Chapter 9: Problem 60
True or false. Give an explanation for your answer. If the power series \(\sum C_{n} x^{n}\) does not converge for \(x=\) 1, then the power series does not converge for \(x=2\)
Short Answer
Expert verified
True. If the series diverges at \(x=1\), it also diverges at \(x=2\).
Step by step solution
01
Understand Power Series Convergence
A power series \(\sum C_{n} x^{n}\) converges within a radius determined by its radius of convergence \(R\). This means the series converges for \(x \leq R\) and diverges for \(x > R\). Convergence can be identified at the endpoints through testing.
02
Apply Given Information
The exercise states that the series \\sum C_{n} x^{n} diverges at \(x=1\). This indicates that \(1\) is not within the radius of convergence \(R\).
03
Interpret the Condition for \(x=1\)
If the series diverges at \(x=1\), the radius of convergence \(R\) must be less than \(1\). Thus, \(x=1\) lies outside the convergence interval.
04
Check Similarity for \(x=2\)
If \(R < 1\), then certainly \(x=2\) is outside of the radius of convergence as \(2 > 1\). Therefore, \(x=2\) will also cause the series to diverge.
05
Conclude the Answer
Since both \(x=1\) and \(x=2\) are outside the radius of convergence, the statement is true: the series does not converge for \(x=2\) if it does not converge for \(x=1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Convergence
When dealing with power series, understanding the concept of convergence is very important. A power series is an infinite sum in the form \[ \sum C_{n} x^{n} = C_0 + C_1 x + C_2 x^2 + C_3 x^3 + \cdots \]For a given value of \(x\), this series converges if the sum approaches a finite number as you consider more and more terms. The notion of convergence tells us whether a power series sums up to a meaningful value for a particular \(x\).
- If the series converges for a specific \(x\), we say that \(x\) is within the interval of convergence.
- Convergence is crucial for determining where the series behaves nicely, offering stable, useful results.
Radius of Convergence
A central concept linked to convergence of power series is the radius of convergence. This term refers to the radius of the interval around a central value (usually 0 for a power series) where the series converges. **Determining the Radius:**The radius of convergence \( R \) is found using methods like the Ratio Test or Root Test. These tests generally involve evaluating the limit of the ratio or root involving the coefficients \( C_n \) of the series, not the terms involving \( x \). \[ R = \frac{1}{\limsup_{n \to \infty} \left| \frac{C_{n+1}}{C_n} \right|} \]
- The series converges absolutely when \(|x| < R\).
- At \(|x| = R\), you must test separately to determine convergence.
- For \(|x| > R\), the series definitely diverges.
Divergence
Divergence is the opposite of convergence in power series. If a series does not approach a finite value as more terms are added, it is said to diverge. Recognizing divergence is key to understanding where a power series becomes senseless in calculations.### When Divergence OccursFor a power series, divergence typically happens when:\( |x| > R \), where \(R\) is the radius of convergence. In this case, the terms of the series grow too large, preventing the sum from settling to a stable value.
- A point \(x\) outside the radius of convergence will always lead to divergence.
- If the series diverges at a particular \(x\), any \(x\) further from the center will also result in divergence.