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Determine the quadrants in which the solution of the differential equation is an increasing function. Explain. (Do not solve the differential equation.) $$ \frac{d y}{d x}=\frac{1}{2} x^{2} y $$

Short Answer

Expert verified
The solution of the differential equation is an increasing function in Quadrant I and Quadrant II.

Step by step solution

01

Understanding the Quadrants

Identify the quadrants I-IV on a Cartesian Plane. Remember that Quadrant I: x > 0, y > 0; Quadrant II: x < 0, y > 0; Quadrant III: x < 0, y < 0; and Quadrant IV: x > 0, y < 0.
02

Identify the Sign of dy/dx

According to the given differential equation, \( \frac{dy}{dx}=0.5x^2y \), we see that the change in y is proportional to \(x^2\) (which is always positive for any x) and y. Therefore, the sign of \(\frac{dy}{dx}\) would be the same as the sign of y in any quadrant.
03

Identifying Quadrants where the Function is Increasing

A function is said to be increasing if its derivative is positive. As we established in Step 2, the sign of the derivative, \(\frac{dy}{dx}\) is the same as the sign of y. So, the function is increasing where y > 0. This happens in Quadrant I where x > 0 and y > 0, and Quadrant II where x < 0, y > 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cartesian Plane Quadrants
The Cartesian plane is a fundamental concept in mathematics, providing a platform to visually represent algebraic equations.

Divided into four regions known as quadrants, the plane is structured by a horizontal axis, typically called the x-axis, and a vertical axis, known as the y-axis. These axes intersect at a point called the origin. Each quadrant is defined by the sign of the coordinates:
  • Quadrant I: Both x and y are positive (x > 0, y > 0).
  • Quadrant II: x is negative and y is positive (x < 0, y > 0).
  • Quadrant III: Both x and y are negative (x < 0, y < 0).
  • Quadrant IV: x is positive and y is negative (x > 0, y < 0).
Understanding these quadrants is crucial when discussing the behavior of functions, such as identifying where a function is increasing or decreasing.
Derivative of a Function
A derivative is a powerful tool in calculus that measures how a function changes as its input changes. Essentially, it gives us the rate of change or the slope of the function at any point.

The derivative of a function is represented as \( \frac{dy}{dx} \) for a function \( y \) with respect to the variable \( x \). If the derivative is positive over an interval, the function is increasing; if it's negative, the function is decreasing. In the context of differential equations like \( \frac{dy}{dx}=0.5x^2y \), the terms in the equation dictate how the solution behaves. Specifically, \( 0.5x^2 \) is always positive except for \( x = 0 \), affecting the slope of the function, and hence, its increasing or decreasing nature.
Increasing Function
In mathematical terms, a function is said to be increasing on an interval if for any two points \( a \) and \( b \) within that interval where \( a < b \), the value of the function at \( a \) is less than the value at \( b \), meaning \( f(a) < f(b) \).

This concept directly relates to the sign of the derivative. If the derivative of a function is positive over an interval, the function is increasing on that interval. Following the exercise at hand, the solution to the differential equation \( \frac{dy}{dx}=0.5x^2y \) will be increasing in the quadrants where the y-value is positive, namely Quadrant I and Quadrant II. This is because the product of the positive function \( 0.5x^2 \) and a positive y-value results in a positive rate of change, which indicates an increasing function.

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