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Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. The exponential function \(y=C e^{x}\) is a solution of the differential equation \(d^{n} y / d x^{n}=y, n=1,2,3, \ldots .\)

Short Answer

Expert verified
The statement is true. The exponential function \(y=C e^{x}\) is a solution of the differential equation \(d^{n} y / d x^{n}=y\) for all positive integers n.

Step by step solution

01

Define the function and differentiate

The given function is \(y=C e^{x}\). The first derivative of this function is \(y'=C e^{x}\), which equals \(y\), satisfying the equation for \(n=1\). The second derivative is again \(y''=C e^{x}\), which is equal to the function y, satisfying the equation for \(n=2\).
02

Determine the pattern

It can be seen that the nth derivative of \(y=C e^{x}\) is the same as the original function. Therefore, \(y=C e^{x}\) satisfies the differential equation \(d^{n} y / d x^{n}=y\) for any positive integer value of n.
03

Conclude

Based on the evidence presented by following the steps, it can be concluded that the statement given in the problem is indeed true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are mathematical expressions that describe situations where a constant quantity is multiplied by itself repeatedly over time. Specifically, the function of the form y = C e^{x}, where C is a constant and e is the base of the natural logarithm, is a classic example of an exponential function.

An important property of exponential functions is that their rate of growth is proportional to their current value. That's why they appear so frequently in real-life scenarios such as population growth, radioactive decay, and compound interest calculations.

Additionally, exponential functions have unique characteristics when it comes to calculus. The derivative of an exponential function with base e is a remarkable feature, as it is proportional to the function itself. This means that if you differentiate y=C e^{x} with respect to x, the resulting derivative is y' = C e^{x}, which is the same as the original function multiplied by the constant C. This self-similarity property of the exponential function's derivative makes it incredibly useful in many branches of mathematics and science, especially when solving differential equations.
Derivatives
Derivatives are a cornerstone of calculus and provide a way to measure how a function's output changes as its input changes. They are often thought of as the instantaneous rate of change or the slope of the tangent line to the function's graph at a specific point.

In the context of exponential functions like y = C e^{x}, derivatives give us insight into the function's growth rate at any point. The remarkable thing about the derivative of an exponential function is that it retains the original function's form. As observed in the step-by-step solution, taking the derivative of y=C e^{x} any number of times n will always yield the original function times the constant C, reinforcing the concept that the exponential function is its own derivative.

Understanding how to compute derivatives is not only key for solving problems in calculus but also for modeling and predicting real-world phenomena. Derivatives play a crucial role in various scientific fields, including physics, engineering, economics, and beyond.
Mathematical Induction
Mathematical induction is a technique used to prove statements or formulas about integers. The process includes two steps: proving the base case and proving the inductive step, which assumes the statement is true for a certain number n and then demonstrates it must also be true for n+1.

When applied to the statement that the nth derivative of an exponential function y=C e^{x} is y, mathematical induction can be employed to prove the statement for all positive integer values of n.

Once we know that the base case for n=1 holds true—as it returns the function itself when differentiated—mathematical induction allows us to assume all subsequent n derivatives will also yield the same exponential function. It fortifies our understanding of calculus and provides a logical framework for proving a wide range of mathematical assertions, guaranteeing the reliability and consistency of mathematical theory and its applications.

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Most popular questions from this chapter

Find the derivative of the function. $$ y=\tanh ^{-1}(\sin 2 x) $$

Graph \(y_{1}=\frac{x}{1+x^{2}}, y_{2}=\arctan x\), and \(y_{3}=x\) on \([0,10]\). Prove that \(\frac{x}{1+x^{2}}<\arctan x0\).

An object is projected upward from ground level with an initial velocity of 500 feet per second. In this exercise, the goal is to analyze the motion of the object during its upward flight. (a) If air resistance is neglected, find the velocity of the object as a function of time. Use a graphing utility to graph this function. (b) Use the result in part (a) to find the position function and determine the maximum height attained by the object. (c) If the air resistance is proportional to the square of the velocity, you obtain the equation $$ \frac{d v}{d t}=-\left(32+k v^{2}\right) $$ where \(-32\) feet per second per second is the acceleration due to gravity and \(k\) is a constant. Find the velocity as a function of time by solving the equation $$ \int \frac{d v}{32+k v^{2}}=-\int d t $$ (d) Use a graphing utility to graph the velocity function \(v(t)\) in part (c) if \(k=0.001\). Use the graph to approximate the time \(t_{0}\) at which the object reaches its maximum height. (e) Use the integration capabilities of a graphing utility to approximate the integral \(\int_{0}^{t_{0}} v(t) d t\) where \(v(t)\) and \(t_{0}\) are those found in part (d). This is the approximation of the maximum height of the object. (f) Explain the difference between the results in parts (b) and (e).

Find the integral. $$ \int \operatorname{sech}^{2}(2 x-1) d x $$

Verify the differentiation formula. $$ \frac{d}{d x}\left[\operatorname{sech}^{-1} x\right]=\frac{-1}{x \sqrt{1-x^{2}}} $$

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