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Find both first partial derivatives. $$ f(x, y)=2 x-3 y+5 $$

Short Answer

Expert verified
The first partial derivative with respect to x is 2, and the first partial derivative with respect to y is -3.

Step by step solution

01

Find the Partial Derivative with Respect to x

To find the partial derivative of the function with respect to x, treat y as a constant. The derivative of a constant is zero. So we get: \[\frac{{\partial f(x, y)}}{{\partial x}} = \frac{{\partial}}{{\partial x}}(2x - 3y + 5) = 2\]
02

Find the Partial Derivative with Respect to y

To find the partial derivative of the function with respect to y, treat x as a constant. The derivative of a constant is zero. So we get: \[\frac{{\partial f(x, y)}}{{\partial y}} = \frac{{\partial}}{{\partial y}}(2x - 3y + 5) = -3\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Partial Differentiation
Partial differentiation is a fundamental concept in calculus, especially when dealing with functions that depend on more than one variable. In simple terms, when you partially differentiate a function, you find the rate at which the function changes with respect to one variable while keeping all other variables constant. This technique is crucial when analyzing multi-variable functions.

To compute a partial derivative, follow this basic process:
  • Select the variable you are differentiating with respect to. Treat all other variables as constants during this process.
  • Apply standard differentiation rules, such as the power rule, product rule, or chain rule, to differentiate terms involving the chosen variable.
  • Simplify the expression if needed to obtain the partial derivative.
In our example function, while finding the partial derivative with respect to \(x\), \(y\) and the constant term were treated as constants, resulting in \(\frac{\partial f}{\partial x} = 2\). Conversely, to find the partial derivative with respect to \(y\), \(x\) was treated as constant, giving \(\frac{\partial f}{\partial y} = -3\).
Functions of Several Variables
Functions of several variables are expressions where the output is determined by two or more inputs. These functions are expressed in the form \(f(x, y, z, \ldots)\). Such functions are widespread in real-world applications, including physics, engineering, and economics.

In terms of geometry, functions of several variables can describe 3D surfaces within a coordinate system. For example, the function \(f(x,y) = ...\) defines a surface in a 3D space, where \(x\) and \(y\) are the input variables, and \(f(x, y)\) is the output or the height of the surface above the \(xy\)-plane.

Key aspects to consider:
  • Critical points of these functions require evaluating partial derivatives to locate local extrema, similar to finding maxima and minima in single-variable calculus.
  • Optimization problems often rely on these functions, using techniques like the method of Lagrange multipliers.
Calculus in Multi-Variable Contexts
Calculus extends far beyond single-variable equations to consider functions of multiple variables. This extension is crucial in modeling complex real-world phenomena where more than one factor influences an outcome.

In multivariable calculus, you learn various operations:
  • Partial differentiation, previously discussed, helps in analyzing how each individual variable affects a function.
  • Multiple integrals, such as double and triple integrals, are used to compute areas, volumes, and other cumulative values across dimensions.
Understanding these concepts is crucial in fields such as physics (e.g., modeling electric or gravitational fields), engineering (e.g., stress analysis in materials), and economics (e.g., utility functions involving multiple products or services).

Overall, multivariable calculus provides the tools for advanced problem-solving in varied scientific and analytical settings, allowing for in-depth exploration of how various factors interplay within a system.

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Most popular questions from this chapter

The table shows the world populations \(y\) (in billions) for five different years. (Source: U.S. Bureau of the Census, International Data Base) $$ \begin{array}{|l|c|c|c|c|c|} \hline \text { Year } & 1994 & 1996 & 1998 & 2000 & 2002 \\ \hline \text { Population, } \boldsymbol{y} & 5.6 & 5.8 & 5.9 & 6.1 & 6.2 \\ \hline \end{array} $$ Let \(x=4\) represent the year 1994 . (a) Use the regression capabilities of a graphing utility to find the least squares regression line for the data. (b) Use the regression capabilities of a graphing utility to find the least squares regression quadratic for the data. (c) Use a graphing utility to plot the data and graph the models. (d) Use both models to forecast the world population for the year \(2010 .\) How do the two models differ as you extrapolate into the future?

The utility function \(U=f(x, y)\) is a measure of the utility (or satisfaction) derived by a person from the consumption of two products \(x\) and \(y .\) Suppose the utility function is \(U=-5 x^{2}+x y-3 y^{2}\) (a) Determine the marginal utility of product \(x\). (b) Determine the marginal utility of product \(y\). (c) When \(x=2\) and \(y=3\), should a person consume one more unit of product \(x\) or one more unit of product \(y\) ? Explain your reasoning. (d) Use a computer algebra system to graph the function. Interpret the marginal utilities of products \(x\) and \(y\) graphically.

Use Lagrange multipliers to find the indicated extrema of \(f\) subject to two constraints. In each case, assume that \(x, y\), and \(z\) are nonnegative. Maximize \(f(x, y, z)=x y+y z\) Constraints: \(x+2 y=6, \quad x-3 z=0\)

Ideal Gas Law According to the Ideal Gas Law, \(P V=k T\), where \(P\) is pressure, \(V\) is volume, \(T\) is temperature (in Kelvins), and \(k\) is a constant of proportionality. A tank contains 2600 cubic inches of nitrogen at a pressure of 20 pounds per square inch and a temperature of \(300 \mathrm{~K}\). (a) Determine \(k\). (b) Write \(P\) as a function of \(V\) and \(T\) and describe the level curves.

Find the absolute extrema of the function over the region \(R .\) (In each case, \(R\) contains the boundaries.) Use a computer algebra system to confirm your results. \(f(x, y)=(2 x-y)^{2}\) \(R\) : The triangular region in the \(x y\) -plane with vertices \((2,0)\), \((0,1)\), and \((1,2)\)

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