/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 Show that the length of one arch... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Show that the length of one arch of the sine curve is equal to the length of one arch of the cosine curve.

Short Answer

Expert verified
The length of one arch of the sine curve is equal to the length of one arch of the cosine curve.

Step by step solution

01

Calculate Derivatives

The derivative of the sin(x) function is cos(x) and the derivative of the cos(x) function is -sin(x). The square of each derivative will be used in the arc length formula for each function.
02

Apply Arc Length Formula to Sin(x)

Applying the length formula to sin(x), we will integrate from 0 to \( \pi/2 \) with f'(x)^2 = \(cos(x)^2\), with the formula we have \( L = \int_0^{\pi/2} \sqrt{1+ cos(x)^2} dx \).
03

Apply Arc Length Formula to Cos(x)

Similarly, applying the length formula to cos(x), we will integrate from 0 to \( \pi/2 \) with f'(x)^2 = \(-sin(x)^2\), with the formula we get \( L = \int_0^{\pi/2} \sqrt{1+ sin(x)^2} dx \) due to the fact the square of -sin(x) is \( sin(x)^2 \) due to squaring eliminating negative sign.
04

Comparing Results

Notice that at the end of Steps 2 and 3, the lengths of the arc for sin(x) and cos(x) gave the same integral, this shows that the length of one arch of the sine curve is equal to the length of one arch of the cosine curve.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus
Calculus is a branch of mathematics focused on limits, functions, derivatives, integrals, and infinite series. It's divided into two main parts: differential calculus and integral calculus. Differential calculus studies how things change when an infinitely small change is made, which involves derivatives. Integral calculus, on the other hand, focuses on the accumulation of quantities and the spaces under and between curves.

In the context of our exercise, calculus allows us to understand and calculate the length of curves - a task requiring both derivatives (to understand how steep the curve is at any given point) and integrals (to sum up all those infinitesimal straight-line distances and get the overall arc length).
Derivatives
In calculus, the derivative of a function represents the rate at which the function value changes as its input changes. Loosely speaking, a derivative can be thought of as how much the function is 'moving' at any given point. The process of finding a derivative is called differentiation.

For the exercise involving sine and cosine curves, knowing the derivatives of these functions is crucial. The derivative of sin(x) is cos(x) and the derivative of cos(x) is -sin(x). These derivatives help us comprehend the behavior of the functions and are essential inputs in the arc length formula, as we'll see in the integral calculus section.
Integral Calculus
Integral calculus is concerned with the concept of the integral, which is used to find areas under curves, volumes of solids of revolution, and, relevantly to our exercise, the lengths of curves. The integral adds up an infinite number of infinitesimally small quantities to find a whole.

In the case of calculating arc lengths, the procedure involves setting up an integral that sums the lengths of infinitesimally small, straight segments that approximate the curve. For the sine and cosine functions, integral calculus allows us to find the arc length of one arch by integrating a function derived from their squares' derivatives over a given interval.
Trigonometry
Trigonometry is the study of triangles, particularly right triangles, and the relationships between their angles and sides. However, it extends far beyond just triangles; it includes the study of the properties and applications of sine, cosine, and other trigonometric functions. These functions are waves that have important properties and can model a variety of phenomena.

The sine and cosine functions, which are periodic and repeat every full cycle of an angle's rotation (2π radians), are fundamental in our exercise. By examining their properties, we can show that the arc lengths of these curves over one period, or from 0 to π/2 for a quarter of their period, are equal — a beautiful symmetry in mathematics that is both practical and profound in its implications.

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Most popular questions from this chapter

Laplace Transforms Let \(f(t)\) be a function defined for all positive values of \(t\). The Laplace Transform of \(f(t)\) is defined by$$F(s)=\int_{0}^{\infty} e^{-s t} f(t) d t$$if the improper integral exists. Laplace Transforms are used to solve differential equations, find the Laplace Transform of the function. $$ f(t)=\cosh a t $$

State (if possible) the method or integration formula you would use to find the antiderivative. Explain why you chose that method or formula. Do not integrate. $$ \int \frac{e^{x}}{e^{x}+1} d x $$

True or False? , determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If \(f^{\prime}\) is continuous on \([0, \infty)\) and \(\lim _{x \rightarrow \infty} f(x)=0\), then \(\int_{0}^{\infty} f^{\prime}(x) d x=-f(0)\).

Consider the integral \(\int_{0}^{\pi / 2} \frac{4}{1+(\tan x)^{n}} d x\) where \(n\) is a positive integer. (a) Is the integral improper? Explain. (b) Use a graphing utility to graph the integrand for \(n=2,4\), 8 , and 12 . (c) Use the graphs to approximate the integral as \(n \rightarrow \infty\). (d) Use a computer algebra system to evaluate the integral for the values of \(n\) in part (b). Make a conjecture about the value of the integral for any positive integer \(n .\) Compare your results with your answer in part (c).

True or False? , determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If \(f\) is continuous on \([0, \infty)\) and \(\lim _{x \rightarrow \infty} f(x)=0\), then \(\int_{0}^{\infty} f(x) d x\) converges.

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