Chapter 8: Problem 53
Consider the region bounded by \(y=e^{x}\) the \(x\) -axis, and the lines \(x=0\) and \(x=1 .\) Find the volume of the solid. The solid whose base is the given region and whose cross-sections perpendicular to the \(x\) -axis are squares.
Short Answer
Expert verified
The volume is \( \frac{1}{2} e^2 - \frac{1}{2} \).
Step by step solution
01
Understand the Problem
We need to find the volume of a solid with a base bounded by the curves and lines: \( y = e^x \), the \( x \)-axis, \( x = 0 \), and \( x = 1 \). The cross-sections of the solid, perpendicular to the \( x \)-axis, are squares.
02
Find the Length of the Cross-Sectional Squares
At any point \( x \) between 0 and 1, the cross-sectional area is a square with side length equal to \( y = e^x \). Thus, the side of the square is \( e^x \).
03
Express the Area of a Cross-Section
Since each cross-section is a square with side length \( e^x \), the area of the square \( A(x) \) is \( A(x) = (e^x)^2 = e^{2x} \).
04
Set Up the Integral for Volume
The volume of the solid is the integral of the area of the cross-section from \( x = 0 \) to \( x = 1 \), given by \[ V = \int_{0}^{1} e^{2x} \, dx \].
05
Compute the Integral
To compute \( \int e^{2x} \, dx \), use the substitution \( u = 2x \) which gives \( du = 2 \ dx \) or \( dx = \frac{du}{2} \). Then rewrite the integral: \[ \int e^{2x} \, dx = \int e^u \frac{du}{2} = \frac{1}{2} \int e^u \, du = \frac{1}{2} e^u + C \].
06
Evaluate the Integral
Using bounds \( x = 0 \) to \( x = 1 \), substitute back \( u = 2x \): \[ V = \frac{1}{2} \left[ e^{2x} \right]_{0}^{1} = \frac{1}{2} (e^2 - e^0) = \frac{1}{2} (e^2 - 1) \].
07
Calculate Final Volume
Solve \( \frac{1}{2} (e^2 - 1) = \frac{1}{2} e^2 - \frac{1}{2} \). This gives the volume of the solid as \( \frac{1}{2} e^2 - \frac{1}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross-sectional area
The cross-sectional area of a solid is a critical concept when you're dealing with volumes of solids. When you have a solid, its cross-sectional area gives you information about how thick or wide the solid is at any given point. Cross-sections are slices of the solid taken perpendicular to a specified axis, and can take on various shapes, such as circles, rectangles, or squares. In our exercise, the cross-sections are squares.
- Each cross-section is perpendicular to the x-axis.
- The side of each square is determined by the function value at that point.
Exponential functions
An exponential function is a mathematical function of the form \(f(x) = a \cdot b^x\), where \(a\) and \(b\) are constants, and \(x\) is a variable. In our exercise, we are dealing with the natural exponential function, \(y = e^x\), where \(e\) is a mathematical constant approximately equal to 2.71828.
- The base \(e\) is a constant that appears in many areas of mathematics, especially in calculus.
- The exponential function is continuous and differentiable everywhere.
Definite integrals
A definite integral in calculus is used to compute the total accumulation of a quantity, such as area under a curve, over a specific interval. It is represented as \(\int_{a}^{b} f(x) \,dx\), where \(a\) and \(b\) are the limits of integration, and \(f(x)\) is the function to be integrated. In the context of finding volumes, the definite integral is a powerful tool.
- Integral measures how the cross-sectional area accumulates over a range.
- Convert a plane problem into a volumetric one by summing up the infinitesimal pieces.