/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 $$ y=x^{2}, y=x^{3} $$... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

$$ y=x^{2}, y=x^{3} $$

Short Answer

Expert verified
The points of intersection between the two curves \(y=x^2\) and \(y=x^3\) are (0,0) and (1,1).

Step by step solution

01

Equate the two curves

To find the points of intersection, we set the two equations equal to each other: \(x^2 = x^3\).
02

Solve the equation

We rearrange the equation to get all terms on one side: \(x^3 - x^2 = 0\). Then we factor out \(x^2\) which gives \(x^2(x - 1) = 0\). Setting each factor equal to zero gives two potential solutions: \(x=0\) or \(x=1\).
03

Find y-coordinates

Substitute the values of \(x\) we found into either of our original equations to find the corresponding \(y\)-coordinates. If we substitute these into the first equation \(y=x^2\), we get \(y=0\) when \(x=0\) and \(y=1\) when \(x=1\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Polynomial Equations
Understanding how to solve polynomial equations is crucial in algebra and forms the foundation for much of coordinate geometry and calculus. In the given exercise, we encounter a straightforward polynomial equation, where we are setting two functions, y = x^2 and y = x^3, equal to each other. This process essentially asks, 'At what x-values do these functions output the same y-value?'

To solve for x, we subtract one equation from the other to get x^3 - x^2 = 0, which simplifies our problem to a single variable polynomial equation. In polynomial equations, the aim is to find the roots, or the values of x that make the equation true. By factoring the polynomial, we can break this down into easier pieces, allowing us to see that x=0 or x=1 are solutions to the equation. Remember that every time you set a factor equal to zero, you are finding a potential root of the polynomial equation.
Factoring Polynomials
Factoring polynomials is a method used to simplify expressions and solve equations by finding the 'building blocks' that make up the polynomial. Consider the step where we take x^3 - x^2 = 0 and factor out an x^2, leaving us with x^2(x - 1) = 0.

Why do we factor? Factoring transforms the equation into a product of simpler terms, which we can then solve individually. In algebra, if a product equals zero, one or more of the multiplied factors must be zero. This property allows us to set each factor equal to zero and solve for x. The factored form makes it evident that x=0 is a solution because x^2=0, and also that x=1 is another solution because x-1=0. When faced with a polynomial equation, always look for common factors and use factoring as a tool to find the roots efficiently.
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is the study of geometry using a coordinate system. This allows us to translate geometric problems into algebraic equations, which we can then solve systematically. In our example, we are working with the Cartesian coordinate system, which uses two perpendicular axes, horizontal (x-axis) and vertical (y-axis), to define the position of points.

To find the points of intersection between the curves y = x^2 and y = x^3, we look for pairs of x and y-values that satisfy both equations simultaneously. In this case, solving the polynomial equation leads us to x-values, and substituting these back into the original equations gives us the corresponding y-values, providing us with complete coordinates for the points of intersection. The beauty of coordinate geometry lies in its ability to connect the abstract world of algebra with the concrete world of geometry, allowing us to solve problems that have both numerical and visual interpretations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Individual Project \(\quad\) Select a solid of revolution from everyday life. Measure the radius of the solid at a minimum of seven points along its axis. Use the data to approximate the volume of the solid and the surface area of the lateral sides of the solid.

Writing Read the article "Arc Length, Area and the Arcsine Function" by Andrew M. Rockett in Mathematics Magazine. Then write a paragraph explaining how the arcsine function can be defined in terms of an arc length.

\mathrm{\\{} T h i n k ~ A b o u t ~ I t ~ C o n s i d e r ~ t h e ~ e q u a t i o n ~ \(\frac{x^{2}}{9}+\frac{y^{2}}{4}=1\). (a) Use a graphing utility to graph the equation. (b) Set up the definite integral for finding the first quadrant arc length of the graph in part (a). (c) Compare the interval of integration in part (b) and the domain of the integrand. Is it possible to evaluate the definite integral? Is it possible to use Simpson's Rule to evaluate the definite integral? Explain. (You will learn how to evaluate this type of integral in Section 8.8.)

Pumping Gasoline In Exercises, find the work done in pumping gasoline that weighs 42 pounds per cubic foot. (Hint: Evaluate one integral by a geometric formula and the other by observing that the integrand is an odd function.) A cylindrical gasoline tank 3 feet in diameter and 4 feet long is carried on the back of a truck and is used to fuel tractors. The axis of the tank is horizontal. The opening on the tractor tank is 5 feet above the top of the tank in the truck. Find the work done in pumping the entire contents of the fuel tank into a tractor.

Find the center of mass of the point masses lying on the \(x\) -axis. $$ \begin{aligned} &m_{1}=6, m_{2}=3, m_{3}=5 \\ &x_{1}=-5, x_{2}=1, x_{3}=3 \end{aligned} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.