/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 State the Fundamental Theorem of... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Problem 53

State the Fundamental Theorem of Calculus.

Short Answer

Expert verified
The Fundamental Theorem of Calculus consists of two parts: 1) If a function f is continuous over the interval [a, b] and F is an antiderivative of f on [a, b], then \( \int_{a}^{b} f(x) \, dx = F(b) - F(a) \). 2) If a function f is continuous over an interval I containing a, then for every x in I, the function F defined by \( F(x) = \int_{a}^{x} f(t) \, dt \) is continuous on I and differentiable on the interior of I, and F'(x) = f(x) for all x in I.

Step by step solution

01

Formulate Part 1

The first part of the Fundamental Theorem of Calculus, often called the First Fundamental Theorem of Calculus, links differentiation and integration in a precise way. It states that if a function f is continuous over the interval [a, b] and F is an antiderivative of f on [a, b], then \( \int_{a}^{b} f(x) \, dx = F(b) - F(a) \). In other words, the definite integral of a function can be calculated using one of its antiderivatives.
02

Formulate Part 2

The second part of the Fundamental Theorem of Calculus, often referred to as the Second Fundamental Theorem of Calculus, gives an integral as a function and describes the derivative of that function. It states that if a function f is continuous over an interval I containing a, then for every x in I, the function F defined by \( F(x) = \int_{a}^{x} f(t) \, dt \) is continuous on I and differentiable on the interior of I, and F'(x) = f(x) for all x in I. This means that the derivative of the integral of a function is just the original function.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is one of the two main operations in calculus. It refers to finding the derivative of a function, which represents the rate of change of the function's value with respect to a variable. The derivative gives us a precise value for how a small change in one variable affects a change in another variable.
  • For example, if you have a function describing the position of a car over time, the derivative gives you the speed of the car at any given moment.
  • In mathematical terms, if you have a function \( f(x) \), the derivative is noted as \( f'(x) \).
The process of differentiation breaks down a complex relationship into simpler rates of change. Understanding differentiation is crucial because it allows us to analyze and predict how a system behaves under different conditions.
Integration
Integration is the inverse process of differentiation, and together they form the core of calculus. Integration involves finding an integral, which represents the accumulation of quantities. It can be thought of as finding the area under a curve.
  • There are two types of integrals: indefinite and definite.
  • Indefinite integrals give us a family of functions and are often expressed with a constant \( C \).
  • Definite integrals provide a specific number that represents the area under a curve from one point to another.
Integration helps in solving problems related to the total amount or cumulative effect, such as calculating distances, areas, and even probabilities in certain cases.
Definite Integral
A definite integral is a type of integral that computes the net area under a function over a specific interval. Unlike indefinite integrals, which yield functions, definite integrals provide numerical values.
  • The notation for a definite integral is \( \int_{a}^{b} f(x) \, dx \).
  • The limits of integration, \( a \) and \( b \), represent the bounds of the interval over which you want to find the area.
  • Definite integrals are used for calculating real-world quantities like total distance, area, and volume.
Using the Fundamental Theorem of Calculus, you can calculate definite integrals by evaluating an antiderivative at the upper and lower bounds of the interval.
Antiderivative
Antiderivatives are functions that "reverse" differentiation. Given a function \( f(x) \), its antiderivative \( F(x) \) is a function such that \( F'(x) = f(x) \). Every function has many antiderivatives differing by a constant \( C \).
  • An antiderivative provides a way to backtrack through the process of differentiation, helping to recover a function that gives \( f(x) \) upon differentiation.
  • In practical terms, an antiderivative gives us the "original" function before differentiation occurred.
  • Antiderivatives are crucial for solving integrals. Knowing an antiderivative enables you to compute definite and indefinite integrals.
Effectively working with antiderivatives is central to applying the Fundamental Theorem of Calculus in real-world scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sketch the region whose area is given by the definite integral. Then use a geometric formula to evaluate the integral \((a>0, r>0)\). $$ \int_{-1}^{1}(1-|x|) d x $$

A particle moves along the \(x\) -axis at a velocity of \(v(t)=1 / \sqrt{t}\) \(t>0\). At time \(t=1\), its position is \(x=4\). Find the acceleration and position functions for the particle.

If \(p(x)\) is a polynomial function, then \(p\) has exactly one antiderivative whose graph contains the origin.

An evergreen nursery usually sells a certain shrub after 6 years of growth and shaping. The growth rate during those 6 years is approximated by \(d h / d t=1.5 t+5\) where \(t\) is the time in years and \(h\) is the height in centimeters. The seedlings are 12 centimeters tall when planted \((t=0)\). (a) Find the height after \(t\) years. (b) How tall are the shrubs when they are sold?

Find the value(s) of \(c\) guaranteed by the Mean Value Theorem for Integrals for the function over the given interval. $$ f(x)=\cos x, \quad[-\pi / 3, \pi / 3] $$
See all solutions

Recommended explanations on Math Textbooks

Mechanics Maths

Read Explanation

Geometry

Read Explanation

Logic and Functions

Read Explanation

Probability and Statistics

Read Explanation

Applied Mathematics

Read Explanation

Theoretical and Mathematical Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.