/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Approximate the sum of the serie... [FREE SOLUTION] | 91Ó°ÊÓ

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Approximate the sum of the series by using the first six terms.\(\sum_{n=1}^{\infty} \frac{(-1)^{n+1} n}{2^{n}}\)

Short Answer

Expert verified
The sum of the first six terms of the series is approximately \(0.21875\).

Step by step solution

01

Identification Step

Identify the first term of the series \(a_1\). For the given series, \(a_1\) = 1/2. Also identify the common ratio \(r\). Here, \(-1/2\) is the common ratio.
02

Computation Step

Compute the first 6 terms of the series by multiplying the preceding term by \(-1/2\). The terms are \(1/2\), \(-1/4\), \(3/8\), \(-1/2\), \(5/32\), and \(-3/16\).
03

Summation Step

Add up the computed six terms of the series for the approximation of the sum. Therefore, the sum of the first six terms is \(1/2 - 1/4 + 3/8 - 1/2 + 5/32 - 3/16 = 0.21875\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergent Series
Understanding the behavior of infinite series is a fundamental concept in calculus and analysis. A convergent series is one where the sum of its terms approaches a specific value as the number of terms grows to infinity. The opposite is a divergent series, which means the sum does not settle to any value within the bounds of our standard number system.

When dealing with series, it's important to determine if a series converges or diverges before attempting to find its sum. The given series in the exercise, \(\sum_{n=1}^{\infty} \frac{(-1)^{n+1} n}{2^{n}}\)\, exhibits the signs of a convergent series because the terms decrease in absolute value as 'n' gets larger and alternate in sign, indicating the possibility of it being an alternating series which we will look at more closely in the summation step.
Geometric Series
A geometric series is a series in which each term after the first is obtained by multiplying the previous term by a fixed, non-zero number called the common ratio. This kind of series can be easily identified by this consistent multiplicative pattern.

In the provided example, while the terms of the series are related by a multiplier of \( -1/2 \) which suggests a geometric component, it's not a pure geometric series due to the increasing numerator. However, exploring the concept of geometric series is still advantageous here, as part of the series' behavior—specifically the alternating sign—is characteristic of geometric sequences or series. For a geometric series to converge, the common ratio's absolute value needs to be less than 1, and indeed, \( -1/2 \) satisfies that condition. While this shared aspect does not make our series geometric, it aids in understanding the alteration in signs and indicates convergence.
Series Summation
The series summation is the process of adding up the terms of a series to find a total or a sum. This process can either be done definitively for finite series or approximatively for infinite series, particularly when they are convergent.

In the exercise, we are using series summation to approximate the sum of the series by adding the first six terms. This is a common technique for estimating the sum of an infinite series, known as partial sum approximation. As we compute the terms \(\frac{1}{2} - \frac{1}{4} + \frac{3}{8} - \frac{1}{2} + \frac{5}{32} - \frac{3}{16} = 0.21875\)\, we use the understanding that adding more terms would continue to bring us closer to the series' actual sum, but for practical purposes, this approximation is often sufficient. In a classroom setting, emphasizing how each additional term impacts the accuracy of the sum would add depth to the exercise improvement.

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Most popular questions from this chapter

Compute the first six terms of the sequence \(\left\\{a_{n}\right\\}=\left\\{\left(1+\frac{1}{n}\right)^{n}\right\\}\) If the sequence converges, find its limit.

(a) You delete a finite number of terms from a divergent series. Will the new series still diverge? Explain your reasoning. (b) You add a finite number of terms to a convergent series. Will the new series still converge? Explain your reasoning.

Investigation The interval of convergence of the series \(\sum_{n=0}^{\infty}(3 x)^{n}\) is \(\left(-\frac{1}{3}, \frac{1}{3}\right)\) (a) Find the sum of the series when \(x=\frac{1}{6}\). Use a graphing utility to graph the first six terms of the sequence of partial sums and the horizontal line representing the sum of the series. (b) Repeat part (a) for \(x=-\frac{1}{6}\). (c) Write a short paragraph comparing the rate of convergence of the partial sums with the sum of the series in parts (a) and (b). How do the plots of the partial sums differ as they converge toward the sum of the series? (d) Given any positive real number \(M\), there exists a positive integer \(N\) such that the partial sum \(\sum_{n=0}^{N}\left(3 \cdot \frac{2}{3}\right)^{n}>M\) Use a graphing utility to complete the table. $$ \begin{array}{|l|l|l|l|l|} \hline \boldsymbol{M} & 10 & 100 & 1000 & 10,000 \\ \hline \boldsymbol{N} & & & & \\ \hline \end{array} $$

show that the function represented by the power series is a solution of the differential equation. $$ y=\sum_{n=0}^{\infty} \frac{x^{2 n}}{2^{n} n !}, \quad y^{\prime \prime}-x y^{\prime}-y=0 $$

Let \(f(x)=\sum_{n=0}^{\infty} \frac{x^{n}}{n !}\) (a) Find the interval of convergence of \(f\). (b) Show that \(f^{\prime}(x)=f(x)\). (c) Show that \(f(0)=1\). (d) Identify the function \(f\).

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