/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Combine the sum of the two itera... [FREE SOLUTION] | 91Ó°ÊÓ

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Combine the sum of the two iterated integrals into a single iterated integral by converting to polar coordinates. Evaluate the resulting iterated integral. $$ \int_{0}^{2} \int_{0}^{x} \sqrt{x^{2}+y^{2}} d y d x+\int_{2}^{2 \sqrt{2}} \int_{0}^{\sqrt{8-x^{2}}} \sqrt{x^{2}+y^{2}} d y d x $$

Short Answer

Expert verified
The combined integral is \( \frac{4}{3}\pi \)

Step by step solution

01

Convert to Polar Coordinates

First convert the given integrals into polar coordinates where \(x = r \cos \theta\) and \(y = r \sin \theta\). The integrals become:\[\int_{0}^{\pi/4} \int_{0}^{2 \sec \theta} r^2 d r d \theta + \int_{\pi/4}^{\pi/2} \int_{0}^{2 \csc \theta} r^2 d r d \theta\]
02

Combine the Iterated Integrals

We see that the combined region of integration is a quarter circle in the \(xy\)-plane of radius 2. Thus, the sum of these double integrals can be rewritten as:\[\int_{0}^{\pi/2} \int_{0}^{2} r^2 d r d \theta\]
03

Evaluate the Integral

The given integral is now in easier form to compute:\[\int_{0}^{\pi/2} \int_{0}^{2} r^2 d r d \theta = \int_{0}^{\pi/2} \left[ \frac{1}{3} r^3 \right]_{0}^{2} d \theta = \int_{0}^{\pi/2} \frac{8}{3} d \theta = \left[ \frac{8}{3} \theta \right]_{0}^{\pi/2} = \frac{4}{3}\pi\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Converting Cartesian Coordinates to Polar Coordinates
When solving complex problems in calculus, we often encounter situations where converting Cartesian coordinates to polar coordinates simplifies the process. In Cartesian coordinates, each point on a plane is determined by an x (horizontal) and y (vertical) coordinate. Polar coordinates, however, define a point by its distance from a reference point, known as the pole (usually the origin in the Cartesian system), and an angle from a reference direction (typically the positive x-axis).

The conversion is straightforward; the x and y coordinates are related to polar coordinates by the formulas: \(x = r \cos \theta\) and \(y = r \sin \theta\), where \(r\) is the radius or distance to the point, and \(\theta\) is the angle in radians. To determine \(r\), we use the equation \(r = \sqrt{x^2 + y^2}\), and to find \(\theta\), the formula \(\theta = \arctan\left(\frac{y}{x}\right)\) is used, noting that adjustments may be necessary depending on the quadrant in which the point lies.
Evaluating Double Integrals
Evaluating double integrals is a fundamental skill in calculus, particularly when dealing with two-dimensional areas. A double integral allows us to compute the accumulated value, such as area, volume, or mass, over a two-dimensional region. The process usually involves two integrations performed successively.

The general form for a double integral over a region \(R\) is \(\int\int_R f(x, y) dA\), where \(dA\) can be thought of as a small element of area, and \(f(x, y)\) is the function being integrated. In the context of polar coordinates, the double integral takes the form \(\int\int_R f(r, \theta) r dr d\theta\), the extra \(r\) accounts for the 'stretching' of the area element in polar coordinates. Evaluating such integrals often simplifies when converting regions that are naturally circular or radial into polar coordinates.
Polar Coordinate System
The polar coordinate system offers an alternative to the Cartesian coordinate system for representing points in the plane. While the Cartesian system is organized in a grid-like pattern using perpendicular axes, the polar coordinate system is built on a radial structure. In this system, the location of a point is given by a distance from a central point (the pole, analogous to the origin) and an angle from a reference direction (usually the positive x-axis).

Characteristics of the Polar Coordinate System

  • Reference Point: The pole is akin to the 'zero point' from which measurements start.
  • Reference Line: Known as the polar axis, this is often aligned with the positive x-axis in Cartesian coordinates.
  • Radius: Denoted by \(r\), this non-negative quantity represents the distance of a point from the pole.
  • Angle: Denoted by \(\theta\), this angle, often measured in radians, determines the counterclockwise rotation from the polar axis necessary to reach the point's line of sight from the pole.
Integration in Calculus
Integration is a cornerstone of calculus, essential for solving problems involving areas, volumes, and other quantities that accumulate over a region. The concept of integration can be considered as the inverse process of differentiation, and it allows us to sum infinitely small data points to determine a total quantity.

Integrals can be classified into two broad categories: indefinite integrals, which represent the general form of antiderivatives, and definite integrals, which calculate the accumulated value between two bounds. When dealing with multivariable functions, we encounter multiple integrals (such as double or triple integrals) that extend the concept to higher dimensions.

The process of evaluating an integral, whether single or multiple, often involves determining antiderivatives, applying boundary conditions, and using specific techniques tailored to the integral's form. For functions over two-dimensional regions, double integrals become an invaluable tool for capturing the essence of accumulation in a plane.

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Most popular questions from this chapter

Determine which value best approximates the volume of the solid between the \(x y\) -plane and the function over the region. (Make your selection on the basis of a sketch of the solid and not by performing any calculations.) \(f(x, y)=15-2 y ; R:\) semicircle: \(x^{2}+y^{2}=16, y \geq 0\) (a) 100 (b) 200 (c) 300 (d) \(-200\) (e) 800

A firm's profit \(P\) in marketing two soft drinks is \(P=192 x+576 y-x^{2}-5 y^{2}-2 x y-5000\), where \(x\) and \(y\) represent the numbers of units of the two soft drinks. Use a computer algebra system to evaluate the double integral yielding the average weekly profit if \(x\) varies between 40 and 50 units and \(y\) varies between 45 and 60 units.

Use the indicated change of variables to evaluate the double integral. $$ \begin{aligned} &\int_{R} \int e^{-x y / 2} d A\\\ &x=\sqrt{\frac{v}{u}}, y=\sqrt{u v}\\\ &R \text { : first-quadrant region lying between the graphs of }\\\ &y=\frac{1}{4} x, \quad y=2 x, \quad y=\frac{1}{x}, \quad y=\frac{4}{x} \end{aligned} $$

Let \(R\) represent a county in the northern part of the United States, and let \(f(x, y)\) represent the total annual snowfall at the point \((x, y)\) in \(R\). Interpret each of the following. (a) \(\int_{R} \int f(x, y) d A\) (b) \(\frac{\int_{R} \int f(x, y) d A}{\int_{R} \int d A}\)

True or False? Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. The volume of the sphere \(x^{2}+y^{2}+z^{2}=1\) is given by the integral \(V=8 \int_{0}^{1} \int_{0}^{1} \sqrt{1-x^{2}-y^{2}} d x d y\)

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