/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Determine whether the function i... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the function is a solution of the differential equation \(x y^{\prime}-2 y=x^{3} e^{x}\). $$ y=\ln x $$

Short Answer

Expert verified
No, \(y=\ln x\) is not a solution to the given differential equation.

Step by step solution

01

Calculation of the function's derivative

The derivative of the given function \(y=\ln x\) is \(y'=\frac{1}{x}\).
02

Replacing in the differential equation

Now we substitute \(y\) and \(y'\) into the differential equation : it is \(x*\frac{1}{x} - 2*\ln x=x^{3} e^{x}\). After simplifying this equation we get \(1 - 2*\ln x=x^{3} e^{x}\).
03

Checking the equation

Upon checking, the left hand side of the equation is not equal to the right hand side. Therefore, we conclude that \(y=\ln x\) is not a solution to the given differential equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Derivative
A function derivative is a fundamental concept in calculus. It describes the rate at which a function's output changes relative to its input. In simpler terms, it tells us how fast a function is growing or shrinking at any given point.
To find the derivative of a function like \(y = \ln x\), we follow a specific rule: the derivative of \(\ln x\) with respect to \(x\) is \(y' = \frac{1}{x}\).
This rule comes from the fact that the exponential and logarithmic functions are inverses of each other. The behavior of their derivatives reflects this relationship. When you calculate a derivative, you often determine whether a function will be increasing or decreasing at a particular point. Here, this derivative \( \frac{1}{x} \) tells us that for positive \(x\), as \(x\) increases, the rate of change gets smaller.


Key points about function derivatives:

  • They measure how a function changes with respect to change in its input.
  • The derivative of \(\ln x\) is \(\frac{1}{x}\).
  • Understanding derivatives helps solve differential equations, like in our given problem.
Exponential Function
Exponential functions are a special set of functions that have constants raised to a variable power. The general form of an exponential function is \(a^{x}\), where \(a\) is a constant base. One key exponential function is \(e^{x}\), where \(e\) is approximately 2.718, known as Euler's number.
Exponential functions grow at a rate proportional to their value, meaning the larger the output, the faster it grows. This property makes them vital in modeling growth situations, like populations or investments.
In the differential equation from our exercise, \(x^{3}e^{x}\) represents the right-hand side. It combines polynomial \(x^{3}\) with the exponential component \(e^{x}\), showing how various functions can interact.


Important aspects of exponential functions:

  • They grow rapidly, especially when the base exceeds 1.
  • The derivative of \(e^{x}\) is itself, \(e^{x}\).
  • They can be combined with other functions, like polynomials, to model complex phenomena.
Logarithmic Function
Logarithmic functions are the inverses of exponential functions. For a given exponential base, like \(a\), the logarithmic function is written as \(\log_{a}(x)\), the power to which the base must be raised to produce \(x\).
In most practical applications, especially in calculus, we often use the natural logarithm, \(\ln x\), where the base is \(e\). This is because the natural logarithm helps simplify the derivatives and integrals of exponential functions.
In the exercise, \(y = \ln x\) is checked as a potential solution for the differential equation. Though it doesn't solve the equation, understanding its role illustrates how logarithmic and exponential forms are interchanged in calculations.


Key points about logarithmic functions:

  • Inverse of exponential functions.
  • Simplify calculations involving growth rates and areas under curves.
  • Play an essential role in exponential decay and growth problems.

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Most popular questions from this chapter

A calf that weighs 60 pounds at birth gains weight at the rate \(\frac{d w}{d t}=k(1200-w)\) where \(w\) is weight in pounds and \(t\) is time in years. Solve the differential equation. (a) Use a computer algebra system to solve the differential equation for \(k=0.8,0.9\), and 1 . Graph the three solutions. (b) If the animal is sold when its weight reaches 800 pounds, find the time of sale for each of the models in part (a). (c) What is the maximum weight of the animal for each of the models?

Solve the first-order differential equation by any appropriate method. $$ (x+y) d x-x d y=0 $$

Use the differential equation for electric circuits given by$$ L \frac{d I}{d t}+R I=E. $$ In this equation, \(I\) is the current, \(R\) is the resistance, \(L\) is the inductance, and \(E\) is the electromotive force (voltage). Use the result of Exercise 49 to find the equation for the current if \(I(0)=0, E_{0}=120\) volts, \(R=600 \mathrm{ohms}\), and \(L=4\) henrys. When does the current reach \(90 \%\) of its limiting value?

In a chemical reaction, a certain compound changes into another compound at a rate proportional to the unchanged amount. If initially there are 20 grams of the original compound, and there is 16 grams after 1 hour, when will 75 percent of the compound be changed?

The table shows the population \(P\) (in millions) of the United States from 1960 to \(2000 .\) (Source: U.S. Census Bureau) $$ \begin{array}{|l|c|c|c|c|c|} \hline \text { Year } & 1960 & 1970 & 1980 & 1990 & 2000 \\ \hline \text { Population, } P & 181 & 205 & 228 & 250 & 282 \\ \hline \end{array} $$ (a) Use the 1960 and 1970 data to find an exponential model \(P_{1}\) for the data. Let \(t=0\) represent \(1960 .\) (b) Use a graphing utility to find an exponential model \(P_{2}\) for the data. Let \(t=0\) represent \(1960 .\) (c) Use a graphing utility to plot the data and graph both models in the same viewing window. Compare the actual data with the predictions. Which model better fits the data? (d) Estimate when the population will be 320 million.

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