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(a) evaluate \(f(1,2)\) and \(f(1.05,2.1)\) and calculate \(\Delta z\), and (b) use the total differential \(d z\) to approximate \(\Delta z\) $$ f(x, y)=x \sin y $$

Short Answer

Expert verified
After carrying out the above steps, you should have evaluated \(f(1,2)\) and \(f(1.05,2.1)\), calculated \(\Delta z\), and used the total differential \(d z\) to approximate \(\Delta z\). Keep in mind that the exact results would depend on the values of the trigonometric calculations.

Step by step solution

01

Evaluate Function

First, we substitute the x and y values into the function to evaluate \(f(1,2)\) and \(f(1.05,2.1)\). For instance, \(f(1, 2) = 1 * \sin(2)\) and \(f(1.05, 2.1) = 1.05 * \sin(2.1)\).
02

Compute Δz

We calculate the change in z, \(\Delta z\), by subtracting the result of \(f(1, 2)\) from \(f(1.05, 2.1)\), i.e., \(\Delta z = f(1.05, 2.1) - f(1,2)\).
03

Derive Total Differential

We derive the total differential dz. Using the formula \(dz = \frac{\partial f}{\partial x} dx + \frac{\partial f}{\partial y} dy\), first find \(\frac{\partial f}{\partial x} = \sin(y)\) and \(\frac{\partial f}{\partial y} = x \cos(y)\), then substitute those into the formula to get the total differential.
04

Approximate Δz

Substitute \(dx = 1.05 - 1 = 0.05\) and \(dy = 2.1 - 2 = 0.1\) into the total differential equation, and calculate dz, which would be an approximation for Δz. Calculate \(dz = \sin(2) * 0.05 + 1 * \cos(2) * 0.1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Partial derivatives help us understand how a function changes as we tweak one of its variables while keeping others constant. In the function \(f(x, y) = x \sin y\), we can explore how each variable \(x\) and \(y\) individually influences \(f\).

For the partial derivative with respect to \(x\), denoted as \(\frac{\partial f}{\partial x}\), we consider \(y\) a constant. This leads to \(\sin(y)\), highlighting that \(f\) changes with \(x\) directly proportional to \(\sin(y)\).

On the other hand, the partial derivative with respect to \(y\), \(\frac{\partial f}{\partial y}\), treats \(x\) as constant, resulting in \(x \cos(y)\). This shows how the change in \(f\) due to \(y\) depends on both \(x\) and \(\cos(y)\). Partial derivatives provide a crucial tool for evaluating the function's slope in specific directions.
Differential Approximation
Differential approximation offers a practical way to estimate small changes in a function's output. This concept utilizes the total differential, denoted as \(dz\), to make such approximations feasible.

The formula for the total differential is given by:
  • \(dz = \frac{\partial f}{\partial x} dx + \frac{\partial f}{\partial y} dy\)
The expression combines partial derivatives and small changes in each variable \(dx, dy\).

In practice, when we calculate \(dz\), it serves as an approximation for the actual change \(\Delta z\). Although not exact, this method is particularly helpful for scenarios involving minuscule variations. Hence, by substituting \(dx = 0.05\) and \(dy = 0.1\) into \(dz\), we can estimate how \(f\) reacts to slight shifts in \(x\) and \(y\).
Trigonometric Functions
Trigonometric functions like sine and cosine are pivotal in modeling periodic phenomena. In the context of the function \(f(x, y) = x \sin y\), \(\sin(y)\) embodies one of these essential functions.

Key features of sine include:
  • It ranges between -1 and 1.
  • \(\sin(y)\) completes a full cycle over \(2\pi\) radians.
  • The function oscillates smoothly, producing a wave-like graph.
Sine's behavior at specific values, such as \(y = 2\) or \(y = 2.1\), affects the overall value of \(f(x, y)\). If \(\sin(y)\) increases, so does \(f(x, y)\), demonstrating its direct influence, especially relevant in the exercise at hand.
Evaluating Functions
When evaluating a function, the goal is to determine its output for given inputs. In the example \(f(x, y) = x \sin y\), we plug specific values of \(x\) and \(y\) into the equation.

Consider the scenarios:
  • For \(f(1,2)\), substitute \(x = 1\) and \(y = 2\), yielding \(1 \times \sin(2)\).
  • For \(f(1.05, 2.1)\), use \(x = 1.05\) and \(y = 2.1\), resulting in \(1.05 \times \sin(2.1)\).
Calculation of these outputs allows us to observe \(\Delta z\) by comparing the difference \(f(1.05, 2.1) - f(1, 2)\). Function evaluation is a fundamental mathematical task, vital for analyzing how changes in variables reflect on the function's output.

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Most popular questions from this chapter

The table shows the world populations \(y\) (in billions) for five different years. (Source: U.S. Bureau of the Census, International Data Base) $$ \begin{array}{|l|c|c|c|c|c|} \hline \text { Year } & 1994 & 1996 & 1998 & 2000 & 2002 \\ \hline \text { Population, } \boldsymbol{y} & 5.6 & 5.8 & 5.9 & 6.1 & 6.2 \\ \hline \end{array} $$ Let \(x=4\) represent the year 1994 . (a) Use the regression capabilities of a graphing utility to find the least squares regression line for the data. (b) Use the regression capabilities of a graphing utility to find the least squares regression quadratic for the data. (c) Use a graphing utility to plot the data and graph the models. (d) Use both models to forecast the world population for the year \(2010 .\) How do the two models differ as you extrapolate into the future?

Find the absolute extrema of the function over the region \(R .\) (In each case, \(R\) contains the boundaries.) Use a computer algebra system to confirm your results. \(f(x, y)=x^{2}+2 x y+y^{2}, \quad R=\left\\{(x, y): x^{2}+y^{2} \leq 8\right\\}\)

The endpoints of the interval over which distinct vision is possible are called the near point and far point of the eye. With increasing age, these points normally change. The table shows the approximate near points \(y\) in inches for various ages \(x\) (in years). $$ \begin{array}{|l|c|c|c|c|c|} \hline \text { Age, } x & 16 & 32 & 44 & 50 & 60 \\ \hline \text { Near Point, } y & 3.0 & 4.7 & 9.8 & 19.7 & 39.4 \\ \hline \end{array} $$ (a) Find a rational model for the data by taking the reciprocal of the near points to generate the points \((x, 1 / y)\). Use the regression capabilities of a graphing utility to find a least squares regression line for the revised data. The resulting line has the form \(\frac{1}{y}=a x+b\) Solve for \(y\). (b) Use a graphing utility to plot the data and graph the model. (c) Do you think the model can be used to predict the near point for a person who is 70 years old? Explain.

Use Lagrange multipliers to find the minimum distance from the curve or surface to the indicated point. [Hint: In Exercise 23, minimize \(f(x, y)=x^{2}+y^{2}\) subject to the constraint \(2 x+3 y=-1 .]\) $$ \begin{array}{ll} \underline{\text { Curve }} & \underline{\text {Point}} \\ \text { Line: } 2 x+3 y=-1 \quad (0,0) \end{array} $$

In Exercises \(45-50\), find the critical points and test for relative extrema. List the critical points for which the Second Partials Test fails. \(f(x, y)=x^{3}+y^{3}\)

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