/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Find the gradient of the functio... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the gradient of the function at the given point. $$ f(x, y)=3 x-5 y^{2}+10, \quad(2,1) $$

Short Answer

Expert verified
The gradient of the given function at the point (2,1) is \( \langle 3, -10 \rangle \)

Step by step solution

01

Find the Partial Derivative with respect to x

First, find the partial derivative of the function with respect to x, denoted as \(f_x\). Hold all other variables, in this case y, constant and differentiate normally with respect to x: \(f_x = \frac{\partial}{\partial x}(3x - 5y^2 + 10) = 3\).
02

Find the Partial Derivative with respect to y

Next, find the partial derivative with respect to y, denoted as \(f_y\). This time, hold all other variables, in this case x, constant and differentiate normally with respect to y: \(f_y = \frac{\partial}{\partial y}(3x - 5y^2 + 10) = -10y\).
03

Evaluate the Gradient at the Given Point

Now we can calculate the gradient of the function at the point (2,1) by substituting (2,1) into \(f_x\) and \(f_y\). The gradient is a vector that contains the values of the partial derivatives at the point (2,1): Grad f(2, 1) = \( \langle f_x(2,1), f_y(2,1)\rangle = \langle 3, -10 \times 1\rangle = \langle 3, -10 \rangle \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
In mathematics, especially in multivariable calculus, partial derivatives are an extension of the conventional derivative concept. When you have a function of multiple variables, such as \( f(x, y) \), a partial derivative with respect to one variable is the derivative while treating all other variables as constants. This means you focus on how the function changes as you slightly adjust one variable, ignoring the others. For example, finding the partial derivative \( f_x \) of the function \( f(x, y) = 3x - 5y^2 + 10 \) involves treating \( y \) as a constant and differentiating only with respect to \( x \). This results in \( f_x = 3 \). Similarly, the partial derivative \( f_y \) is found by treating \( x \) as constant, giving us \( f_y = -10y \). This way, you gain insight into the behavior of the function concerning each variable independently.
Multivariable Calculus
Multivariable calculus deals with functions of more than one variable. While single-variable calculus primarily focuses on limits, continuity, and derivatives of functions of a single variable, multivariable calculus involves multiple dimensions and often employs partial derivatives.
In the context of multivariable calculus, a function like \( f(x, y) \) can be thought of as a surface in a three-dimensional space. As you change \( x \) or \( y \), you might move along different paths on the surface, each change creating a unique slope.
  • In such a setting, you can find slopes in various directions by computing partial derivatives.
  • These derivatives tell us how steeply the surface inclines or declines in the directions parallel to the respective axes.
Grasping the basics of multivariable calculus is foundational for working in fields like physics, engineering, and economics, where problems often involve multiple changing factors.
Gradient Vector
The gradient vector is a fundamental concept in multivariable calculus that encompasses the partial derivatives of a function. It is essentially a vector that points in the direction of the steepest ascent of the function.
For the function \( f(x, y) \), the gradient is denoted by \( abla f \) and is composed of the partial derivatives \( (f_x, f_y) \). In our exercise, the gradient at point \( (2, 1) \) is \( \langle 3, -10 \rangle \).
  • This tells us that at (2,1), changing \( x \) by a small amount affects the function by 3 times that small change (holding \( y \) constant).
  • Similarly, changing \( y \) affects the function by -10 times the small change (holding \( x \) constant).
The gradient not only gives the direction of the greatest rate of increase of the function but also its magnitude, which indicates how steep the incline is at a given point. Understanding the gradient is crucial when analyzing multi-dimensional landscapes, optimizing functions, and solving practical problems in science and engineering.

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