/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Sketch the graph of the arbitrar... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch the graph of the arbitrary function \(f\) such that \(f^{\prime}(x)\left\\{\begin{array}{ll}>0, & x<4 \\ \text { undefined, } & x=4 \\ <0, & x>4\end{array}\right.\)

Short Answer

Expert verified
The function \(f\) increases for \(x<4\), has an undefined derivative at \(x=4\), which may indicate a sharp turn or cusp, and decreases for \(x>4\). The graph will generally form a 'v' or '∩' shape centered at \(x = 4\).

Step by step solution

01

Interpret the Meaning of the Derivative Values

The derivative of a function provides information about the rate of change of the function at specific points. A positive derivative indicates that the function is increasing at that point (i.e., the slope of the tangent line to the function at that point is positive), while a negative derivative indicates that the function is decreasing (i.e., the slope is negative). If the derivative is undefined at a point, it often means the function has a sharp turn or a cusp there.
02

Apply the Meaning to the Given Exercise

From the problem, we understand that the function \(f\):\(\) increases for \(x<4\): Because the derivative is positive, the function is moving upwards as \(x\) increases up to 4. \(\) has an undefined derivative at \(x=4\): This suggests that there is a sharp turn or cusp at \(x = 4\). \(\) decreases for \(x>4\): Because the derivative is negative, the function is moving downwards as \(x\) increases beyond 4.
03

Draw the Function \(f\)

With the knowledge from step 2, draw a graph that starts low (for values \(x<4\)), has a sharp turn or cusp at \(x=4\), and then decreases (for \(x>4\)). The precise shape of the function is not given, but it will generally have a 'v' or '∩' type shape centered at \(x = 4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivatives
Derivatives tell us how a function changes as we move along the x-axis. Think of the derivative as a measuring tool that calculates how steep or flat a curve is at any given point. For any function, the derivative gives information about the slope of the tangent line at a certain point. If the derivative is positive at a point, it implies that the function is increasing at that point, meaning the slope is going up as you move along the curve. Conversely, if the derivative is negative, the function is decreasing, indicating a slope that goes down. In simple terms:
  • A positive derivative means the function is climbing up.
  • A negative derivative means the function is going down.
  • An undefined derivative can signal interesting behaviors in the graph, like sharp turns or cusps.
Understanding derivatives is crucial when sketching graphs, as they provide important clues about the function's behavior.
Increasing and Decreasing Functions
Understanding when a function is increasing or decreasing is essential for graph sketching. An increasing function suggests that as you move to the right on the graph, the function goes up, like climbing a hill. This occurs when the derivative is greater than zero \(f'(x) > 0\). On the other hand, a decreasing function means moving right brings you downwards, similar to descending a hill. This happens when the derivative is less than zero \(f'(x) < 0\). Here's what this means practically:
  • If a function's derivative is positive over an interval, the function is increasing in that interval.
  • If a derivative is negative, the function decreases over that interval.
For the function described in the problem, it increases for \(x < 4\) and decreases for \(x > 4\). This change in behavior at \(x = 4\) is particularly interesting. Observing the sign of the derivative at different intervals helps identify regions where the function is rising or falling.
Sharp Turn or Cusp
An undefined derivative can be intriguing because it often indicates an unusual point on the function's graph, such as a sharp turn or cusp. A sharp turn or cusp means the graph suddenly changes direction sharply, unlike the smooth slopes seen elsewhere. Here's what to know about these peculiar features:
  • At a sharp turn or cusp, the slope of the function does not exist; this is why the derivative is undefined.
  • A cusp is typically a point where the graph looks like a sharp peak or point, making the slopes from either side approach infinity differently.
  • Sharp turns indicate moments where the function abruptly changes direction, which can be visualized as a 'V' shape or an inverted 'V'.
In the original exercise, at \(x = 4\), the derivative of the function \(f(x)\) is unspecified, suggesting such a feature. This can result in the graph having a sharp, noticeable bend, which makes it stand out around this point. Such characteristics are crucial when sketching because they define the graph's overall shape and continuity.

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