Chapter 0: Problem 49
Sketch a graph of the equation. $$y=-3$$
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Chapter 0: Problem 49
Sketch a graph of the equation. $$y=-3$$
These are the key concepts you need to understand to accurately answer the question.
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Tangent Line Find an equation of the line tangent to the circle \((x-1)^{2}+(y-1)^{2}=25\) at the point \((4,-3)\)
Find the composite functions \((f \circ g)\) and \((g \circ f)\). What is the domain of each composite function? Are the two composite functions equal? \(f(x)=x^{2}\) \(g(x)=\sqrt{x}\)
Prove that the diagonals of a rhombus intersect at right angles. (A rhombus is a quadrilateral with sides of equal lengths.)
Brinell Hardness The data in the table show the Brinell hardness \(H\) of \(0.35\) carbon steel when hardened and tempered at temperature \(t\) (degrees Fahrenheit). (Source: Standard Handbook for Mechanical Engineers) $$ \begin{array}{|l|l|l|l|l|l|l|} \hline t & 200 & 400 & 600 & 800 & 1000 & 1200 \\ \hline \boldsymbol{H} & 534 & 495 & 415 & 352 & 269 & 217 \\ \hline \end{array} $$ (a) Use the regression capabilities of a graphing utility to find a linear model for the data. (b) Use a graphing utility to plot the data and graph the model. How well does the model fit the data? Explain your reasoning. (c) Use the model to estimate the hardness when \(t\) is \(500^{\circ} \mathrm{F}\).
Volume An open box of maximum volume is to be made from a square piece of material 24 centimeters on a side by cutting equal squares from the corners and turning up the sides (see figure). (a) Write the volume \(V\) as a function of \(x\), the length of the corner squares. What is the domain of the function? (b) Use a graphing utility to graph the volume function and approximate the dimensions of the box that yield a maximum volume. (c) Use the table feature of a graphing utility to verify your answer in part (b). (The first two rows of the table are shown.) $$ \begin{array}{|c|c|c|} \hline \text { Height, } x & \begin{array}{c} \text { Length } \\ \text { and Width } \end{array} & \text { Volume, } \boldsymbol{V} \\ \hline 1 & 24-2(1) & 1[24-2(1)]^{2}=484 \\ \hline 2 & 24-2(2) & 2[24-2(2)]^{2}=800 \\ \hline \end{array} $$
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