Chapter 9: Problem 11
Find a formula for \(s_{n-1} n \geq 1\) $$1 / 3,2 / 5,3 / 7,4 / 9,5 / 11, \ldots$$
Short Answer
Expert verified
The formula is \( \frac{n}{2n+1} \).
Step by step solution
01
Observe the Pattern in Numerators
The given sequence is \( \frac{1}{3}, \frac{2}{5}, \frac{3}{7}, \frac{4}{9}, \frac{5}{11}, \ldots \). Observe that the numerators are in sequence: 1, 2, 3, 4, 5, ... This represents the natural numbers starting from 1. Hence, for the n-th term, the numerator is \( n \).
02
Observe the Pattern in Denominators
Next, look at the denominator sequence: 3, 5, 7, 9, 11, ... The sequence is an arithmetic sequence starting at 3 with a common difference of 2. We can describe these denominators with the formula of an arithmetic sequence \( 3 + (n-1)\times 2 \), which simplifies to \( 2n + 1 \).
03
Write the General Formula
Combining both steps, we find the general formula for the n-th term of the sequence. The n-th term has a numerator \( n \) and a denominator \( 2n+1 \). Thus, the n-th term \( s_n \) of the sequence can be given as \( \frac{n}{2n+1} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Arithmetic Sequences
When we're discussing sequences, an **arithmetic sequence** is a sequence of numbers in which the difference between consecutive terms is constant. This is called the "common difference." For instance, in the sequence: 3, 5, 7, 9, and 11, you can see that each term increases by 2, indicating that the common difference is 2.
The formula for finding the n-th term of an arithmetic sequence is given by: \[ a_n = a_1 + (n - 1) \times d \]where:
The formula for finding the n-th term of an arithmetic sequence is given by: \[ a_n = a_1 + (n - 1) \times d \]where:
- \( a_n \) is the n-th term,
- \( a_1 \) is the first term of the sequence,
- \( n \) is the term number, and
- \( d \) is the common difference between the terms.
Numerator and Denominator
Each number in a sequence like this is a **fraction**, which means it has a numerator and a denominator. The **numerator** is the top number in a fraction, and the **denominator** is the bottom number. In the context of the sequence given, recognizing the patterns of numerators and denominators is crucial.For our sequence \( \frac{1}{3}, \frac{2}{5}, \frac{3}{7}, \ldots \), the numerators follow a simple pattern of natural numbers (1, 2, 3, 4, 5, ...), while the denominators form an arithmetic sequence (3, 5, 7, 9, 11, ...).
The numerator for the n-th term is simply \( n \). The denominator, as examined, follows the formula for an arithmetic sequence: \( 3 + (n - 1) \times 2 \), leading to \( 2n + 1 \) as simplified.These observations help in writing the general term of the sequence as \( \frac{n}{2n + 1} \). Recognizing how numerators and denominators are formed makes finding sequence patterns and forming equations less complex.
The numerator for the n-th term is simply \( n \). The denominator, as examined, follows the formula for an arithmetic sequence: \( 3 + (n - 1) \times 2 \), leading to \( 2n + 1 \) as simplified.These observations help in writing the general term of the sequence as \( \frac{n}{2n + 1} \). Recognizing how numerators and denominators are formed makes finding sequence patterns and forming equations less complex.
Sequence Pattern Recognition
The ability to recognize **patterns in sequences** is a fundamental skill in mathematics. It allows us to derive equations that define the entire sequence based on specific term behaviors.
In our example sequence \( \frac{1}{3}, \frac{2}{5}, \frac{3}{7}, \ldots \), a clear pattern emerges when examining both the numerators and denominators separately. Recognizing such patterns:
By understanding sequence pattern recognition, one can rewrite the sequence as a formula: \( s_n = \frac{n}{2n + 1} \). Practices like this are instrumental in higher-level math, from understanding simple sequences to tackling complex series.
In our example sequence \( \frac{1}{3}, \frac{2}{5}, \frac{3}{7}, \ldots \), a clear pattern emerges when examining both the numerators and denominators separately. Recognizing such patterns:
- Helps simplify the process of writing the general formula for sequences.
- Ensures that we can predict future terms accurately without calculating all values sequentially.
By understanding sequence pattern recognition, one can rewrite the sequence as a formula: \( s_n = \frac{n}{2n + 1} \). Practices like this are instrumental in higher-level math, from understanding simple sequences to tackling complex series.