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Given \(f(x)=\sin x\) and \(g(x)=\pi x\), evaluate each expression. (a) \(f(g(2))\) (b) \(f\left(g\left(\frac{1}{2}\right)\right)\) (c) \(g(f(0))\) (d) \(g\left(f\left(\frac{\pi}{4}\right)\right)\) (e) \(f(g(x))\) (f) \(g(f(x))\)

Short Answer

Expert verified
(a) \(f(g(2))=0\), (b) \(f(g(1/2))=1\), (c) \(g(f(0))=0\), (d) \(g(f(\pi/4))=\pi \sqrt{2}/2\), (e) \(f(g(x))=\sin(\pi x)\), (f) \(g(f(x))=\pi \sin x\)

Step by step solution

01

Evaluate \(f(g(2))\)

Substitute \(2\) into \(g(x)\) to get \(g(2)=2\pi\). Next substitute \(2\pi\) into \(f(x)\) to get \(f(2\pi)=\sin(2\pi)=0\)
02

Evaluate \(f(g(1/2))\)

Substitute \(\frac{1}{2}\) into \(g(x)\) to get \(g(1/2)=\pi/2\). Next substitute \(\pi/2\) into \(f(x)\) to get \(f(\pi/2)=\sin(\pi/2)=1\)
03

Evaluate \(g(f(0))\)

Substitute \(0\) into \(f(x)\) to get \(f(0)=\sin(0)=0\). Next substitute \(0\) into \(g(x)\) to get \(g(0)=\pi \cdot 0=0\)
04

Evaluate \(g(f(\pi/4))\)

Substitute \(\pi/4\) into \(f(x)\) to get \(f(\pi/4)=\sin(\pi/4)=\sqrt{2}/2\). Next substitute \(\sqrt{2}/2\) into \(g(x)\) to get \(g(\sqrt{2}/2)=\pi \cdot (\sqrt{2}/2)=\pi \sqrt{2}/2\)
05

Express \(f(g(x))\)

Substitute \(x\) into \(g(x)\) to get \(g(x)=\pi x\). Next, substitute \(\pi x\) into \(f(x)\) to get \(f(\pi x)=\sin(\pi x)\)
06

Express \(g(f(x))\)

Substitute \(x\) into \(f(x)\) to get \(f(x)=\sin x\). Next, substitute \(\sin x\) into \(g(x)\) to get \(g(\sin x)=\pi \sin x\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Composition
Understanding function composition is crucial for working with complex mathematical operations. Essentially, function composition involves applying one function to the result of another function. This is similar to completing two sequential actions, where the outcome of the first action becomes the input for the second action.

For the given functions, you experienced this concept firsthand. To evaluate the expression like \( f(g(x)) \), you first apply the inner function \( g(x) \) to the input value, then you take that result and plug it into the outer function \( f(x) \). An analogy might be putting on socks (\( g(x) \)) before putting on shoes (\( f(x) \)); you can't reverse the order. This step-by-step progression in functions as if following a 'recipe' is at the heart of function composition.
Trigonometric Functions
Trigonometric functions like sine and cosine are fundamental in calculus, dealing with the relationships of angles and sides in right-angled triangles. These functions are also periodic and have values repeating over intervals, making them essential in describing oscillations and waves.

The function \( f(x) = \sin x \) provided in the exercise is a primary example of a trigonometric function. When evaluating a function like \( \sin x \), you may need to recall key angle values which are common in the unit circle, such as \( \sin(0) \) and \( \sin(\pi/2) \). Remembering that \( \sin \) has a maximum value of 1 and a minimum of -1 will help you predict and understand the function's behavior.
Evaluating Functions
Evaluating functions is an essential skill, which involves calculating the output of a function given a specific input. When you're asked to evaluate something like \( f(2) \), it means to find the value of \( f(x) \) where \( x = 2 \).

In our case, you worked through various examples, substituting specific values into the formulas given for \( f(x) \) and \( g(x) \). Through this process, you become comfortable with the mechanics of function evaluation. This fundamental concept is the backbone of higher-level calculus, as it teaches you to navigate functions' behavior for specific inputs.
Function Transformation
Function transformation involves changing a function's graph, which includes shifting, stretching, compressing, or reflecting it. The exercise \( g(f(x)) = \pi \sin x \) showcased a kind of transformation known as stretching. Multiplying the sine function by \( \pi \) stretches the graph vertically, making the amplitude greater.

Vertical Stretch Example

Imagine you have \( y = \sin x \), which normally oscillates between -1 and 1. If we apply the transformation to create \( y = \pi \sin x \), the new function oscillates between -\( \pi \) and \( \pi \), simply because every value of \( \sin x \) gets multiplied by \( \pi \). Understanding how these transformations affect the graph's shape is pivotal in analyzing and predicting a function's behavior.

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