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In Exercises find the limit. $$ \lim _{x \rightarrow-\infty} \frac{x}{\sqrt{x^{2}+1}} $$

Short Answer

Expert verified
The limit of \(\lim _{x \rightarrow-\infty} \frac{x}{\sqrt{x^{2}+1}}\) is \(-1\).

Step by step solution

01

Identify the form

Observe the function \[ \frac{x}{\sqrt{x^{2}+1}} \] as \(x\) approaches negative infinity. It is of the form \(\frac{-\infty}{\infty}\) which is an indeterminate form. In such cases, we can use L'Hôpital's rule.
02

Apply L'Hôpital's rule

L'Hôpital's rule states that for functions of the form \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\), the limit can be found as the limit of their derivatives. Compute the derivatives of the numerator and denominator. Derivative of \(x\) is \(1\) and the derivative of \(\sqrt{x^{2}+1}\) using chain rule is \(\frac{x}{\sqrt{x^{2}+1}}\). So we get \(\lim _{x \rightarrow-\infty} \frac{1}{\frac{x}{\sqrt{x^{2}+1}}}\)
03

Simplify the formula

Now simplify the ratio, \(\lim _{x \rightarrow-\infty} \frac{\sqrt{x^{2}+1}}{x}\). The limit is again of indeterminate form which means we can apply L'Hôpital's rule again and get \(\lim _{x \rightarrow-\infty} \frac{\frac{x}{\sqrt{x^{2}+1}}}{1}\)
04

Applying L'Hôpital's rule again

After applying L'Hôpital's rule again, we get \(\lim _{x \rightarrow-\infty} \frac{x}{\sqrt{x^{2}+1}}\) which is the same function we started with. However, now we know that if this limit exists it must be the same as the one we just calculated. Evaluating at \(x = -\infty\), we finally get the limit as \(-1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indeterminate Forms
In the world of calculus, indeterminate forms are expressions that do not have definite values at first glance. These often occur in limit problems, where evaluating straightforwardly leads to ambiguous cases like \( \frac{0}{0}, \frac{\infty}{\infty}, 0\cdot\infty, \infty - \infty, \text{etc.} \). When dealing with limits, encountering an indeterminate form means you cannot conclude the value of the limit directly, and further analysis is required.

An indeterminate form hints that standard approaches to find a limit may not be sufficient. It signals the necessity for mathematical tools or techniques to simplify or transform the expression to reveal a solvable limit. Whether it’s through algebraic manipulation or applying rules like L'Hôpital's, the goal is to move past the ambiguity into a clear-cut answer for the limit.
L'Hôpital's Rule
L'Hôpital's Rule is an effective technique for solving indeterminate forms like \( \frac{0}{0} \) and \( \frac{\infty}{\infty} \). Named after the French mathematician Guillaume de l'Hôpital, this rule provides a method to evaluate the limits of expressions that initially result in these indeterminate forms.

The rule states: if the limits of the numerator and the denominator of a function both approach either zero or infinity, the limit of the fraction can be found by taking the derivative of the numerator and the denominator separately, i.e., \[\lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}\]
if the latter limit exists or is\( \pm \infty \). This becomes especially useful in cases where algebraic manipulation doesn’t simplify the expression or when dealing with trigonometric or exponential functions.

Using L'Hôpital's Rule effectively requires a couple of checks:
  • Ensure the original limit is of an indeterminate form.
  • If the limit can still be indeterminate after applying the rule, it might be necessary to apply the rule more than once.
  • Keep checking for simplified forms that could emerge after differentiation, which could reveal the limit without further need for derivatives.
Infinite Limits
Infinite limits are a concept that arises when the values of a function grow without bound as the input variable approaches a particular point. Practically, this can mean the function tends towards positive or negative infinity. In our example case, as \( x \to -\infty \), we need to investigate the behavior of the function \( \frac{x}{\sqrt{x^2 + 1}} \).

Achieving an understanding of infinite limits involves analyzing how each part of the function behaves when the input becomes extremely large (either positively or negatively). The objective is not to determine a finite value that a function approaches, but rather to describe its tendency towards infinity or negative infinity.

Here's how we can break down the concept:
  • Check how the numerator and the denominator behave separately as \( x \to -\infty \).
  • The dominant term in the expression significantly impacts the result. Simplifying this could hint at approaching a finite value or confirming the tendency to infinity.
  • In contexts like these, determining the quotient of leading terms helps in understanding the final limit — it might simplify to a finite number even when both terms independently tend to infinity.

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