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When predicting population growth, demographers must consider birth and death rates as well as the net change caused by the difference between the rates of immigration and emigration. Let \(P\) be the population at time \(t\) and let \(N\) be the net increase per unit time resulting from the difference between immigration and emigration. So, the rate of growth of the population is given by $$ \frac{d P}{d t}=k P+N, \quad N \text { is constant. } $$ Solve this differential equation to find \(P\) as a function of time if at time \(t=0\) the size of the population is \(P_{0}\).

Short Answer

Expert verified
The solution to the given differential equation, considering an initial population \(P_{0}\) at \(t=0\), is \(P(t) = e^{kt}(-Nt + P_{0})\).

Step by step solution

01

Setting Up the Differential Equation

According to the problem, the rate of growth of the population is given by the differential equation \(\frac{d P}{d t}=k P+N\), where \(N\) is a constant representing the net increase in population due to migration.
02

Solving the Differential Equation

This is a first-order linear differential equation. In order to solve it, we can perform separation of variables and then integrate. Rewrite the equation as: \(\frac{d P}{d t} - kP = N\), which can be solved as an integrating factor problem. The integrating factor here is \(e^{-kt}\). We multiply through by this factor, giving us \(e^{-kt} \frac{d P}{d t} - k e^{-kt} P = Ne^{-kt}\). This can be rewritten as a derivative: \(\frac{d}{dt} [ e^{-kt} P] = Ne^{-kt}\). Integrating both sides gives \(e^{-kt} P = -Nt + C\), where \(C\) is the constant of integration.
03

Applying the Initial Condition

We know from the problem's statement that at \(t=0\), the size of the population is \(P_{0}\). We use this condition to solve for \(C\). Substituting into the equation gives us \(e^{0} P_{0} = -N*0 + C\), so \(C = P_{0}\). The population \(P\) as a function of time is then given by \(P(t) = e^{kt}(-Nt + P_{0})\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Growth
Population growth is a fascinating topic that involves the study of how populations change over time. In demographic studies, it's important to understand the components that influence these changes.
This includes birth rates, death rates, and migration patterns. All these factors together help predict how a population will grow.When assessing population growth, demographers look at the *net change*. This net change is particularly significant as it reflects the balance between people entering and leaving an area.
  • **Birth Rates and Death Rates:** These are natural components influencing growth. More births than deaths mean growth, and vice versa.
  • **Migration:** The movement of people in and out also affects population size. Those entering increase population, while those exiting decrease it.
The mentioned equation \( \frac{dP}{dt} = kP + N \) captures this essence. Here, \( k \) represents the intrinsic rate of growth or decay due to births and deaths, and \( N \) symbolizes a constant net change from migration. This equation helps predict future population size at any given time, which is invaluable for planning and resource allocation.
First-order Linear Differential Equations
First-order linear differential equations are a type of differential equation where the highest derivative is the first derivative.
These are often encountered in various scientific fields and serve as basic models for numerous processes, including population growth. In mathematical terms, an equation of the form \( \frac{dy}{dt} + P(t)y = Q(t) \) is first-order linear. The population growth model \( \frac{dP}{dt} - kP = N \) fits this mold nicely.Solving a first-order linear differential equation typically involves transforming it into a more integrable form. This is accomplished using techniques such as:
  • **Separation of Variables:** This method involves rearranging the equation to isolate the differentials on each side.
  • **Integrating Factor:** This technique is especially useful when the equation cannot easily be separated.
These techniques enable us to solve the model equation, offering insights into how parameters like \( k \) and \( N \) affect population dynamics over time.
Integrating Factor
The integrating factor method is a clever solution technique for solving first-order linear differential equations.
This approach simplifies complex equations, making them more easily solvable by integration.To handle an equation like \( \frac{dP}{dt} - kP = N \), the integrating factor, which is \( e^{-kt} \), is chosen strategically. It is derived based on the coefficient of \( P \) in the differential equation.Using this factor:
  • We multiply through the equation by \( e^{-kt} \). This transformation simplifies the left-hand side into a derivative.
  • It transforms the equation into \( \frac{d}{dt}[e^{-kt}P] = Ne^{-kt} \), a more manageable form.
Subsequently, integrating both sides with respect to \( t \) provides a solution that is then adjusted using any initial conditions, such as \( P(0) = P_0 \).
With these steps, the integrating factor method emerges as a powerful tool for solving various dynamic equations, including those depicting population trends.

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Most popular questions from this chapter

The logistic differential equation models the growth rate of a population. Use the equation to (a) find the value of \(k\), (b) find the carrying capacity, (c) use a computer algebra system to graph a slope field, and (d) determine the value of \(P\) at which the population growth rate is the greatest. \(\frac{d P}{d t}=3 P\left(1-\frac{P}{100}\right)\)

The management at a certain factory has found that a worker can produce at most 30 units in a day. The learning curve for the number of units \(N\) produced per day after a new employee has worked \(t\) days is \(N=30\left(1-e^{k t}\right)\). After 20 days on the job, a particular worker produces 19 units. (a) Find the learning curve for this worker. (b) How many days should pass before this worker is producing 25 units per day?

Consider a tank that at time \(t=0\) contains \(v_{0}\) gallons of a solution of which, by weight, \(q_{0}\) pounds is soluble concentrate. Another solution containing \(q_{1}\) pounds of the concentrate per gallon is running into the tank at the rate of \(r_{1}\) gallons per minute. The solution in the tank is kept well stirred and is withdrawn at the rate of \(r_{2}\) gallons per minute. A 200 -gallon tank is full of a solution containing 25 pounds of concentrate. Starting at time \(t=0\), distilled water is admitted to the tank at a rate of 10 gallons per minute, and the well-stirred solution is withdrawn at the same rate. (a) Find the amount of concentrate \(Q\) in the solution as a function of \(t\). (b) Find the time at which the amount of concentrate in the tank reaches 15 pounds. (c) Find the quantity of the concentrate in the solution as \(t \rightarrow \infty\).

Solve the Bernoulli differential equation. $$ y y^{\prime}-2 y^{2}=e^{x} $$

The logistic equation models the growth of a population. Use the equation to (a) find the value of \(k\), (b) find the carrying capacity, (c) find the initial population, (d) determine when the population will reach \(\mathbf{5 0 \%}\) of its carrying capacity, and (e) write a logistic differential equation that has the solution \(P(t)\). \(P(t)=\frac{1500}{1+24 e^{-0.75 t}}\)

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