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Solve the differential equation. $$g^{\prime}(x)=6 x^{2}, g(0)=-1$$

Short Answer

Expert verified
The solution to the given differential equation is \(g(x) = 2x^{3} - 1\).

Step by step solution

01

Determining the Indefinite Integral

Obtain the indefinite integral of the given \(g'(x)\), to get \(g(x)\). Thus, \(\int g'(x)\, dx = \int 6x^{2}\, dx = 2x^{3} + C\), where C is the constant of integration.
02

Calculate the Constant of Integration

Determine the constant \(C\) using the given condition \(g(0) = -1\). So, by substituting into \(g(x) = 2(0)^{3} + C\), we get \(C = -1\).
03

Writing the Solution

Combine the obtained values to write the solution of the differential equation, \(g(x) = 2x^{3} - 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indefinite Integral
An indefinite integral is an integral that does not have limits or boundaries specified for its integration. It represents a family of functions and is expressed generally with a constant of integration, denoted as 'C'.

The process of finding an indefinite integral is called anti-differentiation or integration. In our example, the indefinite integral of \(g'(x) = 6x^2\) is determined by integrating with respect to \(x\). This means we are looking for a function \(g(x)\) whose derivative is \(6x^2\).

The integral of \(6x^2\) results in \(2x^3\), since the power rule indicates that you increase the exponent by one and divide by the new exponent. However, since integration can produce an entire family of functions, an arbitrary constant \(C\) is added: \[g(x) = 2x^3 + C\]. This constant ensures our solution encompasses all possible functions that could differentiate back to \(6x^2\).

Understanding indefinite integrals is essential, especially in solving differential equations, because they help in reversing the process of differentiation, allowing us to find the original function from its derivative.
Constant of Integration
The constant of integration, represented by the letter 'C', plays a crucial role in indefinite integration. It arises due to the fact that multiple functions can share the same derivative.

Hence, when you integrate a function, you are actually finding not just one function but a family of functions that differ by a constant. In this way, the solution can account for all potential horizontal shifts.

In our problem, after integrating \(g'(x) = 6x^2\), we got \(g(x) = 2x^3 + C\). Without a specific condition, \(C\) can be any real number, leading to infinite potential solutions for \(g(x)\).

Therefore, to determine \(C\) uniquely and pinpoint the exact function fitting the original differential equation, we need additional information—an initial condition or boundary condition, as provided in most practical scenarios of differential equations.
Initial Conditions
Initial conditions are additional pieces of information that allow us to find a specific solution from the general solution of a differential equation. These conditions specify values of the function or its derivatives at particular points, thereby helping determine the constant of integration.

In the problem at hand, the initial condition given is \(g(0) = -1\). It means that when \(x = 0\), the function \(g(x)\) has a value of \(-1\).

By substituting the values from the initial condition into the function obtained from indefinite integration, \(g(x) = 2x^3 + C\), we are able to compute the specific constant \(C\):
  • Substitute \(x = 0\) into the equation: \(g(0) = 2(0)^3 + C = -1\)
  • Solve for \(C\): \(C = -1\)
This transforms the general solution into the specific solution that satisfies both the differential equation and the initial condition: \(g(x) = 2x^3 - 1\).

Thus, initial conditions are essential for determining the precise solution of a differential equation, anchoring the flexibility provided by the constant of integration.

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Most popular questions from this chapter

Slope Fields (a) use a graphing utility to graph a slope field for the differential equation, (b) use integration and the given point to find the particular solution of the differential equation, and (c) graph the solution and the slope field in the same viewing window. $$\frac{d y}{d x}=2 x,(-2,-2)$$

A particle moves along the \(x\) -axis at a velocity of \(v(t)=1 / \sqrt{t}\) \(t>0\). At time \(t=1\), its position is \(x=4\). Find the acceleration and position functions for the particle.

If \(f^{\prime}(x)=\left\\{\begin{array}{cc}1, & 0 \leq x<2 \\ 3 x, & 2 \leq x \leq 5\end{array}, f\right.\) is continuous, and \(f(1)=3\), find \(f .\) Is \(f\) differentiable at \(x=2 ?\)

Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If \(f\) is continuous on \([a, b]\), then \(f\) is integrable on \([a, b]\).

Two airplanes are in a straight-line landing pattern and, according to FAA regulations, must keep at least a three-mile separation. Airplane \(A\) is 10 miles from touchdown and is gradually decreasing its speed from 150 miles per hour to a landing speed of 100 miles per hour. Airplane \(\mathrm{B}\) is 17 miles from touchdown and is gradually decreasing its speed from 250 miles per hour to a landing speed of 115 miles per hour. (a) Assuming the deceleration of each airplane is constant, find the position functions \(s_{1}\) and \(s_{2}\) for airplane \(A\) and airplane B. Let \(t=0\) represent the times when the airplanes are 10 and 17 miles from the airport. (b) Use a graphing utility to graph the position functions. (c) Find a formula for the magnitude of the distance \(d\) between the two airplanes as a function of \(t .\) Use a graphing utility to graph \(d .\) Is \(d<3\) for some time prior to the landing of airplane \(A\) ? If so, find that time.

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