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Use polar coordinates to find the limit. [Hint: Let \(x=r \cos \theta\) and \(y=r \sin \theta\), and note that \((x, y) \rightarrow(0,0)\) implies \(r \rightarrow 0 .]\) $$ \lim _{(x, y) \rightarrow(0,0)} \frac{x^{2}-y^{2}}{\sqrt{x^{2}+y^{2}}} $$

Short Answer

Expert verified
The limit of the function as (x, y) approaches (0,0) is 0.

Step by step solution

01

Conversion

Convert the given x and y variables into polar coordinates. For this problem, using the formulas where \(x=r \cos \theta\) and \(y=r \sin \theta\), we obtain \((x^2 - y^2) / \sqrt{x^2 + y^2}\) can be written as \(r^2 \cos^2 \theta - r^2 \sin^2 \theta\) / r.
02

Simplify

Simplify the expression by dividing the numerator and denominator by r. After simplifying, the expression is transformed into \(r(\cos^2 \theta - \sin^2 \theta)\)
03

Limit in polar coordinates

Now, use the fact that we are heading towards the origin, which in polar coordinates means \(r \rightarrow 0\). Thus, the limit becomes \( \lim _{r \rightarrow 0} r(\cos^2 \theta - \sin^2 \theta)\)
04

Calculate the limit

As the r term in the function approaches zero, the whole function tends towards 0, regardless of the value of theta. So the limit is zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinate System
The polar coordinate system is a two-dimensional coordinate system where each point on a plane is determined by a distance from a reference point, called the origin or pole, and an angle from a reference direction, typically the positive x-axis. Unlike the Cartesian coordinate system which uses horizontal and vertical distances (x and y coordinates) to locate points, the polar coordinate system uses the notation \( (r, \theta) \) where \( r \) is the radius or distance from the origin, and \( \theta \) is the angle in radians measured from the reference direction.

Learning how to navigate between these two coordinate systems is crucial for tackling advanced mathematical problems, especially those which are naturally radial or involve circular motion. In the context of limits and calculus, polar coordinates can simplify problems involving radial symmetry or when approaching the origin from all directions.
Limit of a Function
In calculus, the limit of a function is a fundamental concept that describes the behavior of a function as the input approaches a certain value. It is a way to express the value that a function 'approaches' as the independent variable gets closer and closer to a given point. For example, when we say \( \lim_{{(x, y) \rightarrow (0,0)}} f(x, y) \), we are interested in the value that \( f(x, y) \) takes as \( (x, y) \) approaches the origin (0,0).

The limit does not always exist, but when it does, it helps us to understand the behavior of functions at points where they may not be directly defined. Moreover, it is a stepping stone towards understanding more complex concepts such as continuity, derivatives, and integrals.
Converting Cartesian Coordinates to Polar Coordinates
Converting from Cartesian coordinates (x, y) to polar coordinates \( (r, \theta) \) involves using trigonometry and the Pythagorean theorem. The conversion formulas are \( x = r \cos(\theta) \) and \( y = r \sin(\theta) \). To find 'r', one can apply the Pythagorean theorem to the coordinates to get \( r = \sqrt{x^2 + y^2} \), while the angle \( \theta \) can be found using trigonometric functions such as the arctangent.

Understanding this conversion is crucial when evaluating limits of functions in polar coordinates, as it often simplifies the expressions involved. For example, a distance from the origin in Cartesian coordinates, \( \sqrt{x^2 + y^2} \) transforms neatly into 'r' when converted to polar coordinates—streamlining the process of finding the limit.
Simplification of Algebraic Expressions
Simplification of algebraic expressions is the process of reducing complexity in an expression to make it easier to understand or evaluate. This often involves factoring, expanding polynomials, canceling common terms, and applying basic arithmetic operations.

For instance, when encountering a fraction where the numerator and denominator share a common factor, we can simplify by dividing both by that factor. Simplification is vital when evaluating limits, as seen in the exercise, where dividing by 'r' across the numerator and the denominator of the fraction greatly reduces the complexity of the limit problem, thereby making the evaluation of the limit more straightforward.

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