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Find the derivative of the function. \(f(t)=-2 t^{2}+3 t-6\)

Short Answer

Expert verified
The derivative of the function \(f(t)=-2 t^{2}+3 t-6\) is \(f'(t) = -4t + 3\).

Step by step solution

01

Apply the power rule on the first term

The derivative of \(-2 t^{2}\) is calculated by multiplying the power by the coefficient and then reducing the power by 1. According to the power rule, this results in \(-2*2*t^{2-1}= -4t\).
02

Apply the power rule on the second term

Similarly, the derivative of \(3 t\) is calculated. In this case, it's like \(t\) is to the power of 1, so the power rule gives \(3*1*t^{1-1} = 3\).
03

Compute the derivative of the constant term

The derivative of a constant, in this case \(-6\), is always 0.
04

Combine the results

The derivative of the function \(f(t)\) is the sum of the derivatives of its terms, thus \(f'(t) = -4t + 3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
The power rule is a fundamental technique used in calculus to find the derivative of a polynomial function, where a term is raised to a power. For any term in the form of \(a \times x^n\), its derivative is calculated by bringing the exponent down in front and multiplying it with the coefficient \(a\), then subtracting one from the original exponent.

For example, using the power rule on the term \(-2t^2\), we multiply the exponent \(2\) by the coefficient \(-2\) to get \(-4\), and reduce the exponent by one, resulting in \(-4t^{2-1} = -4t\). Efficient use of the power rule allows for quick differentiation of terms where variables are raised to any real number power, making it essential for derivative calculation.
Derivative of a Constant
The derivative of a constant is an important concept in differential calculus. A constant is a number that does not change, and therefore, has no rate of change. In the context of derivatives, which measure the rate at which a function changes, the derivative of any constant value is always zero.

This principle implies that when differentiating an equation, any term that does not contain a variable, such as \(-6\) in the original function \(f(t)=-2t^2+3t-6\), can be simply disregarded. The derivative will not include these constant terms, as they do not contribute to the change or slope of the function.
Derivative Calculation
Derivative calculation involves the application of derivative rules to find the rate at which a function changes at a particular point. For a given polynomial function like \(f(t)=-2t^2+3t-6\), we systematically apply the power rule for variables raised to a power and acknowledge that the derivative of a constant is zero.

By following these steps sequentially—identifying each term's nature and applying the respective rule—we can build up the derivative of the entire function term by term. In our example, the combination of the derivatives of the individual terms \(-4t+3+0\) yields the final derivative \(f'(t) = -4t + 3\). This process of derivative calculation is the cornerstone of understanding how functions behave and change, and is widely used in various fields including physics, engineering, and economics.

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Most popular questions from this chapter

Prove (Theorem 2.3) that \(\frac{d}{d x}\left[x^{n}\right]=n x^{n-1}\) for the case in which \(n\) is a rational number. (Hint: Write \(y=x^{p / q}\) in the form \(y^{q}=x^{p}\) and differentiate implicitly. Assume that \(p\) and \(q\) are integers, where \(q>0 .\) )

Relationship between \(f\) and \(g\) is given. Explain the relationship between \(f^{\prime}\) and \(g^{\prime}\). $$ g(x)=f\left(x^{2}\right) $$

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A man 6 feet tall walks at a rate of 5 feet per second away from a light that is 15 feet above the ground (see figure). When he is 10 feet from the base of the light, (a) at what rate is the tip of his shadow moving? (b) at what rate is the length of his shadow changing?

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