\) if \(t=(0.9)^{2}\) \(s_{4}=-16 t^{2}+16(0.81)^{3}, \quad s_{4}=0\) if \(t=(0.9)^{3}\): \(s_{n}=-16 t^{2}+16(0.81)^{n-1}, \quad s_{n}=0\) if \(t=(0.9)^{n-1}\) Beginning with \(s_{2}\), the ball takes the same amount of time to bounce up as it does to fall, and so the total time elapsed before it comes to rest is given by \(t=1+2 \sum_{n=1}^{\infty}(0.9)^{n}\) Find this total time.

Find all values of \(x\) for which the series converges. For these values of \(x\), write the sum of the series as a function of \(x\). $$ \sum_{n=0}^{\infty}(-1)^{n} x^{n} $$

Projectile Motion A projectile fired from the ground follows the trajectory given by $$ y=\left(\tan \theta-\frac{g}{k v_{0} \cos \theta}\right) x-\frac{g}{k^{2}} \ln \left(1-\frac{k x}{v_{0} \cos \theta}\right) $$ where \(v_{0}\) is the initial speed, \(\theta\) is the angle of projection, \(g\) is the acceleration due to gravity, and \(k\) is the drag factor caused by air resistance. Using the power series representation $$ \ln (1+x)=x-\frac{x^{2}}{2}+\frac{x^{3}}{3}-\frac{x^{4}}{4}+\cdots, \quad-1

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