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Select the basic integration formula you can use to find the integral, and identify \(u\) and \(a\) when appropriate. $$ \int \frac{2 t-1}{t^{2}-t+2} d t $$

Short Answer

Expert verified
The integral \(\int \frac{2t-1}{t^{2}-t+2} dt\) simplifies to \( ln|t^{2}-t+2| + C\)

Step by step solution

01

Apply the method of Partial Fractions

First, express the given integrand \(\frac{2t-1}{t^{2}-t+2}\) as a sum or difference of simpler fractions. In this case, we rearrange and redefine terms to obtain: \(\frac{2t-1}{t^{2}-t+2} = \frac{2t-t+2-t+1}{t^{2}-t+2}\) = \(\frac{2(t-1)+2-(t-1)}{t^{2}-t+2}\) = \(2\frac{t-1}{t^{2}-t+2} - \frac{t-1}{t^{2}-t+2}\)
02

Perform the Integration

Next, perform the integration operation on the new expression. The first term is a standard rational function and can be directly integrated while for the second term we take \(u=t-1\) and \(du=dt.\) So, \[\int \frac{2t-1}{t^{2}-t+2} dt\] = \(2\int \frac{1}{t^{2}-t+2}dt - \int \frac{1}{t^{2}-t+2}dt\)
03

Simplify the Integration:

Simplify the integral derived in step 2 using integration of rational functions: \[\int \frac{1}{t^{2}-t+2} dt =\frac{1}{2} ln|t^{2}-t+2| + C\] as this is the general form. Calculate the two integrals separately to obtain the final answer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integral Calculus
Integral calculus is a key branch of mathematical analysis focusing on theories and techniques for evaluating integrals, which represent the area under a curve, accumulation of quantities, or more abstractly, the antiderivative operation.

Understanding how to solve an integral involves recognizing various types of functions and applying appropriate techniques to find their integrals. In the context of our exercise, \[ \int \frac{2 t-1}{t^{2}-t+2} d t \], the goal is to determine the function whose derivative is \(\frac{2 t-1}{t^{2}-t+2}\) — essentially reversing the differentiation process.

To approach integration problems, students must be fluent with basic integration formulas, such as those for power functions \(\int x^n dx = \frac{x^{n+1}}{n+1}+C\), exponential functions \(\int e^x dx = e^x + C\), and trigonometric functions \(\int\sin(x)dx = -\cos(x)+C\), among others. Learning integration by partial fractions, as seen in the provided exercise, is a crucial skill for handling rational function integrations which cannot be tackled directly through elementary formulas.
Rational Function Integration
Rational function integration pertains to the integration of functions represented as ratios of two polynomials. The integrand in our exercise, \(\frac{2 t-1}{t^{2}-t+2}\), is a rational function because it is one polynomial divided by another.

Direct integration of rational functions is not always simple. However, there are several strategies to address them, with one of the most powerful being the method of partial fractions. This method allows students to decompose a complex rational function into simpler fractions that can be integrated readily.

To achieve a better comprehension of rational function integration, students should familiarize themselves with the notion of antiderivatives and practice the application of integration techniques such as substitution, by-parts integration, and of course, partial fractions, which is particularly useful when the denominator is a quadratic or higher degree polynomial.
Method of Partial Fractions
The method of partial fractions is a technique used specifically for integrating rational functions where the degree of the numerator is less than the degree of the denominator. The aim is to express a complex rational function as a sum of simpler fractions whose antiderivatives are more straightforward to find.

In the step-by-step solution, the given integrand \(\frac{2t-1}{t^{2}-t+2}\) is initially decomposed into simpler terms. This is a crucial part of the method, involving algebraic manipulations to rewrite the integrand in a form that is easier to integrate.

To master this method, it's beneficial for students to practice recognizing and creating partial fraction decompositions. Once the rational function is broken down into parts, integrating each part often becomes much simpler-oftentimes, reducing the problem to integrating basic functions, as seen with the term \(2\int \frac{1}{t^{2}-t+2}dt\) in the exercise.

It's also essential to understand the role of constants and variables. In the solution given, by setting \(u=t-1\), the student essentially applies a u-substitution simplifying the integration process. By thoroughly understanding partial fractions, students can confidently tackle a wide range of rational functions found in their calculus courses.

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