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Find the sum of the series. For what values of the variable does the series converge to this sum? $$4+y+y^{2} / 3+y^{3} / 9+\cdots$$

Short Answer

Expert verified
The sum is \( \frac{12}{3-y} \) for \( |y| < 3 \).

Step by step solution

01

Recognize the Series

The given series is: \( 4 + y + \frac{y^2}{3} + \frac{y^3}{9} + \cdots \), which suggests it might be a geometric series.
02

Identify the First Term and Common Ratio

Identify the first term \( a \) of the series. Here, \( a = 4 \). Next, identify the common ratio \( r \), which is the ratio of a term to its preceding term: \( r = \frac{y}{3} \).
03

Check for Convergence of the Series

A geometric series converges if the absolute value of the common ratio \( |r| < 1 \). Here, \( |r| = \left| \frac{y}{3} \right| < 1 \) implies that \( |y| < 3 \).
04

Calculate the Sum of the Converging Series

For a converging geometric series, the sum is given by \( S = \frac{a}{1-r} \). Substituting the known values, we get \( S = \frac{4}{1 - \frac{y}{3}} \). Simplifying, we find \( S = \frac{12}{3-y} \) for \( |y| < 3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Convergence Criteria
In the context of a geometric series, **convergence** refers to whether the series approaches a specific value as more terms are added. For a geometric series, convergence is determined by the **common ratio** \( r \). The series will converge if the absolute value of this ratio is less than one.
This is expressed mathematically as:
  • \( |r| < 1 \)
If this condition holds, the series will sum to a finite value. Otherwise, the series is considered divergent, meaning it does not settle toward a specific number as more terms are added.
In the given exercise, our series has a ratio of \( r = \frac{y}{3} \). Therefore, the series converges if \(|y| < 3\). This criterion helps determine the acceptable range of values for \( y \), over which the series will result in a reliable sum and not stretch indefinitely.
Calculating the Sum of a Series
Once we establish that a geometric series converges, we can find its sum. The formula for the sum \( S \) of an infinite converging geometric series is given by:
  • \( S = \frac{a}{1 - r} \)
Here, \( a \) is the first term of the series, and \( r \) is the common ratio.
Applying this to the original exercise:
  • The first term \( a = 4 \).
  • The common ratio \( r = \frac{y}{3} \).
Plug these values into the formula, we get:
  • \( S = \frac{4}{1 - \frac{y}{3}} \)
  • Simplifying, \( S = \frac{12}{3-y} \)
This formula gives us the precise sum of the series within its convergence range \(|y| < 3\). It's a straightforward calculation once \( a \) and \( r \) are known.
The Geometric Series Formula
A **geometric series** is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio \( r \).
The general expression for a geometric series can be written as:
  • \( a, ar, ar^2, ar^3, \ldots \)
This series has particular significance due to its simplicity and its well-defined sum formula:
  • \( S = \frac{a}{1-r} \), provided \(|r| < 1\)
Recognizing a series as geometric involves identifying a constant factor between consecutive terms. In our exercise, the sequence \( 4 + y + \frac{y^2}{3} + \frac{y^3}{9} + \cdots \) follows this pattern, with each term being a fixed ratio \( \frac{y}{3} \) of the prior term.
This formula is crucial because it provides a method to determine the sum of all series terms, as long as the series converges. By agreeing to use a consistent fixed ratio, the geometric series becomes one of the fundamental concepts in mathematical analysis of infinite sums.

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