Chapter 12: Problem 49
Find the indefinite integral. $$ \int(2 t \mathbf{i}+\mathbf{j}+\mathbf{k}) d t $$
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Chapter 12: Problem 49
Find the indefinite integral. $$ \int(2 t \mathbf{i}+\mathbf{j}+\mathbf{k}) d t $$
These are the key concepts you need to understand to accurately answer the question.
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A curve \(C\) is given by the polar equation \(r=f(\theta)\). Show that the curvature \(K\) at the point \((r, \theta)\) is \(K=\frac{\left[2\left(r^{\prime}\right)^{2}-r r^{\prime \prime}+r^{2}\right]}{\left[\left(r^{\prime}\right)^{2}+r^{2}\right]^{3 / 2}}\) [Hint: Represent the curve by \(\mathbf{r}(\theta)=r \cos \theta \mathbf{i}+r \sin \theta \mathbf{j}\).]
Consider the vector-valued function \(\mathbf{r}(t)=\left(e^{t} \sin t\right) \mathbf{i}+\left(e^{t} \cos t\right) \mathbf{j}\) Show that \(\mathbf{r}(t)\) and \(\mathbf{r}^{\prime \prime}(t)\) are always perpendicular to each other.
Use a graphing utility to graph the function. In the same viewing window, graph the circle of curvature to the graph at the given value of \(x\). $$ y=\ln x, \quad x=1 $$
Find the curvature \(K\) of the curve, where \(s\) is the arc length parameter. $$ \mathbf{r}(s)=\left(1+\frac{\sqrt{2}}{2} s\right) \mathbf{i}+\left(1-\frac{\sqrt{2}}{2} s\right) \mathbf{j} $$
Find the curvature \(K\) of the plane curve at the given value of the parameter. \(\mathbf{r}(t)=t^{2} \mathbf{j}+\mathbf{k}, \quad t=0\)
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