Chapter 9: Problem 42
If \(\sum C_{n}(x-3)^{n}\) converges at \(x=7\) and diverges at \(x=10,\) what can you say about the convergence at \(x=11 ?\) At \(x=5 ?\) At \(x=0 ?\)
Short Answer
Expert verified
Converges at \(x=5\) and \(x=0\), diverges at \(x=11.\)
Step by step solution
01
Understanding the Convergence Criteria
For a power series \(\sum C_{n}(x-a)^{n}\), the series converges within a radius of convergence \(R\) around the center \(a\). If the series converges at a point, the distance from that point to \(a\) must be less than or equal to \(R.\)
02
Identify the Center
The given power series \(\sum C_{n}(x-3)^{n}\) is centered at \(x=3\). Hence, \(a=3.\)
03
Evaluate Convergence at Given Points
The series converges at \(x=7\), which is a distance \(|7-3| = 4\) from the center \(x=3\). Thus, the radius of convergence \(R\) is at least 4.
04
Analyze Divergence Condition
The series diverges at \(x=10\), which indicates the distance \(|10-3| = 7\) exceeds the radius of convergence \(R.\) Thus, \(R < 7.\)
05
Determine Convergence at Other Points
Given \(R\) is between 4 and 7, evaluate the distance from \(x=3\) to the points of interest:- **At \(x=11\):** Distance is \(8\), which is greater than \(R\), hence the series diverges.- **At \(x=5\):** Distance is \(2\), which is less than \(R\), hence the series converges.- **At \(x=0\):** Distance is \(3\), which is less than \(R\), hence the series converges.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Radius of Convergence
The radius of convergence is a crucial concept when dealing with power series. It's essentially the distance within which a power series converges, or sums up to a specific value. Picture it as a circle on the number line, where the center is a certain point, usually denoted as \(a\). This circle stretches out to a radius, \(R\), within which the series will converge.
For example, consider a series centered at \(x = 3\):
For example, consider a series centered at \(x = 3\):
- At \(x = 7\), the series converges. This means the distance between \(7\) and \(3\) (which is \(7 - 3 = 4\)) is within the radius \(R\).
- At \(x = 10\), the series does not converge. This implies the distance \(10 - 3 = 7\) is outside the radius \(R\).
Power Series
Power series are like siblings to polynomials in the world of mathematical series. They are sums of infinite terms of the form \( C_n(x-a)^n \). Here, \(C_n\) represents the coefficients, \(x\) is the variable, and \(a\) is the center of the series.
A power series
A power series
- may converge at some values of \(x\), where it has a finite or predictable outcome,
- or diverge at others, where it has no meaningful sum.
Divergence
Divergence is a term that describes the behavior of a series that does not converge. If series are characters in a story, a divergent series walks off the plot. This happens when the sum of a series doesn't settle to any particular number but instead, grows infinitely large or loses any predictability.
In our scenario:
In our scenario:
- At \(x = 10\), the power series diverges, hinting the radius of convergence isn't large enough to reach this point from \(x = 3\).
- Using this information, we can correctly predict behavior at other points, like \(x = 11\), where the distance from the center also exceeds the radius of convergence.