/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Find the points of intersection ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the points of intersection of the graphs of the equations.\(r=\frac{\theta}{2}\) \(r=2\)

Short Answer

Expert verified
The points of intersection are (0,0) and (4,2) in polar coordinates.

Step by step solution

01

Convert to Cartesian Coordinates

The given polar equations \(r=\frac{\theta}{2}\) and \(r=2\) need to be converted to Cartesian coordinates. The general conversion is \(x = rcos(\theta)\) and \(y = rsin(\theta)\). Applying this shown conversion to our polar equations we get \(x1 = \frac{\theta}{2}cos(\theta)\), \(y1 = \frac{\theta}{2}sin(\theta)\) and \(x2=2cos(\theta)\), \(y2=2sin(\theta)\).
02

Set Cartesian Equations Equal

Now, to find the intersections, set \(x1 = x2\) and \(y1 = y2\) to each other and solve for \(\theta\). So, \(\frac{\theta}{2}cos(\theta) = 2cos(\theta)\) and \(\frac{\theta}{2}sin(\theta) = 2sin(\theta)\)
03

Solve for Theta

The solutions that we get from the equations formulated by setting Cartesian coordinates the same are the values of theta where the intersection occur in polar coordinates. Solving admits solution \(\theta = 0\), \(\theta = 4\)
04

Convert Back to Polar Coordinate

Now, we use \(r = \theta/2\) to convert these \(\theta\) values back to polar coordinates. Substituting \(\theta = 0\), we get \(r = 0/2 = 0\). For \(\theta = 4\), we get \(r = 4/2 = 2\). So the intersection points are (0,0) and (4,2).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cartesian Coordinates Conversion
Understanding the relationship between polar and Cartesian coordinates is fundamental when working with different types of problems in geometry and trigonometry. To convert polar coordinates to Cartesian coordinates, we use the formulas:
\[ x = r \times \text{cos}(\theta) \]
\[ y = r \times \text{sin}(\theta) \]
where \( r \) is the radius (distance from the origin) and \( \theta \) is the angle in radians from the positive x-axis. For instance, in the exercise where we have the polar equations \( r = \frac{\theta}{2} \) and \( r = 2 \), converting them to Cartesian coordinates simplifies the problem and allows for finding points of intersections as if they were standard Cartesian graphs. By substituting \( r \) with the given polar equations, we obtain the Cartesian equations that represent the same curves in a different coordinate system.
Solving Polar Equations
When tasked with solving polar equations like those in the provided exercise, it is crucial to handle the variables \( r \) and \( \theta \) correctly. Polar equations can be seen as defining a radius \( r \) for every angle \( \theta \), which plots a path on the polar grid. To solve polar equations, especially for intersections, one might need to go through the process of equating two polar equations, as we do by converting them into Cartesian form and setting \( x \) and \( y \) components equal to each other. After finding the values of \( \theta \), which are the angles where the intersection occurs, we substitute back into one of the original polar equations to find the corresponding radius \( r \), giving us the full polar coordinates of intersection points.
Polar and Cartesian Systems
The polar and Cartesian coordinate systems are two different methods for representing points in a plane. While the Cartesian system uses perpendicular axes (x and y) to denote position through horizontal and vertical displacement, the polar coordinate system uses an angle and a distance from a fixed center point, called the pole, to denote position.

In the polar system, any point is represented by \( (r, \theta) \), with \( r \) being the straight-line distance from the pole and \( \theta \) being the angle from the positive x-axis (usually in radians). Because of their inherent differences, converting between polar and Cartesian systems is a common practice to simplify calculations or to apply particular mathematical techniques. It's especially useful in scenarios involving rotational symmetry, where polar coordinates offer a more straightforward approach to the problems.
Trigonometric Functions
Trigonometric functions play a crucial role in converting between polar and Cartesian coordinates and are fundamental when working with angles and circles. Sine and cosine functions describe the relationship between the angles of a right triangle and the ratio of its sides, but they also correspond to the x and y coordinates of a point on the unit circle.

For solving polar equations, understanding that \( \text{cos}(\theta) \) provides the x-coordinate and \( \text{sin}(\theta) \) the y-coordinate is essential. These functions are periodic and exhibit specific patterns and properties, such as \( \text{sin}(\theta) = \text{sin}(\theta + 2\text{k}\text{Ï€}) \) and \( \text{cos}(\theta) = \text{cos}(\theta + 2\text{k}\text{Ï€}) \), where \( k \) is an integer, which can be used to solve equations involving trigonometric functions over specific intervals.

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Most popular questions from this chapter

It Use a graphing utility to graph the polar equation \(r=6[1+\cos (\theta-\phi)]\) for (a) \(\phi=0,(\) b) \(\phi=\pi / 4\) and (c) \(\phi=\pi / 2\). Use the graphs to describe the effect of the angle \(\phi\). Write the equation as a function of \(\sin \theta\) for part (c).

Find the area of the surface generated by revolving the curve about each given axis. $$ \begin{array}{ll} \underline{\text { Parametric Equations }} & \underline{\text { Interval }} \\\ x=t, y=2 t, \quad 0 \leq t \leq 4, &\quad \text { (a) } x \text { -axis } \quad \text { (b) } y \text { -axis }\end{array} $$

Sketch a graph of the polar equation. $$ r=1+\sin \theta $$

Use a graphing utility to graph the curve represented by the parametric equations. Indicate the direction of the curve. Identify any points at which the curve is not smooth. Curtate cycloid: \(x=2 \theta-\sin \theta, \quad y=2-\cos \theta\)

Consider a projectile launched at a height \(h\) feet above the ground and at an angle \(\theta\) with the horizontal. If the initial velocity is \(v_{0}\) feet per second, the path of the projectile is modeled by the parametric equations \(x=\left(v_{0} \cos \theta\right) t\) and \(y=h+\left(v_{0} \sin \theta\right) t-16 t^{2}\). The center field fence in a ballpark is 10 feet high and 400 feet from home plate. The ball is hit 3 feet above the ground. It leaves the bat at an angle of \(\theta\) degrees with the horizontal at a speed of 100 miles per hour (see figure). (a) Write a set of parametric equations for the path of the ball. (b) Use a graphing utility to graph the path of the ball when \(\theta=15^{\circ} .\) Is the hit a home run? (c) Use a graphing utility to graph the path of the ball when \(\theta=23^{\circ} .\) Is the hit a home run? (d) Find the minimum angle at which the ball must leave the bat in order for the hit to be a home run.

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