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91Ó°ÊÓ

Find the magnitude of \(\mathrm{v}\). \(\mathbf{v}=\mathbf{i}-2 \mathbf{j}-3 \mathbf{k}\)

Short Answer

Expert verified
The magnitude of the vector \(v\) is \(\sqrt{14}\).

Step by step solution

01

Identify the coefficients

Identify the coefficients (x, y, z) from vector v. In this case, \(x = 1\), \(y = -2\), and \(z = -3\)
02

Substitute in the Magnitude Formula

Substitute x, y and z into the formula for magnitude (\(\sqrt{x^2 + y^2 + z^2}\)). This gives us \(\sqrt{1^2 + (-2)^2 + (-3)^2}\)
03

Simplify and Solve

Squaring the numbers and then adding gives us \(1 + 4 + 9 = 14\). Taking the square root of 14 will give the exact magnitude of vector v.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vectors
Vectors are a fundamental concept in mathematics and physics. They are used to represent quantities that have both a magnitude (or size) and direction. Imagine them like arrows in space, pointing from one location to another.
A vector can be written in different forms, but the one we'll focus on is the component form. For example, the vector \( \mathbf{v} \) given as \( \mathbf{i} - 2 \mathbf{j} - 3 \mathbf{k} \) represents a three-dimensional vector.
  • \( \mathbf{i} \), \( \mathbf{j} \), and \( \mathbf{k} \) are the unit vectors of the x, y, and z axes in three-dimensional space, respectively.
  • The coefficients in front of these unit vectors indicate how far and in which direction the vector extends along each axis.
  • In our example, \( \mathbf{v} \) moves 1 unit in the x-direction, -2 units in the y-direction, and -3 units in the z-direction.
By understanding vectors, we can model and solve real-world problems involving motion, forces, and more.
Magnitude Formula
The magnitude of a vector is essentially the distance of the vector from the origin to the point in three-dimensional space it defines. This is akin to finding the length of the arrow representing the vector. To compute the magnitude of a vector \( \mathbf{v} = x \mathbf{i} + y \mathbf{j} + z \mathbf{k} \), we use the magnitude formula:
\[ \text{Magnitude} = \sqrt{x^2 + y^2 + z^2} \]
Let's break down how this formula works.
  • You square each component of the vector: \( x^2 \), \( y^2 \), and \( z^2 \).
  • Then, you sum these squared values together.
  • Finally, you take the square root of that sum to find the magnitude.
In the given exercise, the components \( x = 1 \), \( y = -2 \), and \( z = -3 \) are substituted into this formula. Calculating it step-by-step helps to make sure we're applying the right math operations to reach the correct magnitude.
Three-Dimensional Space
Three-dimensional space is where most of our physical world operates, and understanding it is key to interpreting vectors. Imagine three intersecting lines (axes) crossing at a point, each representing a different dimension—width, height, and depth.
  • The x-axis usually represents left and right.
  • The y-axis represents up and down.
  • The z-axis helps describe forward and backward motion.
Any point in this space can be plotted using three coordinates, as in (x, y, z). The vector \( \mathbf{v} = \mathbf{i} - 2 \mathbf{j} - 3 \mathbf{k} \) represents movement along these axes. Each component corresponds to a specific direction and magnitude in these axes.
By calculating the magnitude, we measure its distance from the origin (0,0,0) to the point (1, -2, -3) in this space. Understanding three-dimensional vectors and their magnitudes helps in various fields, like physics (for forces), engineering (for structures), and graphics (for 3D modeling).

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