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91Ó°ÊÓ

Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If prices are rising at a rate of \(0.5 \%\) per month, then they are rising at a rate of \(6 \%\) per year.

Short Answer

Expert verified
False. If prices are rising at a rate of \(0.5 \%\) per month, they are actually rising at a rate of approximately \(6.17 \%\) per year, not \(6 \%\), due to the effect of compounding.

Step by step solution

01

Understand the Problem

The problem states that the prices are rising at a rate of \(0.5 \%\) per month and asserts that this equals to \(6 \%\) per year. To evaluate this, it's important to remember that the yearly rate is not necessarily 12 times the monthly rate because the increases get compounded.
02

Calculate the Yearly Rate

Let's calculate the yearly rate of growth based on the monthly rate. We start with an initial amount of 1 (this can represent any starting price). After one year, if the growth is compounded monthly at \(0.5\%\) or \(0.005\) as a decimal, the amount after a year (12 months) would be \(1(1 + 0.005)^{12}\) = \(1.061678\), according to the formula for compounded interest.
03

Compare

The computed value 1.061678 shows a growth rate of \(6.1678\%\). This exceeding \(6\%\) clearly demonstrates that the statement is false. The yearly rate of growth is higher than \(6\%\) because of the effect of compounding.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Compounding Interest
When we talk about compounding interest, it refers to the process where the value grows based not only on the initial amount but also on the interest accumulated from previous periods. This compounding effect means that over time, the value increases at an increasing rate.

Here's how it works:
  • Each period, the amount grows by a percentage (interest rate).
  • For the next period, this percentage is applied to the new total amount, i.e., the original amount plus the compounded interest.
  • This process repeats over different compounding periods, causing the value to grow exponentially rather than linearly.
In our given problem, the prices increase at 0.5% every month. When we apply this percentage to the monthly compounded amounts, we use a mathematical formula for compounded interest over 12 months: \[A = P (1 + r/n)^{nt}\]where:
  • \(A\) is the future value (what you have after a year),
  • \(P\) is the initial amount (starting price),
  • \(r\) is the annual interest rate (expressed as a decimal),
  • \(n\) is the number of compounding periods within a year,
  • \(t\) is the time in years.
In our scenario, the calculation reveals how the compounding effect causes the annual growth rate to surpass the simple multiplication of the monthly rate by 12.
Monthly Interest Rate
The monthly interest rate is quite simply the rate or percentage by which a value increases each month. It's an important metric for evaluating short-term growth within a year.

To calculate the monthly interest rate in the context of our exercise, we convert the given percentage into a decimal. For a 0.5% monthly increase, we divide by 100 to get the decimal form: \(0.5\% = 0.005\).This simple transformation is crucial for calculations relating to compounding because all these changes need to be expressed as decimals.

Each month, the rate is applied to the current value (which includes the past month's compounded interest), resulting in what's referred to as **compounding monthly growth**. When compounded over several periods like in our problem, the monthly rate significantly contributes to the annual growth, as the interest accumulates on top of previously accumulated interest.
Annual Growth Rate
The annual growth rate provides a comprehensive measure of increase over one year, considering the effect of all periodic increases within that time frame.

It’s not simply the sum of the monthly rates due to the compounding effect. Instead, the annual growth incorporates compounded accumulation, showing the power of compound interest over time.

In our exercise, to find the annual growth owing to a 0.5% monthly increase, we compound monthly over a year using:\[1(1 + 0.005)^{12}\]This result gives us a multiplier that when applied to the original amount (let’s use 1 for simplicity) yields a growth of about 6.1678% instead of 6%.

Understanding this difference is crucial as it highlights how compounded rates impact the total annual growth compared to a straightforward multiplication of the monthly rate by 12. By seeing the annual effect, students can grasp the influence of compounding which often results in a higher value than initially anticipated.

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Most popular questions from this chapter

Glucose is added intravenously to the bloodstream at the rate of \(q\) units per minute, and the body removes glucose from the bloodstream at a rate proportional to the amount present. Assume that \(Q(t)\) is the amount of glucose in the bloodstream at time \(t\). (a) Determine the differential equation describing the rate of change of glucose in the bloodstream with respect to time. (b) Solve the differential equation from part (a), letting \(Q=Q_{0}\) when \(t=0\). (c) Find the limit of \(Q(t)\) as \(t \rightarrow \infty\).

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