/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 92 Find the indefinite integral.\(\... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the indefinite integral.\(\int \frac{e^{x}-e^{-x}}{e^{x}+e^{-x}} d x\)

Short Answer

Expert verified
The indefinite integral of the given expression is \(ln(cosh(x)) + C\).

Step by step solution

01

Simplify Expression

Firstly, recognize the given expression as a simplification of hyperbolic functions: \(\frac{sinh(x)}{cosh(x)} = tanh(x)\). So, the integral now becomes \(\int{tanh(x)}\, dx\).
02

Integrate the Simplified Expression

The integral of \(tanh(x)\) can be obtained as a standard result, and it is \(ln(cosh(x)) + C\), where C is the constant of integration.
03

Write Final Answer

The indefinite integral of the original expression thus is \(ln(cosh(x)) + C\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hyperbolic Functions
Hyperbolic functions are analogs of the more common circular trigonometric functions, but they are based on hyperbolas rather than circles. These functions include hyperbolic sine (\(sinh\)), hyperbolic cosine (\(cosh\)), and hyperbolic tangent (\(tanh\)). For the given exercise, understanding these functions is crucial.

Here, the hyperbolic tangent function is introduced, defined as:
  • \(tanh(x) = \frac{sinh(x)}{cosh(x)}\).
The relation shows how hyperbolic functions can be interconnected. By simplifying the original expression, \(\frac{e^{x}-e^{-x}}{e^{x}+e^{-x}}\), it is directly transformed into \(tanh(x)\). This transformation is vital for integration because it allows us to use standard results.

In general, just like their trigonometric counterparts, hyperbolic functions are critical in calculus, especially when dealing with complex or exponential functions.
Integration Techniques
Integration techniques involve methods to find integrals either definite or indefinite. With an indefinite integral, we find antiderivatives. In the given exercise, the use of simplification is notable. When faced with a complex integral, identifying it as a form of a simpler known integral can save much effort.
Exploring techniques:
  • Simplification: Recognizing expressions as forms of familiar functions, such as hyperbolic or trigonometric ones, can simplify integration significantly.
  • Standard Integrals: Knowing standard results helps in quick identification and integration of basic functions. For instance, the integral of \(tanh(x)\) is known and can be directly applied.
In this case, by recognizing \(tanh(x)\), we directly applied the formula for its integral, which is \(ln(cosh(x)) + C\). This step-by-step simplification and identification transform a potentially difficult integration into a straightforward application of known results.
Calculus
Calculus is the branch of mathematics that studies continuous change. It consists of two major areas: differentiation and integration. Integration is the process of finding the integral of a function, which can be thought of as the reverse operation of differentiation.
In calculus, we engage with a range of functions, including polynomial, trigonometric, exponential, and hyperbolic, each having its own familiars and standards. The exercise here is a perfect example of how calculus concepts are applied, requiring knowledge of:
  • Function identification: Recognizing that \(\frac{e^{x}-e^{-x}}{e^{x}+e^{-x}}\) simplifies to a hyperbolic function (\(tanh(x)\)).
  • Standard integration results: Quickly integrating familiar forms like \(tanh(x)\) using known solutions, e.g., \(ln(cosh(x)) + C\).
This exercise illustrates the value of understanding calculus basics thoroughly—by mastering fundamental principles like these, solving complex problems can become more manageable.

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Most popular questions from this chapter

Vertical Motion An object is dropped from a height of 400 feet. (a) Find the velocity of the object as a function of time (neglect air resistance on the object). (b) Use the result in part (a) to find the position function. (c) If the air resistance is proportional to the square of the velocity, then \(d v / d t=-32+k v^{2}\), where \(-32\) feet per second per second is the acceleration due to gravity and \(k\) is a constant. Show that the velocity \(v\) as a function of time is \(v(t)=-\sqrt{\frac{32}{k}} \tanh (\sqrt{32 k} t)\) by performing the following integration and simplifying the result. \(\int \frac{d v}{32-k v^{2}}=-\int d t\) (d) Use the result in part (c) to find \(\lim _{t \rightarrow \infty} v(t)\) and give its interpretation. (e) Integrate the velocity function in part (c) and find the position \(s\) of the object as a function of \(t\). Use a graphing utility to graph the position function when \(k=0.01\) and the position function in part (b) in the same viewing window. Estimate the additional time required for the object to reach ground level when air resistance is not neglected. (f) Give a written description of what you believe would happen if \(k\) were increased. Then test your assertion with a particular value of \(k\).

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