Chapter 8: Problem 47
Evaluate the definite integral. Use a graphing utility to confirm your result. $$ \int_{0}^{4} x e^{-x / 2} d x $$
Short Answer
Expert verified
The evaluated integral is approximately 1.2094
Step by step solution
01
Apply Integration by Parts
In integration by parts, the integral of a product of two functions is given by \(uv - \int v du\). By letting \(u = x\) and \(dv = e^{-x / 2} dx\), we can find that \(du = dx\) and \(v = -2e^{-x / 2}\).
02
Apply the Integration by Parts Formula
Applying these values to the formula, the integral becomes: \(-2x e^{-x / 2} - \int -2 e^{-x / 2} dx\). This simplifies further to \(-2x e^{-x / 2} + 4e^{-x / 2} \).
03
Evaluate the Definite Integral
We substitute the limits 0 and 4 into the integral to find its numerical value: \( -2x e^{-x / 2} + 4e^{-x / 2} \bigg|_0^4 \). This simplifies to \( -8e^{-2} + 4e^{-2} - 4 \).
04
Compute Value
By calculating the values, we can simplify the result to 4 - 16 e^{-2} approximately equal to 1.2094.
05
Confirm the Result with a Graphing Utility
To confirm the result visually, plot the function \( f(x) = xe^{-x/2} \) on a graphing utility and calculate integral from 0 to 4, which should give a close value to the calculated result.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration by Parts
Integration by parts is a valuable technique in calculus for evaluating integrals, especially those involving a product of functions. The general formula you use is \[ \int u \, dv = uv - \int v \, du \]. Here’s how it works:
- Selecting functions: Choose which part of the integrand is \(u\) and which is \(dv\). A common rule is to let \(u\) be a function that becomes simpler when differentiated, while \(dv\) is something easily integrated.
- Computing derivatives and integrals: Once you have \(u\) and \(dv\), find \(du\) by differentiating \(u\), and \(v\) by integrating \(dv\).
- Substituting into the formula: Substitute \(u\), \(v\), \(du\) into the integration by parts formula to transform the original integral into a hopefully simpler one.
- \(u = x\), hence \(du = dx\).
- \(dv = e^{-x/2} \, dx\), resulting in \(v = -2e^{-x/2}\).
Graphing Utility
A graphing utility is a digital tool that helps visualize functions and confirm integrals or other calculus problems. It can be an application on a calculator or a computer-based software such as Desmos or GeoGebra. Here’s how you can make the most of it:
- Visualizing Functions: Plotting allows you to see the function’s behavior and its curve. It offers a geometric understanding which might not be obvious from the equation alone.
- Evaluating Integrals: After you’ve calculated an integral by hand, using a graphing utility provides confirmation. Input the function and set the interval, and the utility will compute the area under the curve.
- Checking Work: If your integral’s result from the utility closely matches your hand-calculated value, it reassures the work is likely correct.
Numerical Integration
Numerical integration is a strategy to approximate the value of a definite integral. It's especially useful when the integral does not have an elementary antiderivative or is complex. Popular techniques include:
Though for our integral \(\int_{0}^{4} xe^{-x/2} \, dx\), we solved it analytically, numerical methods can be excellent for confirming results or handling functions that can't easily be integrated by basic calculus methods.
- Trapezoidal Rule: Approximates the area under a curve by dividing the total area into trapezoids rather than rectangles. It's a step up in accuracy from simpler methods like Riemann sums.
- Simpson’s Rule: This combines parabolic arcs rather than straight lines to better fit the curve being integrated. It often yields more accurate results than the trapezoidal rule.
Though for our integral \(\int_{0}^{4} xe^{-x/2} \, dx\), we solved it analytically, numerical methods can be excellent for confirming results or handling functions that can't easily be integrated by basic calculus methods.